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Jim Kelley wrote in news:eve92l$mip$1
@news.service.uci.edu: K7ITM wrote: "Let's see... e=m*c^2. Now what c is that? I think I know which one, and as far as I know there hasn't been a dispute about that on RRAA. The question posed on the newsgroup, and the one which still seems to be a point of contention is which one should go in *this* equation: f = c / w I maintain the answer is still - it depends on the medium. Jim, I am not a physicist... but I recall when introduced to e=m*c^2 at high school, that "c" was defined as "the velocity of light in a vacuum". If the "in a vacuum" qualification was unnecessary, if wasn't relevant, I wonder why they complicated and restricted the definition? I am with you (until someone presents a convincing argument otherwise). This leaves all those books, software etc giving a value for "c" as not necessarily in need of revision. Owen |
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