One word answers...
 

Owen Duffy wrote:

Dan Bloomquist wrote in news:4khKh.5006$ya1.3770
@news02.roc.ny:


Owen Duffy wrote:


Dan Bloomquist wrote in
:



Are the principles that apply to this example inconsistent with the
general case (eg dc, ac, transient, steady state etc)?

Yes.


I would have thought the answer was NO, the principles are *not*
inconsistent with the general case.

Hi Owen,
See the example I posted where a pulse is sent down the line. In that
case all the energy is dissipated in the source resistor.


Dan, I don't deny there may be cases where that may happen, but it is not
true that reflected power is necessarily dissipated (or partly
dissipated) in the equivalent source resistance.

And I answered accordingly when you asked the very question, I agreed
with you. And I showed just that in the step example of a previous post.

Owen

Best, Dan.

One word answers...
 

Cecil Moore wrote in news:KGhKh.7646$yW.5893
@newssvr11.news.prodigy.net:

Owen Duffy wrote:
You could devise an example with an AC source that had exactly the same
outcome, more complicated mathematics to solve it, but the exactly the
same outcome.

But the point is that I can devise an example with an
AC source that has the opposite outcome simply by using
a Norton equivalent source. When the reflection arrives,
the dissipation doubles.

Your Norton equivalent doesn't pretend to replicate my (real) source in
every way, it only pretends to supply the same voltage and current to its
load... and it does that.

Owen

One word answers...
 

Dan Bloomquist wrote in news:xYhKh.5014$ya1.2122
@news02.roc.ny:

But your underlying principle is that the source steps and doesn't
change. So any general case where the source is at some different level
is now not covered.

It semantics Dan, the excitation is part of the scenario or example, it is
not a principle of circuits or transmisssion lines.

Owen

One word answers...
 

Owen Duffy wrote:
I would have thought the answer was NO, the principles are *not*
inconsistent with the general case.

Even considering the dissipation within a Thevenin
equivalent circuit is inconsistent with any valid
significance according to Ramo and Whinnery.
--
73, Cecil, w5dxp.com

One word answers...
 

Owen Duffy wrote:

Dan Bloomquist wrote in news:xYhKh.5014$ya1.2122
@news02.roc.ny:


But your underlying principle is that the source steps and doesn't
change. So any general case where the source is at some different level
is now not covered.


It semantics Dan, the excitation is part of the scenario or example, it is
not a principle of circuits or transmisssion lines.

Like saying the impedance of a capacitor is the same no matter what the
frequency......

From here, I'll let you have the last word. I'm not into hand waving....

Owen

Best, Dan.

One word answers...
 

Dan Bloomquist wrote in
:

Owen Duffy wrote:

Dan Bloomquist wrote in
news:4khKh.5006$ya1.3770 @news02.roc.ny:


Owen Duffy wrote:


Dan Bloomquist wrote in
:



Are the principles that apply to this example inconsistent with
the general case (eg dc, ac, transient, steady state etc)?

Yes.


I would have thought the answer was NO, the principles are *not*
inconsistent with the general case.

Hi Owen,
See the example I posted where a pulse is sent down the line. In that
case all the energy is dissipated in the source resistor.


Dan, I don't deny there may be cases where that may happen, but it is
not true that reflected power is necessarily dissipated (or partly
dissipated) in the equivalent source resistance.

And I answered accordingly when you asked the very question, I agreed
with you. And I showed just that in the step example of a previous
post.


Dan we are agreed!

My conclusion is that the view put by some that reflected power is
(necessarily) fully or partly dissipated in the PA equivalent source
resistance, (possibly overheating the PA,) is a simplistic view, the
explanation doesn't apply in general and although apparently appealing,
it is wrong.

Owen

One word answers...
 

Owen Duffy wrote:
Dan, I don't deny there may be cases where that may happen, but it is not
true that reflected power is necessarily dissipated (or partly
dissipated) in the equivalent source resistance.

The question is whether reflected power is ever dissipated
in the source. I can come up with a black box source that
dissipates 100% of the reflected power. All it takes is
a circulator and a load resistor. How does your DC
principles handle a circulator?
--
73, Cecil, w5dxp.com

One word answers...
 

Owen Duffy wrote:
Your Norton equivalent doesn't pretend to replicate my (real) source in
every way, ...

I thought we were discussing general principles, not
replicating a special case example in every way.
--
73, Cecil, w5dxp.com

One word answers...
 

Owen Duffy wrote:
My conclusion is that the view put by some that reflected power is
(necessarily) fully or partly dissipated in the PA equivalent source
resistance, (possibly overheating the PA,) is a simplistic view, the
explanation doesn't apply in general and although apparently appealing,
it is wrong.

The question is: Does any reflected joules/second ever
get dissipated in the PA? To ascertain the answer, one
must calculate the interference patterns in both directions.
If the energy is not dissipated anywhere else, it is
dissipated in the PA.
--
73, Cecil, w5dxp.com

One word answers...
 

Owen Duffy wrote in
:

....
When the switch is closed, current flows into the line. Until t=2T
seconds, the current If that flows into the line equals 100V/(100+100
ohms) = 0.5A, during which time the resistor dissipates heat at the
rate of I^2*R = 100W. The voltage of the wave Vf travelling from the
source is I*Zo = 50V. This situation is constant until t=2T seconds.
....

David Ryeburn is awake, even if I wasn't at 5.38 when I wrote this.

should be ...during which time the resistor dissipates heat at the
rate of I^2*R = 25W...

It doesn't materially change anything, but I messed up!

Owen