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Thevenin and s-parameters...
Hello,
I'm have "little" doubt about s-parameter simulations. My question is very simple but I do not know if the answer is the same. The Thevenin theorem can be applied to a s-parameter simulation? That is, if I do a simulation using a port P1 of 50 ohm where at valley of the generator I've connected 2 impedences, one in parallel Z1 and one in series Z2. Supposing I obtained S11 at frequency f1. Then I incorporate the impedence Z2 (at frequency f1) in the port 1 impedence (using Thevenin), can I obtain the same S11 parameters for f1 fequency? Camelot |
Thevenin and s-parameters...
"camelot" wrote in message ups.com... Hello, I'm have "little" doubt about s-parameter simulations. My question is very simple but I do not know if the answer is the same. The Thevenin theorem can be applied to a s-parameter simulation? That is, if I do a simulation using a port P1 of 50 ohm where at valley of the generator I've connected 2 impedences, one in parallel Z1 and one in series Z2. Supposing I obtained S11 at frequency f1. Then I incorporate the impedence Z2 (at frequency f1) in the port 1 impedence (using Thevenin), can I obtain the same S11 parameters for f1 fequency? Camelot I believe the thevenin theorem applies to s-parameter simulation provided you assume the amplifier (generator) is perfect Class A and perfectly stable. You need to be aware of where the load is located on the transmission (1/4 wave? Not sure what you mean by 'valley'). See http://www.sss-mag.com/pdf/arrl_circles.pdf |
Thevenin and s-parameters...
camelot wrote:
Hello, I'm have "little" doubt about s-parameter simulations. My question is very simple but I do not know if the answer is the same. The Thevenin theorem can be applied to a s-parameter simulation? That is, if I do a simulation using a port P1 of 50 ohm where at valley of the generator I've connected 2 impedences, one in parallel Z1 and one in series Z2. Supposing I obtained S11 at frequency f1. Then I incorporate the impedence Z2 (at frequency f1) in the port 1 impedence (using Thevenin), can I obtain the same S11 parameters for f1 fequency? From: "Fields and Waves ...", by Ramo and Whinnery: "It must be emphasized, as in any Thevenin equivalent circuit, that the equivalent circuit was derived to to tell what happens in the *load* under different *load* conditions, and significance cannot be automatically attached to a calculation of power loss in the internal impedance of the equivalent circuit." Power loss in the internal impedance of the Thevenin equivalent circuit is related to the s-parameters. |s11|^2 is power reflected from the network input divided by the power incident on the network input. -- 73, Cecil http://www.w5dxp.com |
Thevenin and s-parameters...
Thank you for your comments,
I'm doing some calculations and simulations in order to verify if I can bypass representation problem of s-parameters in other ways rather than the Thevenin one. There is one thing I'd like to submit to your attention, the known formula S11=(Zin-Z0)/(Zin+Z0), where Z0 is the port impedance and Zin the load, does not works if you consider Z0 not pure real (usually 50 ohm) but composed by a real and an imaginary part i.e. Z0 = a+jb. Are there other known formulas for S11 for Z0 real+imaginary? Camelot |
Thevenin and s-parameters...
"camelot" wrote in message ups.com... Thank you for your comments, I'm doing some calculations and simulations in order to verify if I can bypass representation problem of s-parameters in other ways rather than the Thevenin one. There is one thing I'd like to submit to your attention, the known formula S11=(Zin-Z0)/(Zin+Z0), where Z0 is the port impedance and Zin the load, does not works if you consider Z0 not pure real (usually 50 ohm) but composed by a real and an imaginary part i.e. Z0 = a+jb. Are there other known formulas for S11 for Z0 real+imaginary? Camelot http://www.rfcafe.com/references/electrical/s-h-y-z.htm Also: http://www.daycounter.com/Calculator...lculator.phtml Regards, Frank (VE6CB) |
Thevenin and s-parameters...
On Jan 29, 2:12 am, "camelot" wrote: Thank you for your comments, I'm doing some calculations and simulations in order to verify if I can bypass representation problem of s-parameters in other ways rather than the Thevenin one. There is one thing I'd like to submit to your attention, the known formula S11=(Zin-Z0)/(Zin+Z0), where Z0 is the port impedance and Zin the load, does not works if you consider Z0 not pure real (usually 50 ohm) but composed by a real and an imaginary part i.e. Z0 = a+jb. Are there other known formulas for S11 for Z0 real+imaginary? Camelot Frank has already provided you with links to (I presume) transformations to other linear two-port representations. But I'm curious. Why do you think that the formula you wrote above doesn't work when Z0 is complex? In what way do you think it does not work? I'm also curious why you would pick a complex reference impedance for S-parameter work, but that's really a different issue. Cheers, Tom |
Thevenin and s-parameters...
"camelot" wrote in message ups.com... Thank you for your comments, I'm doing some calculations and simulations in order to verify if I can bypass representation problem of s-parameters in other ways rather than the Thevenin one. There is one thing I'd like to submit to your attention, the known formula S11=(Zin-Z0)/(Zin+Z0), where Z0 is the port impedance and Zin the load, does not works if you consider Z0 not pure real (usually 50 ohm) but composed by a real and an imaginary part i.e. Z0 = a+jb. Are there other known formulas for S11 for Z0 real+imaginary? Actually, characteristic impedance Z0 is assumed to be 50 Ohm, 300 Ohm or 75 Ohm (etc.), based on the type of transmission line, under the assumption that the line is "lossless", thus in theory only it only considers the complex components. For a lossless line, Z0 = sqrt(L/C) In reality, the resistance (conductance) must be considered, whe Z0 = sqrt((r+jwl)/(G+jwC)) |
Thevenin and s-parameters...
Hi Tom,
well, after few researches on several books, I found that the formula I provided by me works only for real Z0. The general formula valid in case Z0 is complex is the follow: S11=(Zin-Z0*)/(Zin+Z0) Where Z0* is the conjugate of Z0. Obviously, if Z0 is real, the conjugate coincide with the real one. However, thank you for your interest ;-) Camelot But I'm curious. Why do you think that the formula you wrote above doesn't work when Z0 is complex? In what way do you think it does not work? I'm also curious why you would pick a complex reference impedance for S-parameter work, but that's really a different issue. Cheers, Tom |
Thevenin and s-parameters...
On Jan 30, 11:13 pm, "camelot" wrote:
Hi Tom, well, after few researches on several books, I found that the formula I provided by me works only for real Z0. The general formula valid in case Z0 is complex is the follow: S11=(Zin-Z0*)/(Zin+Z0) Where Z0* is the conjugate of Z0. Obviously, if Z0 is real, the conjugate coincide with the real one. However, thank you for your interest ;-) Camelot But I'm curious. Why do you think that the formula you wrote above doesn't work when Z0 is complex? In what way do you think it does not work? I'm also curious why you would pick a complex reference impedance for S-parameter work, but that's really a different issue. Cheers, Tom I'm not sure where you got it, but the formula with the complex conjugate is NOT correct! The formula without complex conjugate is correct, for complex Z and Z0, both. That the formula using the complex conjugate is incorrect is trivial to see: consider that a line terminated in a load equal to the line's characteristic impedance (be it purely resistive, or complex) has no reflection. That is, if load Z = Z0, there is no reflection. Then if Z0 is complex and has a non-zero reactive component, your formula yields S11 which is not zero, for a line which is terminated to have no reflection. As far as I am concerned, that would be incorrect. The original formula, without complex conjugate, yields the correct answer for this case. Can you come up with a case where it is incorrect? Cheers, Tom |
Thevenin and s-parameters...
Hi Tom,
as far as I am concerned, your observations are rights only if we are talking about real quantities. If you have a load that is complex then you obtain perfect matching (there is no reflection) only if Z0 is not equal to Zin but it is the conjugate of Zin. If you remember, this is the same condition valid for the maximum power transferring when the load in complex. Do you agree with these considerations? Regards, Camelot I'm not sure where you got it, but the formula with the complex conjugate is NOT correct! The formula without complex conjugate is correct, for complex Z and Z0, both. That the formula using the complex conjugate is incorrect is trivial to see: consider that a line terminated in a load equal to the line's characteristic impedance (be it purely resistive, or complex) has no reflection. That is, if load Z = Z0, there is no reflection. Then if Z0 is complex and has a non-zero reactive component, your formula yields S11 which is not zero, for a line which is terminated to have no reflection. As far as I am concerned, that would be incorrect. The original formula, without complex conjugate, yields the correct answer for this case. Can you come up with a case where it is incorrect? Cheers, Tom- Hide quoted text - - Show quoted text - |
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