"Richard Clark" wrote in message
...
On Tue, 6 Feb 2007 22:35:04 -0500, "Stefan Wolfe"
wrote:

2. The effect of the 80m hill 10Km away is negligible. The arc tan is only
.008 degrees, thus the transmitter hardly "sees" it.

Actually, Stefan, the transmitter cannot see through it at all.

Answer: 0 Feet.

Our Lincolnshire student needs to think back to simple trigonometry to
answer this. The path loss, once the height of the hill is made
irrelevant, is sufficient as Stefan points out.

73's
Richard Clark, KB7QHC
The only way I could figure the hill in is if one is trying to Knife-edge
over the hill. Otherwise the hill is totally irrelevant to the problem.