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#1
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hello
Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi |
#2
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![]() wrote in message oups.com... hello Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi Who is right, you or Jeff? You are more than 100% off from each other. In truth, i could receive that signal holding a hand held 10GHz receiver while sitting on the ground. The 80m hill is nothing from an observer 10KM away...only .006 degree from the top of the transmitter tower. It is part of the horizon. I love it when you guys talk like you are sol knowledgeable yet lack the common sense to conceptualize the problem as it really exists. |
#3
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![]() " In truth, i could receive that signal holding a hand held 10GHz receiver while sitting on the ground. The 80m hill is nothing from an observer 10KM away...only .006 degree from the top of the transmitter tower. It is part of the horizon. I love it when you guys talk like you are sol knowledgeable yet lack the common sense to conceptualize the problem as it really exists. So you are saying that you can achieve 30km at 10GHz to a hand held receiver at ground level with a 300 foot hill in the way!!! I am sure that you could not do this with any sensible power even at 2m let alone 10GHz. Perhaps it is your concept of what is going on that is wrong. Have you heard of Fresnel Zones?? When obstructions come within the first Fresnel zone significant attenuation occurs. With the situation that you are describing the path is totally obstructed, with the path only possible due to diffraction from the hill top. The hill top impinges to at least the top of the 5th Fresnel Zone, hence the attenuation is very high. As the height of the Rx antenna increases the attenuation is still very high until the hill top only start to intersect with of the first zone (antenna height~150m). It then drops quite rapidly until there is true line of sight and bottoms out when the hill top is clear of the second zone. You make a great deal of the hill only being 0.006 degree at the horizon. If you plot it accurately and with reference to the Fresnel zones, it does make a big difference. With the Rx antenna at ground level the top of the Fresnel zones are never below the horizon, which is completely different to the situation when the hill is there (-5th Zone obstructed). Also, without the hill you only have to raise the Rx antenna to about 15m to achieve line of sight compared to 200m with the hill there!!!!!! Quite a big difference I think you will agree, and one that your 'conceptualisation doesn't seem to allow for!! 73 Jeff |
#4
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![]() wrote in message oups.com... hello Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi Please show your work. |
#5
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![]() "Stefan Wolfe" wrote in message ... wrote in message oups.com... hello Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi Please show your work. Hi Stephan Your posts seem to inply that the receive antenna will "see" the 20 meter high transmitting antenna when the receiver antenna is in the shadow of the 80 meter hill. It seems that the receiver needs to be out of the shadow of the hill unless you are able to estimate refraction from the hill. But, your aparent confidance in the statement "0 feet" makes me wonder if I have this problem wrongly analyzed. I have so much confidance in Richard Fry's data that I had accepted his estimation of 270 meters to be as close as you can estimate. Do I misunderstand your post about what minimum height is needed? Jerry |
#6
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![]() "Jerry Martes" wrote in message news:iLuyh.5336$384.156@trnddc05... "Stefan Wolfe" wrote in message ... wrote in message oups.com... hello Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi Please show your work. Hi Stephan Your posts seem to inply that the receive antenna will "see" the 20 meter high transmitting antenna when the receiver antenna is in the shadow of the 80 meter hill. It seems that the receiver needs to be out of the shadow of the hill unless you are able to estimate refraction from the hill. But, your aparent confidance in the statement "0 feet" makes me wonder if I have this problem wrongly analyzed. I have so much confidance in Richard Fry's data that I had accepted his estimation of 270 meters to be as close as you can estimate. Do I misunderstand your post about what minimum height is needed? Jerry Hi Jerry, how many shadows have you seen that are 20Km long? |
#7
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From: "Stefan Wolfe"
how many shadows have you seen that are 20Km long? ______________ Can we count the shadow of the moon on the earth during a fully-eclipsed sun? If so, that's a bit more than 20 km. RF |
#8
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![]() "Stefan Wolfe" wrote in message ... "Jerry Martes" wrote in message news:iLuyh.5336$384.156@trnddc05... "Stefan Wolfe" wrote in message ... wrote in message oups.com... hello Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi Please show your work. Hi Stephan Your posts seem to inply that the receive antenna will "see" the 20 meter high transmitting antenna when the receiver antenna is in the shadow of the 80 meter hill. It seems that the receiver needs to be out of the shadow of the hill unless you are able to estimate refraction from the hill. But, your aparent confidance in the statement "0 feet" makes me wonder if I have this problem wrongly analyzed. I have so much confidance in Richard Fry's data that I had accepted his estimation of 270 meters to be as close as you can estimate. Do I misunderstand your post about what minimum height is needed? Jerry Hi Jerry, how many shadows have you seen that are 20Km long? Hi Stephan Tell me where I have misunderstood the problem. I assumed the transmitting antenna was Lower than the top of the hill. But, you seem to imply that the transmitter can be seen even when the hill is blocking the "view" to it. I have actually never measured a shadow longer that a few feet, but I assumed they continued to exist to infinity when an object blocks them from view. Jerry |
#9
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![]() "Jerry Martes" wrote in message news:2Yvyh.37369$5U4.35764@trnddc07... "Stefan Wolfe" wrote in message ... "Jerry Martes" wrote in message news:iLuyh.5336$384.156@trnddc05... "Stefan Wolfe" wrote in message ... wrote in message oups.com... hello Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi Please show your work. Hi Stephan Your posts seem to inply that the receive antenna will "see" the 20 meter high transmitting antenna when the receiver antenna is in the shadow of the 80 meter hill. It seems that the receiver needs to be out of the shadow of the hill unless you are able to estimate refraction from the hill. But, your aparent confidance in the statement "0 feet" makes me wonder if I have this problem wrongly analyzed. I have so much confidance in Richard Fry's data that I had accepted his estimation of 270 meters to be as close as you can estimate. Do I misunderstand your post about what minimum height is needed? Jerry Hi Jerry, how many shadows have you seen that are 20Km long? Hi Stephan Tell me where I have misunderstood the problem. I assumed the transmitting antenna was Lower than the top of the hill. But, you seem to imply that the transmitter can be seen even when the hill is blocking the "view" to it. I have actually never measured a shadow longer that a few feet, but I assumed they continued to exist to infinity when an object blocks them from view. Well you see Jerry, the reason you only see it for a few feet is because the attenuation of the light varies inversely with the distance from the object that blocks the light. I think you have done a good job in making my point. Thanks, |
#10
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![]() "Stefan Wolfe" wrote in message ... "Jerry Martes" wrote in message news:2Yvyh.37369$5U4.35764@trnddc07... "Stefan Wolfe" wrote in message ... "Jerry Martes" wrote in message news:iLuyh.5336$384.156@trnddc05... "Stefan Wolfe" wrote in message ... wrote in message oups.com... hello Jeff i am very thank full to your help, i have got Rx height 101.2 Regards naqvi Please show your work. Hi Stephan Your posts seem to inply that the receive antenna will "see" the 20 meter high transmitting antenna when the receiver antenna is in the shadow of the 80 meter hill. It seems that the receiver needs to be out of the shadow of the hill unless you are able to estimate refraction from the hill. But, your aparent confidance in the statement "0 feet" makes me wonder if I have this problem wrongly analyzed. I have so much confidance in Richard Fry's data that I had accepted his estimation of 270 meters to be as close as you can estimate. Do I misunderstand your post about what minimum height is needed? Jerry Hi Jerry, how many shadows have you seen that are 20Km long? Hi Stephan Tell me where I have misunderstood the problem. I assumed the transmitting antenna was Lower than the top of the hill. But, you seem to imply that the transmitter can be seen even when the hill is blocking the "view" to it. I have actually never measured a shadow longer that a few feet, but I assumed they continued to exist to infinity when an object blocks them from view. Well you see Jerry, the reason you only see it for a few feet is because the attenuation of the light varies inversely with the distance from the object that blocks the light. I think you have done a good job in making my point. Thanks, Hi Stephan I now understand now that you do think you can receive 10 GHz signals while the receiver is in the shadow caused by the mountain between you and the transmitter. Do I understand you correctly? Jerry |
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