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Virgil Smith
December 29th 03, 04:35 AM
I have a bunch of oddball crystals that I want to test. I know I can just
build up a generic oscillator to find the
resonant frequency, but out of curiousity I would like to
know the quality of the things, too.

Anyone know of any neat ideas for measuring the Q of a
crystal?

I would welcome any and all suggestions,

-vs-

Tom Bruhns
December 29th 03, 08:08 AM
If you have access to old QSTs, you should be able to find articles
about measuring crystal parameters. Look especially for things by Wes
Hayward, W7ZOI. There's a fairly simple crystal-tester you can build
to measure enough parameters to extract equivalent L, Cs, Cp and R, I
believe. I 'spose someone will pop in with a more specific reference
for you.

Cheers,
Tom

"Virgil Smith" > wrote in message news:<3iNHb.504277$275.1417484@attbi_s53>...
> I have a bunch of oddball crystals that I want to test. I know I can just
> build up a generic oscillator to find the
> resonant frequency, but out of curiousity I would like to
> know the quality of the things, too.
>
> Anyone know of any neat ideas for measuring the Q of a
> crystal?
>
> I would welcome any and all suggestions,
>
> -vs-

Tom Bruhns
December 29th 03, 08:08 AM
If you have access to old QSTs, you should be able to find articles
about measuring crystal parameters. Look especially for things by Wes
Hayward, W7ZOI. There's a fairly simple crystal-tester you can build
to measure enough parameters to extract equivalent L, Cs, Cp and R, I
believe. I 'spose someone will pop in with a more specific reference
for you.

Cheers,
Tom

"Virgil Smith" > wrote in message news:<3iNHb.504277$275.1417484@attbi_s53>...
> I have a bunch of oddball crystals that I want to test. I know I can just
> build up a generic oscillator to find the
> resonant frequency, but out of curiousity I would like to
> know the quality of the things, too.
>
> Anyone know of any neat ideas for measuring the Q of a
> crystal?
>
> I would welcome any and all suggestions,
>
> -vs-

Joe McElvenney
December 29th 03, 08:49 AM
Hi,

To calculate Q at series resonance, you will need to
ascertain both the effective series resistance and one of
the series reactances (XL or XC). In his Jan/Feb 2002
article "Quartz Crystal Parameter Measurement", Jack
Hardcastle, G3JIR uses a simple test rig and a
mathematical/graphical method to determine both the
resistance and effective series capacitance.

There is an obvious error in the circuit to look out for
though, where an extra series crystal (Y2) was
inadvertently added by the draughtsman.


Cheers - Joe

Joe McElvenney
December 29th 03, 08:49 AM
Hi,

To calculate Q at series resonance, you will need to
ascertain both the effective series resistance and one of
the series reactances (XL or XC). In his Jan/Feb 2002
article "Quartz Crystal Parameter Measurement", Jack
Hardcastle, G3JIR uses a simple test rig and a
mathematical/graphical method to determine both the
resistance and effective series capacitance.

There is an obvious error in the circuit to look out for
though, where an extra series crystal (Y2) was
inadvertently added by the draughtsman.


Cheers - Joe

Joe McElvenney
December 29th 03, 08:53 AM
Oops!

I should have said that the article was in 'QEX'.


Cheers - Joe

Joe McElvenney
December 29th 03, 08:53 AM
Oops!

I should have said that the article was in 'QEX'.


Cheers - Joe

Virgil Smith
December 29th 03, 07:53 PM
"Joe McElvenney" > wrote in message
...
> Oops!
>
> I should have said that the article was in 'QEX'.
>
>
> Cheers - Joe
>
>

Hi, Joe:

Sounds like just what I need. Thanks a lot!

(Now to dig up the back issue of QEX.)

73,

-vs-

Virgil Smith
December 29th 03, 07:53 PM
"Joe McElvenney" > wrote in message
...
> Oops!
>
> I should have said that the article was in 'QEX'.
>
>
> Cheers - Joe
>
>

Hi, Joe:

Sounds like just what I need. Thanks a lot!

(Now to dig up the back issue of QEX.)

73,

-vs-

Nick Kennedy
December 30th 03, 07:23 PM
"Virgil Smith" > wrote in message news:<3iNHb.504277
>
> Anyone know of any neat ideas for measuring the Q of a
> crystal?
>
> I would welcome any and all suggestions,
>
> -vs-

Let's see if I can describe a method based on W7ZOI's efforts, with
some updates by K8IQY. By the way, the W7ZOI techniques from QST were
added as appendixes into one of Doug Demaw's ARRL books. Demaw
integrated Hayward's various test jigs into one crystal tester. You
can get a board from Far Circuits.

You put the crystal in a specific (typically 50 ohm) environment by
putting 50 ohm attenuators between generator and crystal and between
crystal and detector. The detector might be a diode detector plus
voltmeter or an oscilloscope. You'll also have another 50 ohm 3 dB
pad in series that can be switched in and out.

1. With the pad switched IN, adjust frequency until the peak output
is read (resonance). Note the center frequency and meter indication.

2. Switch the pad OUT and find the frequencies above and below the
center frequency that give the same indication. These are the + and –
3 dB frequencies and the difference between them is the bandwidth.

Now you can calculate Q by dividing the center frequency by the
bandwidth. Pretty low isn't it? This is a loaded Q, not the
crystal's Q. The total resistance in the circuit is 50 ohms source
plus 50 ohms load plus the crystal's yet unknown Rs.

3. Tune back to the center frequency where the output is at its peak.
Unplug the crystal and substitute a pot of maybe 0 to 25 ohms range.
(I actually just substitute fixed resistors since I don't have a
decent pot like this.) When you find a value that gives the same
meter indication as the crystal did, that is the value of Rs. (This
is because we are at series resonance, so Xc and XL have cancelled.)

Alright. Another formula for loaded Q is XL / R. R in this case is
100 ohms plus the Rs you just measured. And XL is 2*PI*Fc*L, where Fc
is the center frequency you measured earlier. You already have the
loaded Q from step 2, so you are down to one unknown. Just solve for
XL and/or L, which is the equivalent inductance of the crystal. In
like manner, you can find the series C, since Xc = XL.

And finally, the Q you wanted (the crystal's Q) is XL / Rs.

Now you know about everything about the crystal and can get one of
your Hayward or Demaw books and start designing some filters. Hayward
has nice software for this in both Introduction to RF Design and
Experimental Methods in RF Design, both from ARRL. If you want to
include holder (parallel) C in your modeling, 5 pF is a good estimate.

Jim Kortge, K8IQY puts his crystal in a 12.5 ohm environment by using
4:1 (impedance) bifilar transformers into and out of the crystals (50
ohm attenuators are still used though, to assure known generator and
load resistances). This has the advantage of making the resistance
measurement easier, but it makes the loaded bandwidth smaller, so you
need a good stable generator that you can read to the Hz. Those
little DDS units are nice. Be sure to use filtering if necessary for
signal purity. Jim designed a nice little VXO (variable crystal
oscillator) that uses one of the crystals from the set you are
measuring in the oscillator circuit. See it on NJQRP's page:

http://www.njqrp.org/pvxo/index.html

I followed Jim's lead but used resistive 50 to 12.5 ohm matching pads
instead of transformers. That way I got rid of any reactive effects
(which are minimal) of the transformers, but required a lot more
driving power due to the loss in the matching pads.

OK, that was probably more than you wanted to know. Hope I remembered
this stuff right.

73—Nick, WA5BDU
in Arkansas

Nick Kennedy
December 30th 03, 07:23 PM
"Virgil Smith" > wrote in message news:<3iNHb.504277
>
> Anyone know of any neat ideas for measuring the Q of a
> crystal?
>
> I would welcome any and all suggestions,
>
> -vs-

Let's see if I can describe a method based on W7ZOI's efforts, with
some updates by K8IQY. By the way, the W7ZOI techniques from QST were
added as appendixes into one of Doug Demaw's ARRL books. Demaw
integrated Hayward's various test jigs into one crystal tester. You
can get a board from Far Circuits.

You put the crystal in a specific (typically 50 ohm) environment by
putting 50 ohm attenuators between generator and crystal and between
crystal and detector. The detector might be a diode detector plus
voltmeter or an oscilloscope. You'll also have another 50 ohm 3 dB
pad in series that can be switched in and out.

1. With the pad switched IN, adjust frequency until the peak output
is read (resonance). Note the center frequency and meter indication.

2. Switch the pad OUT and find the frequencies above and below the
center frequency that give the same indication. These are the + and –
3 dB frequencies and the difference between them is the bandwidth.

Now you can calculate Q by dividing the center frequency by the
bandwidth. Pretty low isn't it? This is a loaded Q, not the
crystal's Q. The total resistance in the circuit is 50 ohms source
plus 50 ohms load plus the crystal's yet unknown Rs.

3. Tune back to the center frequency where the output is at its peak.
Unplug the crystal and substitute a pot of maybe 0 to 25 ohms range.
(I actually just substitute fixed resistors since I don't have a
decent pot like this.) When you find a value that gives the same
meter indication as the crystal did, that is the value of Rs. (This
is because we are at series resonance, so Xc and XL have cancelled.)

Alright. Another formula for loaded Q is XL / R. R in this case is
100 ohms plus the Rs you just measured. And XL is 2*PI*Fc*L, where Fc
is the center frequency you measured earlier. You already have the
loaded Q from step 2, so you are down to one unknown. Just solve for
XL and/or L, which is the equivalent inductance of the crystal. In
like manner, you can find the series C, since Xc = XL.

And finally, the Q you wanted (the crystal's Q) is XL / Rs.

Now you know about everything about the crystal and can get one of
your Hayward or Demaw books and start designing some filters. Hayward
has nice software for this in both Introduction to RF Design and
Experimental Methods in RF Design, both from ARRL. If you want to
include holder (parallel) C in your modeling, 5 pF is a good estimate.

Jim Kortge, K8IQY puts his crystal in a 12.5 ohm environment by using
4:1 (impedance) bifilar transformers into and out of the crystals (50
ohm attenuators are still used though, to assure known generator and
load resistances). This has the advantage of making the resistance
measurement easier, but it makes the loaded bandwidth smaller, so you
need a good stable generator that you can read to the Hz. Those
little DDS units are nice. Be sure to use filtering if necessary for
signal purity. Jim designed a nice little VXO (variable crystal
oscillator) that uses one of the crystals from the set you are
measuring in the oscillator circuit. See it on NJQRP's page:

http://www.njqrp.org/pvxo/index.html

I followed Jim's lead but used resistive 50 to 12.5 ohm matching pads
instead of transformers. That way I got rid of any reactive effects
(which are minimal) of the transformers, but required a lot more
driving power due to the loss in the matching pads.

OK, that was probably more than you wanted to know. Hope I remembered
this stuff right.

73—Nick, WA5BDU
in Arkansas

W3JDR
December 30th 03, 11:20 PM
See the "Examples" section of my web site to see how a DDS signal generator
and a little software makes these measurements easy:
http://mysite.verizon.net/jdrocci/

Joe
W3JDR

"Nick Kennedy" > wrote in message
om...
> "Virgil Smith" > wrote in message news:<3iNHb.504277
> >
> > Anyone know of any neat ideas for measuring the Q of a
> > crystal?
> >
> > I would welcome any and all suggestions,
> >
> > -vs-
>
> Let's see if I can describe a method based on W7ZOI's efforts, with
> some updates by K8IQY. By the way, the W7ZOI techniques from QST were
> added as appendixes into one of Doug Demaw's ARRL books. Demaw
> integrated Hayward's various test jigs into one crystal tester. You
> can get a board from Far Circuits.
>
> You put the crystal in a specific (typically 50 ohm) environment by
> putting 50 ohm attenuators between generator and crystal and between
> crystal and detector. The detector might be a diode detector plus
> voltmeter or an oscilloscope. You'll also have another 50 ohm 3 dB
> pad in series that can be switched in and out.
>
> 1. With the pad switched IN, adjust frequency until the peak output
> is read (resonance). Note the center frequency and meter indication.
>
> 2. Switch the pad OUT and find the frequencies above and below the
> center frequency that give the same indication. These are the + and -
> 3 dB frequencies and the difference between them is the bandwidth.
>
> Now you can calculate Q by dividing the center frequency by the
> bandwidth. Pretty low isn't it? This is a loaded Q, not the
> crystal's Q. The total resistance in the circuit is 50 ohms source
> plus 50 ohms load plus the crystal's yet unknown Rs.
>
> 3. Tune back to the center frequency where the output is at its peak.
> Unplug the crystal and substitute a pot of maybe 0 to 25 ohms range.
> (I actually just substitute fixed resistors since I don't have a
> decent pot like this.) When you find a value that gives the same
> meter indication as the crystal did, that is the value of Rs. (This
> is because we are at series resonance, so Xc and XL have cancelled.)
>
> Alright. Another formula for loaded Q is XL / R. R in this case is
> 100 ohms plus the Rs you just measured. And XL is 2*PI*Fc*L, where Fc
> is the center frequency you measured earlier. You already have the
> loaded Q from step 2, so you are down to one unknown. Just solve for
> XL and/or L, which is the equivalent inductance of the crystal. In
> like manner, you can find the series C, since Xc = XL.
>
> And finally, the Q you wanted (the crystal's Q) is XL / Rs.
>
> Now you know about everything about the crystal and can get one of
> your Hayward or Demaw books and start designing some filters. Hayward
> has nice software for this in both Introduction to RF Design and
> Experimental Methods in RF Design, both from ARRL. If you want to
> include holder (parallel) C in your modeling, 5 pF is a good estimate.
>
> Jim Kortge, K8IQY puts his crystal in a 12.5 ohm environment by using
> 4:1 (impedance) bifilar transformers into and out of the crystals (50
> ohm attenuators are still used though, to assure known generator and
> load resistances). This has the advantage of making the resistance
> measurement easier, but it makes the loaded bandwidth smaller, so you
> need a good stable generator that you can read to the Hz. Those
> little DDS units are nice. Be sure to use filtering if necessary for
> signal purity. Jim designed a nice little VXO (variable crystal
> oscillator) that uses one of the crystals from the set you are
> measuring in the oscillator circuit. See it on NJQRP's page:
>
> http://www.njqrp.org/pvxo/index.html
>
> I followed Jim's lead but used resistive 50 to 12.5 ohm matching pads
> instead of transformers. That way I got rid of any reactive effects
> (which are minimal) of the transformers, but required a lot more
> driving power due to the loss in the matching pads.
>
> OK, that was probably more than you wanted to know. Hope I remembered
> this stuff right.
>
> 73-Nick, WA5BDU
> in Arkansas

W3JDR
December 30th 03, 11:20 PM
See the "Examples" section of my web site to see how a DDS signal generator
and a little software makes these measurements easy:
http://mysite.verizon.net/jdrocci/

Joe
W3JDR

"Nick Kennedy" > wrote in message
om...
> "Virgil Smith" > wrote in message news:<3iNHb.504277
> >
> > Anyone know of any neat ideas for measuring the Q of a
> > crystal?
> >
> > I would welcome any and all suggestions,
> >
> > -vs-
>
> Let's see if I can describe a method based on W7ZOI's efforts, with
> some updates by K8IQY. By the way, the W7ZOI techniques from QST were
> added as appendixes into one of Doug Demaw's ARRL books. Demaw
> integrated Hayward's various test jigs into one crystal tester. You
> can get a board from Far Circuits.
>
> You put the crystal in a specific (typically 50 ohm) environment by
> putting 50 ohm attenuators between generator and crystal and between
> crystal and detector. The detector might be a diode detector plus
> voltmeter or an oscilloscope. You'll also have another 50 ohm 3 dB
> pad in series that can be switched in and out.
>
> 1. With the pad switched IN, adjust frequency until the peak output
> is read (resonance). Note the center frequency and meter indication.
>
> 2. Switch the pad OUT and find the frequencies above and below the
> center frequency that give the same indication. These are the + and -
> 3 dB frequencies and the difference between them is the bandwidth.
>
> Now you can calculate Q by dividing the center frequency by the
> bandwidth. Pretty low isn't it? This is a loaded Q, not the
> crystal's Q. The total resistance in the circuit is 50 ohms source
> plus 50 ohms load plus the crystal's yet unknown Rs.
>
> 3. Tune back to the center frequency where the output is at its peak.
> Unplug the crystal and substitute a pot of maybe 0 to 25 ohms range.
> (I actually just substitute fixed resistors since I don't have a
> decent pot like this.) When you find a value that gives the same
> meter indication as the crystal did, that is the value of Rs. (This
> is because we are at series resonance, so Xc and XL have cancelled.)
>
> Alright. Another formula for loaded Q is XL / R. R in this case is
> 100 ohms plus the Rs you just measured. And XL is 2*PI*Fc*L, where Fc
> is the center frequency you measured earlier. You already have the
> loaded Q from step 2, so you are down to one unknown. Just solve for
> XL and/or L, which is the equivalent inductance of the crystal. In
> like manner, you can find the series C, since Xc = XL.
>
> And finally, the Q you wanted (the crystal's Q) is XL / Rs.
>
> Now you know about everything about the crystal and can get one of
> your Hayward or Demaw books and start designing some filters. Hayward
> has nice software for this in both Introduction to RF Design and
> Experimental Methods in RF Design, both from ARRL. If you want to
> include holder (parallel) C in your modeling, 5 pF is a good estimate.
>
> Jim Kortge, K8IQY puts his crystal in a 12.5 ohm environment by using
> 4:1 (impedance) bifilar transformers into and out of the crystals (50
> ohm attenuators are still used though, to assure known generator and
> load resistances). This has the advantage of making the resistance
> measurement easier, but it makes the loaded bandwidth smaller, so you
> need a good stable generator that you can read to the Hz. Those
> little DDS units are nice. Be sure to use filtering if necessary for
> signal purity. Jim designed a nice little VXO (variable crystal
> oscillator) that uses one of the crystals from the set you are
> measuring in the oscillator circuit. See it on NJQRP's page:
>
> http://www.njqrp.org/pvxo/index.html
>
> I followed Jim's lead but used resistive 50 to 12.5 ohm matching pads
> instead of transformers. That way I got rid of any reactive effects
> (which are minimal) of the transformers, but required a lot more
> driving power due to the loss in the matching pads.
>
> OK, that was probably more than you wanted to know. Hope I remembered
> this stuff right.
>
> 73-Nick, WA5BDU
> in Arkansas

Virgil Smith
December 31st 03, 08:48 PM
"Nick Kennedy" > wrote in message
om...
> "Virgil Smith" > wrote in message news:<3iNHb.504277
> >
> > Anyone know of any neat ideas for measuring the Q of a
> > crystal?
> >
> > I would welcome any and all suggestions,
> >
> > -vs-
>
> Let's see if I can describe a method based on W7ZOI's efforts, with
> some updates by K8IQY. By the way, the W7ZOI techniques from QST were
> added as appendixes into one of Doug Demaw's ARRL books. Demaw
> integrated Hayward's various test jigs into one crystal tester. You
> can get a board from Far Circuits.
>
> You put the crystal in a specific (typically 50 ohm) environment by
> putting 50 ohm attenuators between generator and crystal and between
> crystal and detector. The detector might be a diode detector plus
> voltmeter or an oscilloscope. You'll also have another 50 ohm 3 dB
> pad in series that can be switched in and out.
>
> 1. With the pad switched IN, adjust frequency until the peak output
> is read (resonance). Note the center frequency and meter indication.
>
> 2. Switch the pad OUT and find the frequencies above and below the
> center frequency that give the same indication. These are the + and -
> 3 dB frequencies and the difference between them is the bandwidth.
>
> Now you can calculate Q by dividing the center frequency by the
> bandwidth. Pretty low isn't it? This is a loaded Q, not the
> crystal's Q. The total resistance in the circuit is 50 ohms source
> plus 50 ohms load plus the crystal's yet unknown Rs.
>
> 3. Tune back to the center frequency where the output is at its peak.
> Unplug the crystal and substitute a pot of maybe 0 to 25 ohms range.
> (I actually just substitute fixed resistors since I don't have a
> decent pot like this.) When you find a value that gives the same
> meter indication as the crystal did, that is the value of Rs. (This
> is because we are at series resonance, so Xc and XL have cancelled.)
>
> Alright. Another formula for loaded Q is XL / R. R in this case is
> 100 ohms plus the Rs you just measured. And XL is 2*PI*Fc*L, where Fc
> is the center frequency you measured earlier. You already have the
> loaded Q from step 2, so you are down to one unknown. Just solve for
> XL and/or L, which is the equivalent inductance of the crystal. In
> like manner, you can find the series C, since Xc = XL.
>
> And finally, the Q you wanted (the crystal's Q) is XL / Rs.
>
> Now you know about everything about the crystal and can get one of
> your Hayward or Demaw books and start designing some filters. Hayward
> has nice software for this in both Introduction to RF Design and
> Experimental Methods in RF Design, both from ARRL. If you want to
> include holder (parallel) C in your modeling, 5 pF is a good estimate.
>
> Jim Kortge, K8IQY puts his crystal in a 12.5 ohm environment by using
> 4:1 (impedance) bifilar transformers into and out of the crystals (50
> ohm attenuators are still used though, to assure known generator and
> load resistances). This has the advantage of making the resistance
> measurement easier, but it makes the loaded bandwidth smaller, so you
> need a good stable generator that you can read to the Hz. Those
> little DDS units are nice. Be sure to use filtering if necessary for
> signal purity. Jim designed a nice little VXO (variable crystal
> oscillator) that uses one of the crystals from the set you are
> measuring in the oscillator circuit. See it on NJQRP's page:
>
> http://www.njqrp.org/pvxo/index.html
>
> I followed Jim's lead but used resistive 50 to 12.5 ohm matching pads
> instead of transformers. That way I got rid of any reactive effects
> (which are minimal) of the transformers, but required a lot more
> driving power due to the loss in the matching pads.
>
> OK, that was probably more than you wanted to know. Hope I remembered
> this stuff right.
>
> 73-Nick, WA5BDU
> in Arkansas

Hi, Nick,

No, not more than I wanted to know at all. I'm quite happy to have this
level
of info.

Thanks for the detailed reply -- gives me something to mull over during the
holidays.

-vs-

Virgil Smith
December 31st 03, 08:48 PM
"Nick Kennedy" > wrote in message
om...
> "Virgil Smith" > wrote in message news:<3iNHb.504277
> >
> > Anyone know of any neat ideas for measuring the Q of a
> > crystal?
> >
> > I would welcome any and all suggestions,
> >
> > -vs-
>
> Let's see if I can describe a method based on W7ZOI's efforts, with
> some updates by K8IQY. By the way, the W7ZOI techniques from QST were
> added as appendixes into one of Doug Demaw's ARRL books. Demaw
> integrated Hayward's various test jigs into one crystal tester. You
> can get a board from Far Circuits.
>
> You put the crystal in a specific (typically 50 ohm) environment by
> putting 50 ohm attenuators between generator and crystal and between
> crystal and detector. The detector might be a diode detector plus
> voltmeter or an oscilloscope. You'll also have another 50 ohm 3 dB
> pad in series that can be switched in and out.
>
> 1. With the pad switched IN, adjust frequency until the peak output
> is read (resonance). Note the center frequency and meter indication.
>
> 2. Switch the pad OUT and find the frequencies above and below the
> center frequency that give the same indication. These are the + and -
> 3 dB frequencies and the difference between them is the bandwidth.
>
> Now you can calculate Q by dividing the center frequency by the
> bandwidth. Pretty low isn't it? This is a loaded Q, not the
> crystal's Q. The total resistance in the circuit is 50 ohms source
> plus 50 ohms load plus the crystal's yet unknown Rs.
>
> 3. Tune back to the center frequency where the output is at its peak.
> Unplug the crystal and substitute a pot of maybe 0 to 25 ohms range.
> (I actually just substitute fixed resistors since I don't have a
> decent pot like this.) When you find a value that gives the same
> meter indication as the crystal did, that is the value of Rs. (This
> is because we are at series resonance, so Xc and XL have cancelled.)
>
> Alright. Another formula for loaded Q is XL / R. R in this case is
> 100 ohms plus the Rs you just measured. And XL is 2*PI*Fc*L, where Fc
> is the center frequency you measured earlier. You already have the
> loaded Q from step 2, so you are down to one unknown. Just solve for
> XL and/or L, which is the equivalent inductance of the crystal. In
> like manner, you can find the series C, since Xc = XL.
>
> And finally, the Q you wanted (the crystal's Q) is XL / Rs.
>
> Now you know about everything about the crystal and can get one of
> your Hayward or Demaw books and start designing some filters. Hayward
> has nice software for this in both Introduction to RF Design and
> Experimental Methods in RF Design, both from ARRL. If you want to
> include holder (parallel) C in your modeling, 5 pF is a good estimate.
>
> Jim Kortge, K8IQY puts his crystal in a 12.5 ohm environment by using
> 4:1 (impedance) bifilar transformers into and out of the crystals (50
> ohm attenuators are still used though, to assure known generator and
> load resistances). This has the advantage of making the resistance
> measurement easier, but it makes the loaded bandwidth smaller, so you
> need a good stable generator that you can read to the Hz. Those
> little DDS units are nice. Be sure to use filtering if necessary for
> signal purity. Jim designed a nice little VXO (variable crystal
> oscillator) that uses one of the crystals from the set you are
> measuring in the oscillator circuit. See it on NJQRP's page:
>
> http://www.njqrp.org/pvxo/index.html
>
> I followed Jim's lead but used resistive 50 to 12.5 ohm matching pads
> instead of transformers. That way I got rid of any reactive effects
> (which are minimal) of the transformers, but required a lot more
> driving power due to the loss in the matching pads.
>
> OK, that was probably more than you wanted to know. Hope I remembered
> this stuff right.
>
> 73-Nick, WA5BDU
> in Arkansas

Hi, Nick,

No, not more than I wanted to know at all. I'm quite happy to have this
level
of info.

Thanks for the detailed reply -- gives me something to mull over during the
holidays.

-vs-

Roy Lewallen
January 2nd 04, 11:08 PM
The W7ZOI crystal filter design and crystal measurement methods are described
in detail in _Experimental Methods in RF Design_, published by the ARRL and
available from numerous sources. It should be every serious experimenter's
library.

Roy Lewallen, W7EL

Tom Bruhns wrote:
> If you have access to old QSTs, you should be able to find articles
> about measuring crystal parameters. Look especially for things by Wes
> Hayward, W7ZOI. There's a fairly simple crystal-tester you can build
> to measure enough parameters to extract equivalent L, Cs, Cp and R, I
> believe. I 'spose someone will pop in with a more specific reference
> for you.
>
> Cheers,
> Tom
>
> "Virgil Smith" > wrote in message news:<3iNHb.504277$275.1417484@attbi_s53>...
>
>>I have a bunch of oddball crystals that I want to test. I know I can just
>>build up a generic oscillator to find the
>>resonant frequency, but out of curiousity I would like to
>>know the quality of the things, too.
>>
>>Anyone know of any neat ideas for measuring the Q of a
>>crystal?
>>
>>I would welcome any and all suggestions,
>>
>>-vs-

Roy Lewallen
January 2nd 04, 11:08 PM
The W7ZOI crystal filter design and crystal measurement methods are described
in detail in _Experimental Methods in RF Design_, published by the ARRL and
available from numerous sources. It should be every serious experimenter's
library.

Roy Lewallen, W7EL

Tom Bruhns wrote:
> If you have access to old QSTs, you should be able to find articles
> about measuring crystal parameters. Look especially for things by Wes
> Hayward, W7ZOI. There's a fairly simple crystal-tester you can build
> to measure enough parameters to extract equivalent L, Cs, Cp and R, I
> believe. I 'spose someone will pop in with a more specific reference
> for you.
>
> Cheers,
> Tom
>
> "Virgil Smith" > wrote in message news:<3iNHb.504277$275.1417484@attbi_s53>...
>
>>I have a bunch of oddball crystals that I want to test. I know I can just
>>build up a generic oscillator to find the
>>resonant frequency, but out of curiousity I would like to
>>know the quality of the things, too.
>>
>>Anyone know of any neat ideas for measuring the Q of a
>>crystal?
>>
>>I would welcome any and all suggestions,
>>
>>-vs-

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