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VSWR doesn't matter?
Jerry Martes wrote:
"David G. Nagel" wrote in message ... Tim Wescott wrote: billcalley wrote: We are all told that VSWR doesn't matter when using low loss transmission lines, since the RF energy will travel from the transmitter up to the mismatched antenna, where a certain amount of this RF energy will reflect back towards the transmitter; after which the RF will then reflect back up to the antenna -- where the energy is eventually radiated after bouncing back and forth between the transmitter and antenna. I understand the concept, but what I don't quite understand is why the reflected RF energy isn't simply absorbed by the 50 ohm output of the transmitter after the first reflection? For the RF to bounce back and forth, wouldn't the transmitter's impedance have to be very, very high (or low) when the reflected RF energy hit its output stages? I know I'm missing something vital here... That's assuming you use an antenna tuner. The tuner will transform the transmitter's output impedance* just as it transforms the line. Were the transmitter output impedance actually at 50 ohms, on the other side of the tuner it would have the same VSWR as the line when everything was tuned up. Having said that, the VSWR _does_ matter somewhat when using low loss lines, both because the line loss is low but not zero, and the tuner loss will tend to go up as you correct for higher and higher VSWR. * I am _not_ going to start the Big Transmitter Output Impedance Debate. sed denizens -- just don't comment on what a transmitter's "actual" output impedance may be, lest you start a flame war. If you want a quick lesson in high vswr find a ham with an old tube transmitter and see if he will hook it up to a mismatched load. The cherry red plates are the reflected energy being absorbed. Transistors will just turn to smoke under the same conditions. Dave WD9BDZ Hi david Wouldnt it be OK to have a high VSWR along the transmission line if the "tank ckt" can be adjusted to match the load to the transmitter output impedance? That is, the VSWR along the transmission could concievely be high, yet, with proper "tank ckt" adjustment that impedance seen by the output circuit (plate) wouldnt result in a "cherry red plate". What I am asking is ? is the transmission line VSWR directly related to "plate reddening"? I'm more asking than *telling*. Jerry Jerry; The point I was trying to make is that the reflected current is disapated as heat in the finals if the transmitter isn't matched to the load. In a tube radio the tank circuit is the equivilent of an antenna match/tuner and converts the 2000 or so ohms at the plate to the 50 ohms of the transmission line and the unknown ohms of the mis matched antenna. Dave WD9BDZ |
VSWR doesn't matter?
On Mar 12, 4:56 am, Richard Clark wrote:
On 11 Mar 2007 20:39:46 -0700, "Bob" wrote: The active part of the transmitter output isn't 50 ohm. That would cause half the power to be lost as heat in the output stage. Hi Bob, Well, aside from the initial misunderstanding of how power gets to the load (much less back, and then to the load again); I will put to you a question that has NEVER been answered by those who know what the transmitter output Z ISN'T: "What Z is it?" 73's Richard Clark, KB7QHC As Tim Williams alludes, it depends on the transmitter design. It will often be complex rarther than resistive. Since the active device changes impedance during a single cycle of the RF signal it may not even be adequately described by a single value in ohms for a paticular frequency if you wish to analyse the case of forward and reflected power. Consider a class C or class E output stage with an output transistor that is low impedance during most of the positive half of a cycle of signal and mostly somewhere near open circuit for the negative half of the cycle. It seems to me that the effect of reflected power is going to be different depending its phase relative to the forward power. I think this also applys to a lesser extent to a class A PA with a nice hi-Q tank circuit. As usually whan this topic comes up, It don't feel like we have arrived at a usefull and convincing model of what happens, possibly because simple descriptions don't cover everything. Bob |
VSWR doesn't matter?
On 12 Mar 2007 23:00:59 -0700, "Bob" wrote:
As Tim Williams alludes, it depends on the transmitter design. Hi Bob, No quantifiable answer I see. It's not unexpected, everyone who knows what it isn't has never been able to say what it is. It seems like the stock answer you give the cop who asks if you know the speed limit. "No. But I wasn't speeding!" The dependency here started with a conventional Ham transmitter, one so ordinary as to be a commodity. The design is not so exotic as to elude a very simple value - except for those who know it isn't 50 Ohms. 73's Richard Clark, KB7QHC |
VSWR doesn't matter?
"Cecil Moore" wrote in message
... Of course, that was a tongue-in-cheek posting. But if you could design a Thevenin equivalent source with a 0.1 ohm source impedance, wouldn't the efficiency calculate out to be pretty high? Class D rules. (Using MOSFETs, the Thevenin equivalent is quite easy to spot, too!) Tim -- Deep Fryer: A very philosophical monk. Website @ http://webpages.charter.net/dawill/tmoranwms |
VSWR doesn't matter?
"Roy Lewallen" wrote
The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. _____________ But reflected energy/power does exist. For an easy example, such reflections are evident in the picture seen on an analog TV receiver when the match between the transmit antenna and the transmission connected to it is bad enough. In analog TV transmit systems with a typical 500+ foot length transmission line from the tx to the antenna, a 5% reflection from a far-end mismatch can be quite visible, showing as a "ghost" image that is offset from the main image as related to the round-trip propagation time of the transmission line. RF |
VSWR doesn't matter?
Jimmie D wrote:
"Dan Bloomquist" wrote in message ... billcalley wrote: We are all told that VSWR doesn't matter when using low loss transmission lines, since the RF energy will travel from the transmitter up to the mismatched antenna, where a certain amount of this RF energy will reflect back towards the transmitter; after which the RF will then reflect back up to the antenna -- where the energy is eventually radiated after bouncing back and forth between the transmitter and antenna. As pointed out, VSWR does matter. A lot of bouncing means you heat the transmission line with the power instead of radiating the power. 'Doesn't matter', really means it can be tolerated if need be. I understand the concept, but what I don't quite understand is why the reflected RF energy isn't simply absorbed by the 50 ohm output of the transmitter after the first reflection? For the RF to bounce back and forth, wouldn't the transmitter's impedance have to be very, very high (or low) when the reflected RF energy hit its output stages? I know I'm missing something vital here... Here is what you are missing. In the case of the output, (real/resistive component of the transmitter), seeing the reflected wave, it is _not_ reflecting that power back up the transmission line as you think it is. It would go back to that real impedance and heat the transmitter. Here is what is done with a miss match in the real world. trans-output - match - line - antenna The 'match' is where the magic happens. All the energy coming down the line that got reflected from the antenna 'sees' the 'trans-output - match' as a perfect reflector and gets bounced back[*]. On the other side of the match is the trans-output. There the trans-output sees a perfect impedance, (technically, the conjugate of the trans-output), so that all the power travels through the match toward the antenna. The magic is that when the match is tuned, both of the above conditions are satisfied. *The reflected wave sees a purely reactive reflector not just because of the network but also because of the output power of the transmitter. Without transmitter power the impedance as seen from the load will dramatically change. Best, Dan. Saying that SWR doesnt matter is a rather broad statement(like saying never or always) but I have know of antenna systems having an SWR of 30:1 and his was normal. The feedline was balanced line made of 1 inch copper. Of course an SWR lie this on coax could be fatal to coax and equipment. A more common example of this is the 1/4 wl matching section on a J-pole antenna. It matches 50 ohms to a few Kohms so an SWR of 60: 1 or so would not be unusal here.S oas long as the feedline can handle the current and voltage peaks without much los it doesnt matter much as long as the source impedance is matched to the impedance at the input to the transmission line.Im sure there is a practical limit though. Hi Jimmie, Keep in mind I'm answering in the context of the op's post. And the theoretical SWR on a stub is infinite. The point of the stub at the antenna is to keep the SWR on the transmission line in a reasonable range, to make a match if you will. To put high SWR on the feedline instead of matching at the antenna isn't a great idea in my book. OTOH. I finally did some sidebanding a couple of months ago. (First time on HF.) I got my hands on an old swan 500c. After changing the 6je6's and supply caps, I had to find out what it was like to get on the air. I ran outside and hung a wire between the lab and the shop. 40-50 feet. Put a couple of alligator clips on the end of a chunk of rg-58 and into the window. I started looking for the antenna through the trans-match with an antenna bridge. The tuning was very sharp, lots of Q. I don't know if I could have found it without the bridge :) I was willing to tolerate the miss match to get on the air. Well, it worked out. I made some great QSLs across the mid west and into northern CA. I live in Vernon AZ. I'm pleased this turned out to be as great a radio location as I thought. It shouldn't be long before I get a beam on a tower. By then I'll look to match at the antenna and keep the SWR off the feed line as much as possible. Best, Dan. |
VSWR doesn't matter?
Roy Lewallen wrote:
Yes! All that matters to the transmitter is the impedance it sees. It doesn't know or care that you've mathematically separated the delivered power into "forward" and "reverse" components. It doesn't know or care what the SWR is on the transmission line connected to it, or even if a transmission line is connected at all. Well, without a line, you don't have a real component to tune into. Drawing arcs on a smith chart from an open line with capacitors and coils will only get you to another purely reactive point. Best, Dan. |
VSWR doesn't matter?
In rec.radio.amateur.antenna Roy Lewallen wrote:
David G. Nagel wrote: If you want a quick lesson in high vswr find a ham with an old tube transmitter and see if he will hook it up to a mismatched load. The cherry red plates are the reflected energy being absorbed. Transistors will just turn to smoke under the same conditions. Unfortunately, you'd be learning the wrong lesson. The cherry color is due to the transmitter being loaded with an impedance it's not designed for, causing the final to run at low efficiency. You can disconnect the antenna and replace it with a lumped RC or RL impedance of the same value and get exactly the same result. Alternatively, you can attach any combination of load and transmission line which give the same impedance, resulting in a wide variation of "reflected energy", and get exactly the same result. All that counts is the impedance seen by the transmitter, not the VSWR on the line or the "reflected power". The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. See http://eznec.com/misc/Food_for_thought.pdf for more. Roy Lewallen, W7EL The fact that any transmission line and antenna combination can be replaced with an RLC lumped load at the transmitter output and the transmitter can't tell the difference is something that a lot of hams seem to have a problem understanding. What I've never understood is why so many hams have a problem with the concept of equivalent circuits only when antennas and transmission lines are involved. -- Jim Pennino Remove .spam.sux to reply. |
VSWR doesn't matter?
"Dan Bloomquist" wrote in message ... Jimmie D wrote: "Dan Bloomquist" wrote in message ... Hi Jimmie, Keep in mind I'm answering in the context of the op's post. And the theoretical SWR on a stub is infinite. The point of the stub at the antenna is to keep the SWR on the transmission line in a reasonable range, to make a match if you will. To put high SWR on the feedline instead of matching at the antenna isn't a great idea in my book. Sure yoiu can, that stub is a transmission line. It would matter if it s a 1/4 wl long or 21 1/4 wl long. If it is designed to handle the current and voltage peaks it can transmit power with low loss when a high VSWR is present. Its just that most people dont make there feedlines out of inch copper tubing. Even with 450 ohm ladder line 10:1 VSWR is very acceptable. |
VSWR doesn't matter?
Richard Fry wrote:
"Roy Lewallen" wrote The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. _____________ But reflected energy/power does exist. For an easy example, such reflections are evident in the picture seen on an analog TV receiver when the match between the transmit antenna and the transmission connected to it is bad enough. In analog TV transmit systems with a typical 500+ foot length transmission line from the tx to the antenna, a 5% reflection from a far-end mismatch can be quite visible, showing as a "ghost" image that is offset from the main image as related to the round-trip propagation time of the transmission line. RF Richard, You are undoubtedly correct, but you have also demonstrated what is really the lifeblood of many arguments in RRAA. You have introduced both transient behavior and multi-frequency behavior. Clearly these are important in the real world. However, the vast majority of models and calculations used as support for RRAA postings are steady-state and monochromatic. Anyone who stayed awake through calculus and differential equations might recall that the equations for steady-state and transient behavior are often quite different. No one denies the existence of reflections. Some people get confused by the mathematics of power and voltage. But a big argument is about the round-trip travel of energy in the steady-state. Some people seem to believe that energy continues to flow back and forth from one end of a (mismatched) transmission line to the other under steady-state conditions, even simultaneously traveling in both directions. (Passing like ships in the night?) Since energy is a scalar quantity, and any given joule is not distinguishable from another, it is not clear how the proponents keep track of the bookkeeping, but they muddle through somehow. 73, Gene W4SZ |
VSWR doesn't matter?
Richard Fry wrote: "Roy Lewallen" wrote The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. _____________ But reflected energy/power does exist. For an easy example, such reflections are evident in the picture seen on an analog TV receiver when the match between the transmit antenna and the transmission connected to it is bad enough. In analog TV transmit systems with a typical 500+ foot length transmission line from the tx to the antenna, a 5% reflection from a far-end mismatch can be quite visible, showing as a "ghost" image that is offset from the main image as related to the round-trip propagation time of the transmission line. Richard, The round trip time on the transmission line is 1uS+, and the period of the highest modulating frequency is 0.2uS, so transient performance of the line is very important. Run the numbers on typical ham SSB telphony where the rtt is more like 0.2uS+ and the period of the highest modulating frequency is 300uS, is it any wonder transient performance isn't critical. So, if a solution in the steady state solution doesn't degrade the modulation, why complicate matters with pretend partial time domain solutions. It is half baked thinking in both worlds that drives the thinking that reflected power *must* be dissipated in the anode. There is no doubt that under load end mismatch, there is a reflected wave on the transmission line, and there is no doubt that under some conditions, the anode dissipates more power, and they may be correlated, but the simplistic explanation above that is commonly touted is BS. Owen |
VSWR doesn't matter?
In rec.radio.amateur.antenna Richard Clark wrote:
On Tue, 13 Mar 2007 16:05:02 GMT, wrote: The fact that any transmission line and antenna combination can be replaced with an RLC lumped load at the transmitter output and the transmitter can't tell the difference is something that a lot of hams seem to have a problem understanding. Hi Jim, Would it be fair to say there are a number of Hams (no need to go into proportionality, could be equal number) who have difficulties of understanding with going from lumped, equivalent circuits to antennas and transmission lines? The two perspectives are not exclusionary nor mutually incompatible, only the arguers are. I'd have to say that as soon as a circuit contains a radiator or a transmission line the arm waving begins. -- Jim Pennino Remove .spam.sux to reply. |
VSWR doesn't matter?
On Mar 12, 11:50 pm, Roy Lewallen wrote:
The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. It also isn't true that there is no energy in the reflected wave, that such beliefs are gobbledegook, and that RF standing wave energy just sloshes around in a transmission line at less than light speed. To really understand what is going on, one has to understand superposition and interference between RF energy waves. You are on record as not caring to understand reflected energy. Please don't condemn those of us who are trying to understand. -- 73, Cecil, w5dxp.com |
VSWR doesn't matter?
On Mar 12, 11:53 pm, Roy Lewallen wrote:
Yes! All that matters to the transmitter is the impedance it sees. It doesn't know or care that you've mathematically separated the delivered power into "forward" and "reverse" components. It doesn't know or care what the SWR is on the transmission line connected to it, or even if a transmission line is connected at all. Think about this - if the transmission line is exactly one-wavelength long and lossless, the transmitter sees exactly the same impedance as the load. At the load, we know reflections occur, but they are same-cycle reflections so during steady-state with no modulation, exactly the same conditions exist at the transmitter as exist at the load if the transmitter has the same impedance as the transmission line. So even if we cannot measure the reflections back into the transmitter, they are no doubt, there - that is, unless one denies the existence of reflections in which case, one needs to explain how standing waves are possible without reflections in a single-source system. -- 73, Cecil, w5dxp.com |
VSWR doesn't matter?
On 13 Mar 2007 14:19:12 -0700, "Cecil Moore" wrote:
On Mar 12, 11:50 pm, Roy Lewallen wrote: The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. It also isn't true that there is no energy in the reflected wave, that such beliefs are gobbledegook, and that RF standing wave energy just sloshes around in a transmission line at less than light speed. To really understand what is going on, one has to understand superposition and interference between RF energy waves. You are on record as not caring to understand reflected energy. Please don't condemn those of us who are trying to understand. Did you guys on this thread know that it's been proven statistically that five out of four people have trouble with fractions? Walt,W2DU |
VSWR doesn't matter?
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VSWR doesn't matter?
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VSWR doesn't matter?
Walter Maxwell wrote:
On 13 Mar 2007 14:19:12 -0700, "Cecil Moore" wrote: On Mar 12, 11:50 pm, Roy Lewallen wrote: The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. It also isn't true that there is no energy in the reflected wave, that such beliefs are gobbledegook, and that RF standing wave energy just sloshes around in a transmission line at less than light speed. To really understand what is going on, one has to understand superposition and interference between RF energy waves. You are on record as not caring to understand reflected energy. Please don't condemn those of us who are trying to understand. Did you guys on this thread know that it's been proven statistically that five out of four people have trouble with fractions? Walt,W2DU Walt, I didn't know that, but I'm dain bramaged. 73, Gene W4SZ |
VSWR doesn't matter?
Walter Maxwell wrote in
: On 13 Mar 2007 14:19:12 -0700, "Cecil Moore" wrote: Did you guys on this thread know that it's been proven statistically that five out of four people have trouble with fractions? That's vulgar! |
VSWR doesn't matter?
"Owen Duffy" wrote
Richard, The round trip time on the transmission line is 1uS+, and the period of the highest modulating frequency is 0.2uS, so transient performance of the line is very important. ____________ Sorry, sir, but quite a few decades of experience in the analog TV broadcast industry show otherwise (not to mention an accurate theoretical analysis of this condition). For example, a reflection within an analog TV broadcast signal that is delayed by one microsecond from the main image equates to something like a 10% horizontal displacement of that reflected, or "ghost" image from the main image (525/60Hz TV standard). A ghost television image amounting to 5% of the main image, and offset by 10% of the width of even a fairly small display screen is not difficult to see (or to be objected to) by an "average" observer at an "average" viewing distance from that display screen. Reflected r-f power may be less of a concern to amateur radio operators than it is to commercial operators, but that doesn't mean that reflected power is non-existent, or even unimportant. RF http://rfry.org |
VSWR doesn't matter?
"Richard Fry" wrote in :
"Owen Duffy" wrote Richard, The round trip time on the transmission line is 1uS+, and the period of the highest modulating frequency is 0.2uS, so transient performance of the line is very important. ____________ Sorry, sir, but quite a few decades of experience in the analog TV broadcast industry show otherwise (not to mention an accurate theoretical analysis of this condition). Richard, I don't think you read my words. You are disagreeing with my proposition that transient performance of the line is very important (in the TV example you cited). Owen |
VSWR doesn't matter?
"Bob" wrote in message ups.com... On Mar 12, 1:08 am, "billcalley" wrote: We are all told that VSWR doesn't matter when using low loss transmission lines, No, we are not all told that. The active part of the transmitter output isn't 50 ohm. That would cause half the power to be lost as heat in the output stage. It's only 50ohm once it becomes a moving wave in the transmission line. Bob9 In that case... Half power is only lost when terminated to a 50-ohm load; i.e. no standing waves. What happens when there's a mismatch and reflected energy :) I'll go stand in a corner... |
VSWR doesn't matter?
"Uncle Peter" wrote in message ... "Bob" wrote in message ups.com... On Mar 12, 1:08 am, "billcalley" wrote: We are all told that VSWR doesn't matter when using low loss transmission lines, No, we are not all told that. The active part of the transmitter output isn't 50 ohm. That would cause half the power to be lost as heat in the output stage. It's only 50ohm once it becomes a moving wave in the transmission line. Bob9 In that case... Half power is only lost when terminated to a 50-ohm load; i.e. no standing waves. What happens when there's a mismatch and reflected energy :) I'll go stand in a corner... A mismatch where, between the feedline and the antenna, feedline and source, source and impedance seen at the input to the feedline. Jimmie |
VSWR doesn't matter?
On Tue, 13 Mar 2007 17:39:04 -0500, "Richard Fry" wrote:
"Owen Duffy" wrote Richard, The round trip time on the transmission line is 1uS+, and the period of the highest modulating frequency is 0.2uS, so transient performance of the line is very important. ____________ Sorry, sir, but quite a few decades of experience in the analog TV broadcast industry show otherwise (not to mention an accurate theoretical analysis of this condition). For example, a reflection within an analog TV broadcast signal that is delayed by one microsecond from the main image equates to something like a 10% horizontal displacement of that reflected, or "ghost" image from the main image (525/60Hz TV standard). A ghost television image amounting to 5% of the main image, and offset by 10% of the width of even a fairly small display screen is not difficult to see (or to be objected to) by an "average" observer at an "average" viewing distance from that display screen. Reflected r-f power may be less of a concern to amateur radio operators than it is to commercial operators, but that doesn't mean that reflected power is non-existent, or even unimportant. RF http://rfry.org I know that Roy was heavily involved with TDR at Tektronix years ago. I began working at the RCA Laboratories' antenna lab in 1958. I don't know what Tektronix was doing relative to TDR at that time, but one of my colleagues at the lab was Donald Peterson. Don was then working on TDR, and to our knowledge then, his work on the subject was new. His experiments showed that using TDR we could spot problems in a TV TX transmission line that was causing ghosts. Using Don's technique, he traveled to many TV stations around the country that had ghost problems, and with TDR he was able to determine the precise location of a discontinuity in the transmission line that produced a reflection that caused the ghost. That was over 40 years ago, but I seem to remember that any discontinuity that resulted in a VSWR greater than 1.005:1 produced a ghost that could not be tolerated in the transmitted picture. I'm sure this is the magnitude of reflections Richard F. is referring to. Walt, W2DU |
VSWR doesn't matter?
On Tue, 13 Mar 2007 22:28:02 GMT, Owen Duffy wrote:
Walter Maxwell wrote in : On 13 Mar 2007 14:19:12 -0700, "Cecil Moore" wrote: Did you guys on this thread know that it's been proven statistically that five out of four people have trouble with fractions? That's vulgar! The stat ement or the fractions? Walt, W2DU |
VSWR doesn't matter?
On Tue, 13 Mar 2007 22:22:38 GMT, Gene Fuller wrote:
Walter Maxwell wrote: On 13 Mar 2007 14:19:12 -0700, "Cecil Moore" wrote: On Mar 12, 11:50 pm, Roy Lewallen wrote: The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. It also isn't true that there is no energy in the reflected wave, that such beliefs are gobbledegook, and that RF standing wave energy just sloshes around in a transmission line at less than light speed. To really understand what is going on, one has to understand superposition and interference between RF energy waves. You are on record as not caring to understand reflected energy. Please don't condemn those of us who are trying to understand. Did you guys on this thread know that it's been proven statistically that five out of four people have trouble with fractions? Walt,W2DU Walt, I didn't know that, but I'm dain bramaged. 73, Gene W4SZ Gene, are you aware that religious dyslecsics pray to their dog? Walt |
VSWR doesn't matter?
Walter Maxwell wrote in
: On Tue, 13 Mar 2007 22:28:02 GMT, Owen Duffy wrote: Walter Maxwell wrote in m: On 13 Mar 2007 14:19:12 -0700, "Cecil Moore" wrote: Did you guys on this thread know that it's been proven statistically that five out of four people have trouble with fractions? That's vulgar! The stat ement or the fractions? 5/4 |
VSWR doesn't matter?
"Walter Maxwell" wrote:
That was over 40 years ago, but I seem to remember that any discontinuity that resulted in a VSWR greater than 1.005:1 produced a ghost that could not be tolerated in the transmitted picture. I'm sure this is the magnitude of reflections Richard F. is referring to. _____________ Analog TV transmission is not quite that sensitive to VSWR, fortunately. Matti Siukola of the RCA Broadcast TV antenna group in Gibbsboro, NJ did some experimental work showing that a 1% reflection (1.02 VSWR) or less is unnoticeable to a critical observer, a 3% reflection (1.06 VSWR) is noticeable but tolerable, and a 5% reflection (about 1.1 VSWR) and above is objectionable. These values applied to the r-f spectrum from visual carrier (Fcv) to Fcv +2.5 MHz or so, and for transmission line lengths of 500 feet and more from the tx to the antenna. These parameters were measured using an r-f pulse at the visual carrier frequency having the transition times and r-f bandwidth corresponding to the maximum bandwidth limits of the TV channel, only. The more conventional broadband TDRs used a very short pulse with energy from DC to far beyond the limits of the TV channel. It could resolve small discontinuities along the transmission line, but many of them had no affect on the quality of the transmitted television image, as they were not present in the r-f spectrum of the TV signal. And the pulse return of a wideband TDR is extremely high from the TV transmit antenna itself, which is a DC short across the far end of the line. RF (RCA Broadcast Field Engineer, 1965-1980) |
VSWR doesn't matter?
Yes, there's no simple correlation between VSWR at a particular
frequency and the reflection coefficient seen by a step or pulse type TDR. As Richard pointed out, these TDRs have energy extending from DC (the step type) or some relatively low frequency (pulse type) to extremely high frequencies. The units I was involved in designing had a 3 dB frequency response and step content of up to 60 GHz. The phase has to be quite constant over this entire bandwidth, also, for good step fidelity. This very wide bandwidth is necessary to produce a fast step and step response (on the order of 10 - 15 ps for the units I worked with) in order to resolve anomalies which are physically very close together. It is possible to translate a TDR return into a spectrum of complex reflection coefficients (that is, a plot of reflection coefficient or SWR vs frequency), but this requires a Fourier transform. However, the energy content at any particular frequency is very small, so many repetitions have to be integrated to provide a usable signal/noise ratio. Likewise, a network analyzer can be swept over a very wide frequency range and S11 converted to a TDR waveform by use of an inverse Fourier transform. Because of the major difference in spectral content and methodology, a lot of care has to be taken in translating what you observe with a TDR system to what happens in a steady-state single frequency situation. For just one example, with a TDR you can easily tell the difference between a transmission line and load, and a lumped RC or RL circuit. You can also easily see the difference if you use a signal generator and make measurements at several different frequencies. Or if you watch the transient behavior as you turn the generator on and off (as in the frequency-limited TDR Richard described). But in a single frequency steady state system, you can't tell any difference whatsoever, provided that you choose the RC or RL to have the same terminal impedance as the original transmission line/load combination. Whatever effects are seen with all the "forward" and "reverse" power and energy bouncing around the line are seen exactly the same with no line at all and just an RC or RL as a load. So any explanation of the effects (such as the red plates of the mismatched transmitter posed earlier) has to be made without resorting to the bouncing energy. Why that seems so difficult for so many to do is a puzzle. Roy Lewallen, W7EL Richard Fry wrote: "Walter Maxwell" wrote: That was over 40 years ago, but I seem to remember that any discontinuity that resulted in a VSWR greater than 1.005:1 produced a ghost that could not be tolerated in the transmitted picture. I'm sure this is the magnitude of reflections Richard F. is referring to. _____________ Analog TV transmission is not quite that sensitive to VSWR, fortunately. Matti Siukola of the RCA Broadcast TV antenna group in Gibbsboro, NJ did some experimental work showing that a 1% reflection (1.02 VSWR) or less is unnoticeable to a critical observer, a 3% reflection (1.06 VSWR) is noticeable but tolerable, and a 5% reflection (about 1.1 VSWR) and above is objectionable. These values applied to the r-f spectrum from visual carrier (Fcv) to Fcv +2.5 MHz or so, and for transmission line lengths of 500 feet and more from the tx to the antenna. These parameters were measured using an r-f pulse at the visual carrier frequency having the transition times and r-f bandwidth corresponding to the maximum bandwidth limits of the TV channel, only. The more conventional broadband TDRs used a very short pulse with energy from DC to far beyond the limits of the TV channel. It could resolve small discontinuities along the transmission line, but many of them had no affect on the quality of the transmitted television image, as they were not present in the r-f spectrum of the TV signal. And the pulse return of a wideband TDR is extremely high from the TV transmit antenna itself, which is a DC short across the far end of the line. RF (RCA Broadcast Field Engineer, 1965-1980) |
VSWR doesn't matter?
"Richard Fry" wrote in message
... In analog TV transmit systems with a typical 500+ foot length transmission line from the tx to the antenna, a 5% reflection from a far-end mismatch can be quite visible, showing as a "ghost" image that is offset from the main image as related to the round-trip propagation time of the transmission line. I've noticed that, at least in this area, Fox 39 (WQRF) has a ghost of a few microseconds (I forget what exactly, I've calculated it before). Something like 500 feet, IIRC. Tim -- Deep Fryer: A very philosophical monk. Website @ http://webpages.charter.net/dawill/tmoranwms |
VSWR doesn't matter?
On Mar 13, 2:48 pm, Gene Fuller wrote:
No one denies the existence of reflections. But some people deny that there is any energy in the reflections - see below. :-) But a big argument is about the round-trip travel of energy in the steady-state. Some people seem to believe that energy continues to flow back and forth from one end of a (mismatched) transmission line to the other under steady-state conditions, even simultaneously traveling in both directions. (Passing like ships in the night?) Since energy is a scalar quantity, and any given joule is not distinguishable from another, it is not clear how the proponents keep track of the bookkeeping, but they muddle through somehow. Again Gene, to be able to prove your point, you need to present an example of a standing wave that exists without a forward traveling energy wave and a reverse traveling energy wave. You keep implying that is possible, but have presented no proof. Water is also a scalar. If you had one gallon per minute flowing into a barrel and two gallons per minute flowing out of the barrel, would you argue that there is no water flowing into the barrel and only one gallon of water flowing out of the barrel? Or would you say the *net* water flow is one barrel per minute out of the barrel? -- 73, Cecil, w5dxp.com |
VSWR doesn't matter?
On Mar 13, 9:27 pm, Walter Maxwell wrote:
That was over 40 years ago, but I seem to remember that any discontinuity that resulted in a VSWR greater than 1.005:1 produced a ghost that could not be tolerated in the transmitted picture. And of course, the same thing can happen in a simple system consisting of a TV source, a transmission line, and a mismatched load. TV ghosting can prove that the reflected traveling waves make multiple round trips to the load and back to the source, yet many continue to deny that proof. The best (copout) argument that I have heard against it is that, "That is not steady-state", and therefore doesn't count. :-) -- 73, Cecil, w5dxp.com |
VSWR doesn't matter?
On Mar 14, 6:53 am, Roy Lewallen wrote:
So any explanation of the effects (such as the red plates of the mismatched transmitter posed earlier) has to be made without resorting to the bouncing energy. That's simply not true. When the load is connected directly to the source, incident power is often still rejected, it just doesn't have very far to "bounce". And since it is internal to the source, the "bouncing" is difficult if not impossible to quantitize. If you hang a purly reactive load on a source output, it rejects all the the incident power just like it does at the end of a one- wavelength long transmission line. If we leave the source output terminals open, i.e. an infinite impedance, all of the source power is rejected at the source output terminal, i.e. there is a standing wave on the internal wire (often coax) connected to the source connector. In the same way that a source doesn't know whether it is connected to a transmission line or a lumped circuit, a purely reactive load doesn't know whether it is connected to a source or to a transmission line. Either way, it does an immediate rejection of incident power. Whether the load is connected to a transmission line or directly to a source, the reflection at the load is a same-cycle reflection. Since it happens at the load with a transmission line, why are you surprised that it happens at the load with a source? -- 73, Cecil, w5dxp.com |
VSWR doesn't matter?
On Wed, 14 Mar 2007 03:51:01 GMT, Owen Duffy wrote:
Walter Maxwell wrote in : On Tue, 13 Mar 2007 22:28:02 GMT, Owen Duffy wrote: Walter Maxwell wrote in : On 13 Mar 2007 14:19:12 -0700, "Cecil Moore" wrote: Did you guys on this thread know that it's been proven statistically that five out of four people have trouble with fractions? That's vulgar! The stat ement or the fractions? 5/4 Yer right, that's what I thought you mean't. Walt |
VSWR doesn't matter?
Cecil Moore wrote:
On Mar 13, 2:48 pm, Gene Fuller wrote: No one denies the existence of reflections. But some people deny that there is any energy in the reflections - see below. :-) But a big argument is about the round-trip travel of energy in the steady-state. Some people seem to believe that energy continues to flow back and forth from one end of a (mismatched) transmission line to the other under steady-state conditions, even simultaneously traveling in both directions. (Passing like ships in the night?) Since energy is a scalar quantity, and any given joule is not distinguishable from another, it is not clear how the proponents keep track of the bookkeeping, but they muddle through somehow. Again Gene, to be able to prove your point, you need to present an example of a standing wave that exists without a forward traveling energy wave and a reverse traveling energy wave. You keep implying that is possible, but have presented no proof. Au contraire, mon frere. You continue to claim that a standing wave MUST be made up of two traveling waves, but without proof. My contention is that this distinction is merely a matter of mathematical preference. When standing waves occur, there is absolutely no physical difference between the standing wave and its traveling wave constituents. If you find some physically significant difference due to considering traveling wave constituents rather than the standing wave, then you have made a mistake in your calculations. Water is also a scalar. If you had one gallon per minute flowing into a barrel and two gallons per minute flowing out of the barrel, would you argue that there is no water flowing into the barrel and only one gallon of water flowing out of the barrel? Or would you say the *net* water flow is one barrel per minute out of the barrel? This is totally irrelevant to the issue at hand. Try to keep on task. 73, Gene W4SZ |
VSWR doesn't matter?
billcalley wrote:
snip I've been reading the posts on this. One poster said this has been going on for twenty years! (For the other groups, this thread has life on rec.radio.amateur.antenna) It doesn't need to be so. First, there should be no doubt that reflected power on a transmission line is real. Sure, you can replace the line with a lump but that doesn't clear up the question for others. For the next two examples, see page 179: http://cp.literature.agilent.com/lit...4753-97015.pdf All examples assume the same impedance for source and line. First example, step into an open line with a Thevenin source. The energy is divided between the source and the line. Half the energy is moving down the line and when it returns changes the impedance the source sees to an open circuit. The energy does not flow back into the source, so, where did it go? It is stored in the capacitance of the line. Second example, step into a shorted line. When the energy returns the source now sees a short. The energy does not flow back into the source, so, where did it go? It is stored in the inductance of the line. So here are two examples where the energy sent down the line do not return to the source. Third example. Send a pulse down the line. The Thevenin voltage source will go to short, as it should, when the pulse falls. The pulse is reflected from either an open or a short at the end of the line. All the energy is dissipated in the source impedance when this pulse returns. That is where the energy goes. And it is obviously the _same_ energy created at the source. Sure, non of the cases above represent steady state AC. But they do show that energy may or may not be returned to the real component of the source. With the above in mind, it can be shown, (in some part II), that a real accounting of energy from source to load and back is possible. Equivalent circuits are just that, the trading of line for lump. But, and this is really important, the only reason the effective impedance at the input of a 50 ohm line is not 50 ohms is because of reflected energy. Best, Dan. |
VSWR doesn't matter?
"Richard Fry" wrote in :
In analog TV transmit systems with a typical 500+ foot length transmission line from the tx to the antenna, a 5% reflection from a far-end mismatch can be quite visible, showing as a "ghost" image that is offset from the main image as related to the round-trip propagation time of the transmission line. Richard, read this carefully, I do NOT disagree with what you have said in the paragraph above. For a ghost to be visible to viewers getting signal off air, there is more at play that a 5% reflection from a far end mismatch, the reflected wave is heading towards the transmitter, and needed to encounter another at least another reflection point with sufficiently high reflection coefficient that a sufficiently large, time delayed copy of the original modulated wave reaches the load (even if in turn part is reflected again). This second point of reflection could be a transmission line discontinuity, but it is most likely that it was that the tx end of the transmission line was not matched, that is that the tranmitter did not terminate the line with a near perfect match. It leaves the questions "are transmitters matched to Zo in real life, is matching an unavoidable consequence of optimising power output?". For avoidance of doubt, the discussion in this post is about the transient behaviour of the tranmission line and waves, it is relevant to long transmission lines with analogue TV modulation, but that doesn't mean it is necessarily important to other applications. Owen |
VSWR doesn't matter?
"Owen Duffy" wrote
This second point of reflection could be a transmission line discontinuity, but it is most likely that it was that the tx end of the transmission line was not matched, that is that the tranmitter did not terminate the line with a near perfect match. It leaves the questions "are transmitters matched to Zo in real life, is matching an unavoidable consequence of optimising power output?" ___________ Field experience in my tenure with RCA Broadcast when measuring and minimizing the "ghosting" propensities of commercial analog broadcast TV transmission systems showed/shows that a measured 5% or greater voltage reflection from the transmit antenna/input elbow complex, when sufficiently displaced in time from the main image, will result in an objectionable ghost image seen on an off-air TV set tuned to that station. That would not be true if such a nominal 5% far-end reflection from the antenna system essentially was absorbed by the TV transmitter (whether or not that turned the tube PA plates red, or caused the failure or other compromise of a solid-state PA). Maximizing the output power and efficiency of a broadcast r-f amplifier dictates that its effective output Z must be greatly different than the load Z it is expected to drive. In the case of broadcast transmitters, that source impedance is low (a few ohms), compared to the typical 50 or 75 ohm Zo of the load it is driving. And this it the reason that much of the voltage reflected from an antenna/far-end mismatch returns from the tx back to the antenna to be radiated, and so to produce the TV ghost image seen under those conditions. An equivalent effect is a reality in FM broadcasting, where a poor Z match of the antenna system across the FM channel bandwidth produces synchronous AM, and adds to stereo and SCA crosstalk. RF |
VSWR doesn't matter?
On Mar 14, 12:24 pm, Gene Fuller wrote:
Au contraire, mon frere. You continue to claim that a standing wave MUST be made up of two traveling waves, but without proof. On the contrary, I have presented at least three references as proof. If I remember correctly, it was Ramo, Whinnery, Hecht, and Balanis. You, OTOH, have presented none. My contention is that this distinction is merely a matter of mathematical preference. When standing waves occur, there is absolutely no physical difference between the standing wave and its traveling wave constituents. Obviously false as proven by the different equations for the two types of waves. We laid that one to rest long ago. In fact, it was you who pointed out that standing wave phase is completely different from traveling wave phase and cannot be used to measure phase shift through a coil. If I remember correctly, it was the difference between cos(x*wt) and cos(x)*cos(wt), i.e. *very* different. Water is also a scalar. If you had one gallon per minute flowing into a barrel and two gallons per minute flowing out of the barrel, would you argue that there is no water flowing into the barrel and only one gallon of water flowing out of the barrel? Or would you say the *net* water flow is one barrel per minute out of the barrel? This is totally irrelevant to the issue at hand. Try to keep on task. No, it is virtually identical to your argument. Saying it is "totally irrevelent" doesn't change anything. You are arguing that net energy transfer is primary and the underlying energy components are irrelevant if nonexistant. -- 73, Cecil, w5dxp.com |
VSWR doesn't matter?
On Mar 14, 5:36 pm, "Richard Fry" wrote:
And this it the reason that much of the voltage reflected from an antenna/far-end mismatch returns from the tx back to the antenna to be radiated, and so to produce the TV ghost image seen under those conditions. For whatever reason, ghosting of this sort proves that the reflected energy makes a round trip from the load to the source and back. The ghosting delay is exactly what a speed-of-light EM traveling wave would experience. In fact, multiple ghosting is caused by multiple reflections. -- 73, Cecil, w5dxp.com |
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