Home |
Search |
Today's Posts |
#29
![]() |
|||
|
|||
![]()
On Mon, 12 Mar 2007 13:37:00 -0400, "Jimmie D"
wrote: Your mistake is that you assume the output of the tx is 50 ohms, Hi Jimmie, At the risk of yet another, non-quantitative reply I will repeat: a question that has NEVER been answered by those who know what the transmitter output Z ISN'T: "What Z is it?" in the case you stated the transmitter must be matched to the impedance it sees looking into the transmission line. THAT is true, and it brings us to the point of all this energy sloshing around until the antenna finally dissipates it out into the Æther. It is the reflection off the mismatch of the tuner (the mismatch seen by the antenna as source to the line going back) that prevents energy from presenting any destructive results to the source - the whole point of using a tuner in the first place. 73's Richard Clark, KB7QHC |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Caculating VSWR from rho and rho from VSWR | Antenna | |||
Does it matter about packing? | Boatanchors | |||
VSWR Question | Antenna | |||
VSWR Fundamentals | CB | |||
WTB: V-UHF WATTMETER/ VSWR | Swap |