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Measuring Antenna Efficiency
Owen Duffy wrote:
Firstly you seem to assume that your 36 samples around the azimut circle adequately fulfill Roy's "sampling the field at many points in all directions", surely he mean't all elevation angles as well as all azimuth angles. What is the hourly rental charge on a helicopter? :-) -- 73, Cecil http://www.w5dxp.com |
Measuring Antenna Efficiency
Cecil Moore wrote:
Owen Duffy wrote: Firstly you seem to assume that your 36 samples around the azimut circle adequately fulfill Roy's "sampling the field at many points in all directions", surely he mean't all elevation angles as well as all azimuth angles. What is the hourly rental charge on a helicopter? :-) that's what balloons and blimps are for, or model airplanes.. |
Measuring Antenna Efficiency
Owen wrote:
"Is that true?" Only for limited conditions. Owen is correct that enough samples must be taken to catch all variations in signal strength, in elevation and azimuth if total radiated power is to be determined. A simple vertical antenna rests on the earth and has a null at its tip. It is far from an isotropic radiator. The sampling I described is done on AM broadcast antennas. Only the wave which travels along the earth is usually of any interest. The minimum distance from the broadcast antenna for any field strength measurements is usually one mile to be sure the far field is being measured. The FCC`s ground wave intensity charts assume that if you have ground conductivity such as sea water, a certain power and antenna efficiency deliver 100 millivolts per meter at a distance of one mile from the antenna. Field intensity in millivolts declines linearly with distance so that at 10 miles you might have 10 mv/m if you have 100 mv/m at one mile.Power is proportional to the square of the voltage. Best regards, Richard Harrison, KB5WZI |
Measuring Antenna Efficiency
Richard Harrison wrote:
The FCC`s ground wave intensity charts assume that if you have ground conductivity such as sea water, a certain power and antenna efficiency deliver 100 millivolts per meter at a distance of one mile from the antenna. Field intensity in millivolts declines linearly with distance so that at 10 miles you might have 10 mv/m if you have 100 mv/m at one mile. . . . The attenuation of the ground wave is the same as the free space attenuation? Roy Lewallen, W7EL |
Measuring Antenna Efficiency
Roy Lewallen, W7EL wrote:
"The attenuation of the ground wave is the same as the free space attenuation?" No, it is greater. The attenuation of the ground wave is more rapid because the soil has resistance and imposes a loss on the passing wave. In free space, there is no ground loss and the signal loss is from the spreading of the signal which reduces its density. It declines 6 dB (its power is quartered) every time the distance from the transmitter doubles, that is its volts per meter or signal strength is cut in half. Ground waves decrease more rapidly with distance from the transmitter due to imperfect conductivity in the earth`s surface. Loss goes up with the operating frequency and with higher resistivity in the soil. The FCC`s ground-wave field intensity charts cover limited frequency ranges and each curve is for a specific soil conductivity. Best regards, Richard Harrison, KB5WZI |
Measuring Antenna Efficiency
Richard Harrison wrote:
Roy Lewallen, W7EL wrote: "The attenuation of the ground wave is the same as the free space attenuation?" No, it is greater. The attenuation of the ground wave is more rapid because the soil has resistance and imposes a loss on the passing wave. . . . I should hope so. That's why your statement that the field strength decreases as the inverse of the distance in the context of AM broadcast measurements at ground level was puzzling. Roy Lewallen, W7EL |
Measuring Antenna Efficiency
On Mon, 23 Apr 2007 17:30:20 -0700, Roy Lewallen
wrote: Richard Harrison wrote: Roy Lewallen, W7EL wrote: "The attenuation of the ground wave is the same as the free space attenuation?" No, it is greater. The attenuation of the ground wave is more rapid because the soil has resistance and imposes a loss on the passing wave. . . . I should hope so. That's why your statement that the field strength decreases as the inverse of the distance in the context of AM broadcast measurements at ground level was puzzling. Richard had been reciting decade-for-decade declines of FS faithfully from the FCC charts -over seawater- which he had specifically called out. "Faithfully" except for an inadvertent substitution of decade miles for decade kilometers distance. 73's Richard Clark, KB7QHC |
Measuring Antenna Efficiency
Richard Clark, KB7QHC wrote:
"Faithfully" except for an inadvertent substitution of decade miles for decade kilometers distance." Thank you Richard for such a kind word as "inadvertent". I make mistakes and I apologize for them. Hopefully, none of consequence go uncorrected and mislead anyone. I learn more from my mistakes than from correct postings but it isn`t my favorite way to learn. Thank you to everyone who prompts me to search for the answer to an interesting question. I`m still puzzled about "cluster antennas". Best regards, Richard Harrison, KB5WZI |
Measuring Antenna Efficiency
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Measuring Antenna Efficiency
I`m still puzzled about "cluster antennas". Best regards, Richard Harrison, KB5WZI I really don't know why it puzzles you. I have determined that coupling of elements which means parasitic coupling is wastfull. To avoid this coupling one must have elements that are all resonant. This means ofcourse that element dimensions are necessarily different from neighboring elements so that coupling per se ( there is no attraction or repeling actions between elements) removed which thus creates an arrangement that is in equilibrium. When elements are associated with each other one can call them a 'collection' of elements or a 'cluster' of elements. Now with respect to efficiency this array does not have coupling associated with reflectors and directors thus if the array was energised then a far field of radiation is formed without any wastefull interaction of particles between elements. So when the far field is formed the only "waste" of energy is that created by skin resistance which is easily calculated, since without interaction between elements non radiating energy collision losses cannot occur. If one is looking for efficiency one usually work with input energy equals output energy plus losses. When one is examining the amount of radiation formed in the far field because one does not want to get into a situation of interactive bombardment of partcles that do not contribut to radiation in the far field prior to the generation of radiation. This analysis I suppose can be considered a simple relationship with Poyntings vector and in a way provides support for Poynting where none existed before but I may be over reaching there in some eyes. Hope that satisfies your curiousity Art |
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