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On 28 jul, 00:33, "
wrote: I am curious as to whether RF exposure concerns are greater for a small transmitting loop [like the MFJ tuned loop] compared to a dipole radiating the same power. It would seem that close to the loop, the RF power density may be greater [than it would be at the same distance from the dipole apex] since the radiating volume is smaller. Can I just assume that the power is evenly distributed on the surface of a sphere having a radius equal to my distance from the loop antenna, calculate the power density on the sphere surface, and use that number for evaluation - or are there some near-field considerations not captured using this approach? Thanks, -JJ Hello, When you are close to the loop, let say less then 0.1 lambda, the exposure for the loop will be significantly higher with respect to the full size HW dipole. The reason for that is that at short distance the reactive fields dominate (that are the fields that obey "DC/lumped AC" calculus). While the radiation H field has 1/r relation, the reactive field has a relation between 1/r^2 to 1/r^3. So you cannot calculate the field strength (both H and E) based on the 1/r relation. Some years ago I did a calculation on the H field from a loop with D=3m, radiation efficiency 22%, input power 50W (so radiated power is just 11 W), 3.6 MHz. The H-field at 2m would be about 1.33A/m, while the ICNIRP reference level for the general public is 0.22A/m. At 4.5m from the loop, the field drops to 0.2A/m The reason for the strong local magnetic field is the high Q factor of the loop (about 1500), while a HW dipole will have a Q of about 12. The same radiated power for a HW fipole would result in a about 0.5A feed current. This would result in about 0.04A/m at 2 m distance from the center of the dipole. At the higher HF bands, the levels for a loop and HW dipole will come closer as the reactive fields vanish faster with respect to distance and (with same size of loop), the Q-factor decreases because of higher radiation resistance (hence lower circulating current in the loop). Best regards, Wim PA3DJS www.tetech.nl |
#2
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Thanks all.
Roy, I was not implying that I believe one can assume that the power is from a point source and one can consider the power density passing through a sphere to determine RF safety. I was looking for some guidance as to how to determine a "safe" distance from a small tuned loop assuming a particular frequency and power. It appears that the simple sphere approach works reasonably well beyond a wavelength or so, and may be an acceptable first-order approximation at 1/2 wavelength [from a small loop]. -JJ |
#3
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#4
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Roy Lewallen wrote in news:13an54e9keccc59
@corp.supernews.com: wrote: Thanks all. There's no distinct boundary between the near and far field, but at a wavelength, or even a half wavelength, you're pretty much in the far field of a small antenna. So far field approximations such as the one involving power density on the surface of a sphere are quite reasonable at those distances. Some years ago, I implemented an online calculator based on the method proposed by our communications regulator (then, the ACA). The calculator includes several overseas SAR levels, including that later struck by our radiation regulator (ARPANSA). The key difference between the model used and todays regulatory environment in Australia is that the modelled results are not acceptable below 10MHz. If readers want to play with the model, it is at http://www.vk1od.net/tl/emrcc.php . (The model assumes the antenna is 100% efficient, it it isn't, then adjust the input power to the expected radiated power.) Is assessing the radiation hazard of the loop, the mode is very important to the outcome, and for reasons I don't understand, the FCC, then apparently the rest of the world, recommended a very high average/peak ratio for SSB telephony. If one was really concerned about the loop, a simple measurement instrument could be made from a small loop terminated in a resistive load and detector with a small battery powered LCD panel meter. The loop Antenna Factor can be determined from an NEC model, the detector can be calibrated on a signal generator, and the whole lot then calibrated in mV DC to Field Strength in dBuV/m. I have done this for a 0.6m square loop and the measurement results at locations in the induction and radiation near field areas around a 20m dipole reconciled reasonably with expectations based on the calculator above understanding that the calculator's method is conservative. Owen |
#6
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wrote:
I am curious as to whether RF exposure concerns are greater for a small transmitting loop [like the MFJ tuned loop] compared to a dipole radiating the same power. yes. It would seem that close to the loop, the RF power density may be greater [than it would be at the same distance from the dipole apex] since the radiating volume is smaller. Can I just assume that the power is evenly distributed on the surface of a sphere having a radius equal to my distance from the loop antenna, calculate the power density on the sphere surface, and use that number for evaluation No - or are there some near-field considerations not captured using this approach? yes The big problem is this: a small loop stores a lot of energy in the fields around the loop (if the loop has a Q of, say, 100), and you're radiating 100 Watts, that implies that there is 10kW circulating in the loop between the loop itself and the tuning capacitor. The energy moves between the magnetic field of the loop and the E field of the capacitor every 1/4 cycle. A particularly egregious example is the tabletop small loop shown in QST a few months ago. The Operator is sitting about 1 meter from the loop, and unless he's running very, very low power, he's exceeding the RF exposure limit by quite a bit. The worst thing is that the article makes the assertion that there's a field null along the axis of the loop, which is true in the far field, but certainly not true in the near field. As a practical matter, the field is pretty uniform (within a factor of 2) within a couple loop diameters. Some useful practical numbers: For a 1 meter loop, with a current of 10 Amps, the H field at 2 meters away (along the axis, normal to the plane of the loop) is about .16 A/m (or right at the Maximum Permissible Exposure (MPE) for controlled environments at 30MHz, 100% duty factor) In the plane of the loop, you get down to that level at a distance of about 1.6 meters. Here's the letter I sent to QST about it: http://home.earthlink.net/%7Ew6rmk/qstrfsafety.htm Jim, W6RMK |
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