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Photon vs Wave emissions from antennas?
On 5 Sep, 04:33, Denny wrote:
On the other hand, the absence of porous plates in operating radiometers tends to cast some doubt on your claim that the plates must be porous. Not "my claim," my report. The claim they must be porous arrives through the math necessary to balance the kinetic forces. Again, which radiometer? If you are arguing a "perfect" vacuum, then like a free lunch, I would agree there's no such thing. The Crookes radiometer requires a partial atmosphere to work, other radiometers work quite fine with much less. Depends entirely on what one intends to measure. Despite the photon torpedoes fired at me, I have not seen a convincing physics experiment that deflates my previous arguement... Where the F=MA arguement fails in a radiometer is that the photons impact both sides of the paddles leaving a zero net force for rotation... The fact that a Crookes Radiometer requires an atmosphere is proof of its mode of operation. The fact that it has to be a partial vacuum further proves how it operates (more air density means too much air drag to allow rotation by the weak local differential pressure across the paddle)... Those who reject local differential pressure changes due to local heating by claiming the pressure in the bulb is static ignore the factor of time in molecular exchange of thermal energy gains... Carrying their argument to the logical end means sun heating cannot cause the winds to ever blow across the ground because the net air pressure of Terra is static... denny It's 10PM somewhere, have you hugged your radio today? Perhaps people should take look at other things that creat radiation! For instance the explosion from a energy container such as a transformer feeding a spark plug. The frequency band is widespread leaving time varient current, capacitance and inductance and neglecting resonant lengths. Can a capacitance store a particle or can it blow away a particle formed on its own material?Time varient obviously dependes on the size of the capacitor therefore the time current is applied to the capacitor is irrelevent. I have left off references to icecream, snorkels e.t.c. even tho apparently they are necessary. Art |
Photon vs Wave emissions from antennas?
Denny wrote: On the other hand, the absence of porous plates in operating radiometers tends to cast some doubt on your claim that the plates must be porous. Not "my claim," my report. The claim they must be porous arrives through the math necessary to balance the kinetic forces. Again, which radiometer? If you are arguing a "perfect" vacuum, then like a free lunch, I would agree there's no such thing. The Crookes radiometer requires a partial atmosphere to work, other radiometers work quite fine with much less. Depends entirely on what one intends to measure. Despite the photon torpedoes fired at me, I have not seen a convincing physics experiment that deflates my previous arguement... Where the F=MA arguement fails in a radiometer is that the photons impact both sides of the paddles leaving a zero net force for rotation... The fact that a Crookes Radiometer requires an atmosphere is proof of its mode of operation. The fact that it has to be a partial vacuum further proves how it operates (more air density means too much air drag to allow rotation by the weak local differential pressure across the paddle)... Those who reject local differential pressure changes due to local heating by claiming the pressure in the bulb is static ignore the factor of time in molecular exchange of thermal energy gains... Carrying their argument to the logical end means sun heating cannot cause the winds to ever blow across the ground because the net air pressure of Terra is static... denny It's 10PM somewhere, have you hugged your radio today? Hi Denny - The thing that seems to have certain people confused here is the fact that, with regard to radiometers, there are two different effects at work. Radiation pressure is in fact quite measurable, but is an orders of magnitude smaller force than the thermal/molecular effect that toy store radiometers demonstrate. Radiation pressure is such a small effect that it cannot be observed unless the vessel is first evacuated to an ultra high vacuum. Ordinarily, one would use a torsion or micro balance to measure this effect. But in a radiometer type arrangement, the vanes rotate in a direction away from the more reflective side because the change in momentum is twice as high for a reflected photon as it is for an absorbed photon. But in the case of the thermal, partially evacuated (toy store) radiometer, the black side of the vanes absorbs more thermal energy and is therefore hotter than the white side which absorbs less and reflects more energy. Gas molecules which encounter the vanes in a partially evacuated radiometer are ejected more energetically from the hotter side than from the cooler side thus creating a net force in the direction away from the black (less reflective) side. This is as you described. 73, ac6xg |
Photon vs Wave emissions from antennas?
On Wed, 05 Sep 2007 04:33:11 -0700, Denny wrote:
Despite the photon torpedoes fired at me, I have not seen a convincing physics experiment that deflates my previous arguement... Hi Denny, You need a better reading list. Researching the historical names offered would be a start. Where the F=MA arguement fails in a radiometer is that the photons impact both sides of the paddles leaving a zero net force for rotation... Well, the Newtonian math certainly fails (as does the Quantum math); but not because photons hit (more properly absorbed by) both vanes equally for a net zero force (an appeal to F=MA already dismissed). If you observe the Crookes radiometer (and its brethren), it has distinct differences in reflection/absorption characteristics which impart a very considerable differential in the net force; which, again, do not balance with the energy applied. This is not to dismiss the obvious reaction, however; but no one here has offered any quantifiable forces other than myself. The fact that a Crookes Radiometer requires an atmosphere is proof of its mode of operation. The fact that it has to be a partial vacuum further proves how it operates (more air density means too much air drag to allow rotation by the weak local differential pressure across the paddle)... Unfortunately (and as mentioned several many times), the so-called differential in pressure does not balance with the applied energy. Even if it did, it would require a porous vane to make it work (another negative hit). It would be useful if someone could offer even one line of quantifiable data to support ANYTHING. So much of this is testimonial that this should be called rec.radio.tent.meeting given the general inclination to veer from facts towards faith. Those who reject local differential pressure changes due to local heating by claiming the pressure in the bulb is static ignore the factor of time in molecular exchange of thermal energy gains... Carrying their argument to the logical end means sun heating cannot cause the winds to ever blow across the ground because the net air pressure of Terra is static... Hmmm, who could those heathens be? Perhaps the scurvy Nichols and Tear whose radiometer works so well in a more complete Vacuum? 73's Richard Clark, KB7QHC |
Photon vs Wave emissions from antennas?
Richard Clark wrote:
On Wed, 05 Sep 2007 00:04:23 -0000, Jim Kelley wrote: Richard Clark wrote: The description you offer requires a porous plate which is absent in every radiometer that has come down the pike On the other hand, the absence of porous plates in operating radiometers tends to cast some doubt on your claim that the plates must be porous. Not "my claim," my report. So be it. The absence of porous plates in operating radiometers tends to cast doubt on your report that the plates must be porous. The claim they must be porous arrives through the math necessary to balance the kinetic forces. But a balance of forces would result in the absence of an observable effect. An imbalance in forces is required in order to produce movement. Now, if we simply move to another radiometer (Nichols, Tear, Hull, and Webb already recited) without that partial vacuum, the vanes still move, and expressely by Radiation Pressure. By a different mechanism and in the opposite direction, yes. In essence, these instruments indicate, not measure. A description which applies beautifully to power meters as well, don't you agree? ;-) The coy context of the thread was measuring the mass of a Photon. Absolutely no SI Units have been named or any quantitative values offered (the rather standard omission from claims made here). However, feel free to introduce your own side thread's goal or even offer a guess (your own quatitative value for the mass). I'd like to offer m = E/c^2 as a guess. 73, ac6xg |
Photon vs Wave emissions from antennas?
On Wed, 05 Sep 2007 17:02:38 -0700, Jim Kelley
wrote: Not "my claim," my report. So be it. The absence of porous plates in operating radiometers tends to cast doubt on your report that the plates must be porous. Hi Jim, You should distinguish between reporting, claims, and what you see. The point about being porous is to substantiate the expectation of explaining the full energy budget (and specifically for the Crookes radiometer). I don't know how many times I have to emphasize this, but NO METHOD achieves that balance. The claim they must be porous arrives through the math necessary to balance the kinetic forces. But a balance of forces would result in the absence of an observable effect. An imbalance in forces is required in order to produce movement. The balance is in the energy applied and the energy expended. You put an HP into a car, and it will accelerate 550 foot-pounds/sec. You put x photons into ANY radiometer, and the change in inertia WILL NOT balance. [This is why I expressed my question in Newtonian terms for the benefit of the twins who are so devoted to the master (that they are wholly lost in a simple 2 variable computation). The difference between that computation and performance is extreme. What is more compelling, is that it is quite a departure from what Quantum Mechanics would predict. NO METHOD achieves that balance.] Now, if we simply move to another radiometer (Nichols, Tear, Hull, and Webb already recited) without that partial vacuum, the vanes still move, and expressely by Radiation Pressure. By a different mechanism and in the opposite direction, yes. In essence, these instruments indicate, not measure. A description which applies beautifully to power meters as well, don't you agree? ;-) No. Power meters to even uncommonly high accuracy still conform to Newtonian mechanics. The coy context of the thread was measuring the mass of a Photon. Absolutely no SI Units have been named or any quantitative values offered (the rather standard omission from claims made here). However, feel free to introduce your own side thread's goal or even offer a guess (your own quatitative value for the mass). I'd like to offer m = E/c^2 as a guess. The photo-electron appears to even depart from that. More to follow. 73's Richard Clark, KB7QHC |
Photon vs Wave emissions from antennas?
John Smith wrote:
Why has ether become synonymous with "kook?" From Wikipedia: "Einstein in later years proposed calling empty space equipped with gravitational and electromagnetic fields the "ether", whereby, however, this word is not to denote a substance with its traditional attributes. Thus, in the "ether" there are to be no determinable points, and it is meaningless to speak of motion relative to the "ether." Such a use of the word "ether" is of course admissible, and when once it has been sanctioned by usage in this way, probably quite convenient." Ives was the first to positively measure the effect of speed on clock rates. He wrote in 1940 in a paper in Science: "I have considered the popular claim that the ether has been "abolished" [...]. Reverting to experimental findings I have reviewed the experiment of Sagnac, having in mind the claim that the ether can not be detected experimentally. I have asserted that, in the light of the experimentally found variation of clock rate with motion, this experiment does detect the ether." -- 73, Cecil http://www.w5dxp.com |
Photon vs Wave emissions from antennas?
I have asserted that, in the light of the experimentally
found variation of clock rate with motion, this experiment does detect the ether." -- 73, Cecil http://www.w5dxp.com Me neither... The old bull dozer refused to start and I hunted all over the place for a can of ether... Didn't detect one either... Mind you it was 92 degrees yesterday and rooting around through the toolshed with the sun beating on the steel roof for ether was no picnic... I doubt that Michaelson and Morley worked up that much sweat looking for it... denny |
Photon vs Wave emissions from antennas?
Cecil Moore wrote:
... "I have considered the popular claim that the ether has been "abolished" [...]. Reverting to experimental findings I have reviewed the experiment of Sagnac, having in mind the claim that the ether can not be detected experimentally. I have asserted that, in the light of the experimentally found variation of clock rate with motion, this experiment does detect the ether." Yes, that annoying fact, clocks slow when you place 'em on jet aircraft, refuel the aircraft in flight, and make a few trips around the circumference of the earth. In my present state of thought, this directly relates to the speed of light; further, I suspect, the ether is responsible in establishing the, seeming, barrier of the speed of light. As you approach the speed of light, things are not linear, you must apply magnitudes more energy without corresponding gains in speed. And, although I tend to believe the math which "proves" this, it ends up just another thing I fail to completely be able to wrap my mind around. But, it seems at the speed of light, traversing the ether with matter offers such a resistance to the speed of matter, any further increases of speed are impossible--no matter the amount of expenditure in energy ... At this point, I am just happy to be in the company of others who will, at least, accept the possibility of the ether, and the possibility it can/does have real effects/affects on our material world. Regards, JS |
Photon vs Wave emissions from antennas?
Denny wrote:
... Me neither... The old bull dozer refused to start and I hunted all over the place for a can of ether... Didn't detect one either... Mind you it was 92 degrees yesterday and rooting around through the toolshed with the sun beating on the steel roof for ether was no picnic... I doubt that Michaelson and Morley worked up that much sweat looking for it... denny Denny: If you should be fortunate enough to find/purchase a can of that "ether", be careful not to breath the vapors--they may have a detrimental effect on ones cognitive abilities! :-) Regards, JS |
Photon vs Wave emissions from antennas?
Richard Clark wrote:
In essence, these instruments indicate, not measure. A description which applies beautifully to power meters as well, don't you agree? ;-) No. Power meters to even uncommonly high accuracy still conform to Newtonian mechanics. So it is because of Newtonian mechanics that an RF power meter is actually measuring power rather than indicating power. What is the value gained by this strain on credulity? The coy context of the thread was measuring the mass of a Photon. Absolutely no SI Units have been named or any quantitative values offered (the rather standard omission from claims made here). However, feel free to introduce your own side thread's goal or even offer a guess (your own quatitative value for the mass). I'd like to offer m = E/c^2 as a guess. The photo-electron appears to even depart from that. I've often wondered how one might go about recognizing a photo-electron out of a group of other, less prominent electrons? :-) 73, ac6xg |
Photon vs Wave emissions from antennas?
On Thu, 06 Sep 2007 09:54:43 -0700, Jim Kelley
wrote: So it is because of Newtonian mechanics that an RF power meter is actually measuring power rather than indicating power. What is the value gained by this strain on credulity? Hi Jim, Sounds like you should talk to your Chaplain about these issues. I've often wondered how one might go about recognizing a photo-electron out of a group of other, less prominent electrons? :-) It is like complaining the Nobel winners are indistinguishable from the crowd in the ceremonial hall. Prominent is key, certainly. How many electrons can you motivate to leap over the barrier of the work function of a metal? In Physics, a simple population count would reveal the prominence. Tubes usually have to boil them off incandescent filaments, or rip them out of their matrix with 10's of kilovolts of nearby potential. Hi All, Let's examine those last two motivators. Photons hardly raise the temperature of a metal vane to, what, 1000 degrees? And as for kilovolts of excitation, how much potential is there in a photon? Well, too often this group starves for information in response when I toss these questions out - too technical for this forum of light nappers I suppose. Too often, these threads turn into strings of slaps at the snooze button (and "ether" has been the biggest snooze of them all - self-fulfilling if one were to enlarge on the term's rhetorical baggage). Place a vane coated with sodium into an evacuated quartz tube. Illuminate the sodium coated plate such that it absorbs one microwatt per square meter. This is sufficient power to evoke the photo-electric response (hopefully this is not too arcane a term). The bulk of absorption will occur within a layer depth of 10 atoms. Sodium, one atom thick, measures out to 10^19 atoms per square meter, so we are absorbing the power throughout 10^20 atoms. Hence each atom is illuminated with 10^-26 Watts OR 10^-7 eV/sec. (eV: electron Volt, perhaps another prominence hard to embrace.) The conundrum (sorry for hard words - but even those who use English as a second language manage to cope) here is that to build a potential to at least 1eV (and usually 3 to 5 times that for many metals) would take nearly a year for a single electron to leap the Work Function barrier. In reality, it occurs in less than a nanosecond. It would be interesting to see Arthur's Newtonian math achieving a 10,000,000,000,000,000:1 leap of faith. False idolatry in place of work is like putting a lottery ticket into the collection plate. Strip away my stylistic excess and the facts fill maybe three sentences. Still, I am four sentences ahead of the rest. ;-) 73's Richard Clark, KB7QHC |
Photon vs Wave emissions from antennas?
In my present state of thought, this directly relates to the speed of light; further, I suspect, the ether is responsible in establishing the, seeming, barrier of the speed of light. As you approach the speed of light, things are not linear, you must apply magnitudes more energy is point, I am just happy to be in the company of others who will, at least, accept the possibility of the ether, and the possibility it can/does have real effects/affects on our material world. Regards, JS John The universe is made of many things. Most all are held within the confines of a gravitational force. There are many of these gravitational orbits but one thing is for sure is all these individual orbits or gravitational forces are in equilibrium with each other even to the magnetude of including all the stars and the galaxies. All mass known is in the final borders of the total equilibrium outside of which there is no mass or external forces which has been named the AETHER. Equilibrium of moving parts means changes of the shape of the extreme borders within equilibrium is held .When the equilibrium boundaries change the shape of the eather also must change and eventually must be included in an equilibrium of sorts Art |
Photon vs Wave emissions from antennas?
On Sep 5, 5:02 pm, Jim Kelley wrote:
.... I'd like to offer m = E/c^2 as a guess. 73, ac6xg A link is worth a thousand words (perhaps 10k-100k of Richard's...): http://www.newton.dep.anl.gov/askasc...0/phy00332.htm (in particular the first paragraph of the second response). |
Photon vs Wave emissions from antennas?
art wrote:
... AETHER. Equilibrium of moving parts means changes of the shape of the extreme borders within equilibrium is held .When the equilibrium boundaries change the shape of the eather also must change and eventually must be included in an equilibrium of sorts Art Equilibrium is a poor choice of words when you encompasses the ether, in my humble opinion. You are attempting to give known states/laws/rules/properties to a material (ether) which Einstein himself tells you NOT to--Einstein implies a proper model for the ether was not available during his lifetime, I do not see where that has changed, to date. Indeed, in pure form, equilibrium implies a static state--anything more implies an over unity condition (perpetual motion), the forces which drive the motion and birth of stars-planets and the expanding of the universe is/are NOT in a static state, in six billion years a static state has not come into being, in another six billion years it is not expected for it to come into stasis--only if this will remain true "forever" remains a question. As long as matter exists, the above will, seemingly, remain true. A state of "un-equilibrium" exists in the sheer fact that all matter has been ripped from the very fabric of the ether--this I suspect is a most unnatural state of affairs (no one can be sure, for sure--and we only have one example to view! Other explanations exist ... ) ... we will know when we have "seen" the ether and know of the laws/rules which govern it and its' un-ponder-able properties. Regards, JS |
Photon vs Wave emissions from antennas?
Richard Clark wrote: Still, I am four sentences ahead of the rest. ;-) We now learn of the value in strained credulity. :-) jk |
Photon vs Wave emissions from antennas?
On Thu, 06 Sep 2007 12:47:46 -0700, K7ITM wrote:
On Sep 5, 5:02 pm, Jim Kelley wrote: ... I'd like to offer m = E/c^2 as a guess. 73, ac6xg A link is worth a thousand words (perhaps 10k-100k of Richard's...): http://www.newton.dep.anl.gov/askasc...0/phy00332.htm (in particular the first paragraph of the second response). Hi Tom, Your link is over valued (there is no second response), but it maintains the standard of excellence here in the tradition of 10k-100k more words than quantifiables - and someone else doing the work. Care to walk us through your proffered math? Well, I doubt it. Others may be interested in the curious form of argument offered to a 15 year old however. "For a particle with no mass, the relation reduces to E=pc." The long and short of it is that there is no discussion of mass for a photon (it is simply defined not to exist) and instead there is a shuffle of math that youngster must imagine this bozo is pulling the wool over his eyes through substituting p for Planck's constant h, and c for Planck's energy formula variable v. This wool pulling is another favorite past time here too. Of course, there may be other meanings behind "E=pc." but in the model of thorough work, the description of terms is sadly poor. The typical legacy of offering links. It has all the appeal of a Physicist's joke: "How many milliseconds does it take to do a 5 minute car wash?" 73's Richard Clark, KB7QHC |
Photon vs Wave emissions from antennas?
On Sep 6, 2:53 pm, Richard Clark wrote:
....(there is no second response)... Pity you have so much trouble reading... |
Photon vs Wave emissions from antennas?
Richard Clark wrote:
On Thu, 06 Sep 2007 12:47:46 -0700, K7ITM wrote: On Sep 5, 5:02 pm, Jim Kelley wrote: ... I'd like to offer m = E/c^2 as a guess. 73, ac6xg "E=pc." Yes, and p=mv, so when v=c as is true for photons, and we substitute mc for p in the equation above and then solve for m (the mass of a photon was the original question), we're back at the equation offered previously. But we usually relate more directly to the frequency (or wavelength) of the photon rather than its energy or momentum, so in such a case E=h*nu would provide a more direct route to its mass equivalent. ac6xg |
Photon vs Wave emissions from antennas?
John Smith wrote:
Richard Clark wrote: On Mon, 03 Sep 2007 10:35:50 -0400, Ed Cregger wrote: And who was this Schroedinger guy anyway? He was Lucia's boyfriend who played the Pianoforte. Their lives were humorously chronicled in an illustrated fiction called "Goober Peas." Continuing themes of their friends and relatives populated this series with such stories as the "strange attractors" of kites and trees, or the wave function of a football that couldn't be kicked. The illustrator was purported to be one Eisenstein, but this was later found to be erroneously inferred from earlier cinematic work with similar themes found in "Aleksandr Nevskiy." 73's Richard Clark, KB7QHC Interesting. Did it/he/they have anything to say about visions of silvery and copper colored fingers plucking the harp strings of the seemingly invisible ether? Regards, JS The main character in Woody Allen's "Annie Hall" was based upon ether. |
Photon vs Wave emissions from antennas?
On 6 Sep, 13:14, John Smith wrote:
art wrote: ... AETHER. Equilibrium of moving parts means changes of the shape of the extreme borders within equilibrium is held .When the equilibrium boundaries change the shape of the eather also must change and eventually must be included in an equilibrium of sorts Art Equilibrium is a poor choice of words when you encompasses the ether, in my humble opinion. You are attempting to give known states/laws/rules/properties to a material (ether) which Einstein himself tells you NOT to--Einstein implies a proper model for the ether was not available during his lifetime, I do not see where that has changed, to date. Indeed, in pure form, equilibrium implies a static state--anything more implies an over unity condition (perpetual motion), the forces which drive the motion and birth of stars-planets and the expanding of the universe is/are NOT in a static state, in six billion years a static state has not come into being, in another six billion years it is not expected for it to come into stasis--only if this will remain true "forever" remains a question. As long as matter exists, the above will, seemingly, remain true. A state of "un-equilibrium" exists in the sheer fact that all matter has been ripped from the very fabric of the ether--this I suspect is a most unnatural state of affairs (no one can be sure, for sure--and we only have one example to view! Other explanations exist ... ) ... we will know when we have "seen" the ether and know of the laws/rules which govern it and its' un-ponder-able properties. Regards, JS I believe we view aether differently as well as the term equilibrium. The later describes what is balanced within a border and where momement of the interned is reacted by countermovement in the shape of the border. This is why I keep comming back to Gauss and his description of static particles. True the border varies in shape exposing cracks or deformation of its borders where particles can escape before equilibrium is reformed as internal forces or orbits correct their positions so the retaining border becomes of uniform strength again. If the innards were not mobile and adaptive to change then once the border was fractured it could not adapt and heal itself. This bordcer in itself is balanced as part of other gravitational borders all of which are expanding and regenerating into different border and thus expanding into the aether which has nothing to provide resistance. The main point is that all that is contained must have movement so when the balanc eof equilibrium is momentarily broken it is in a position to adapt its internal movements to attain equilibrium again. How else can one adapt to escaping particles and collisions if there were not constant movementof that which holds together because of equilibrium. True Richard will take exception to this as he views himself as Einsteins successor and is determined to block in his own eyes everything except what spills from his own mouth with the suggestion that he knows all but has not yet decided to disclose it. The same with respect to his credentials that allows him to judge thoughts of others. Art |
Photon vs Wave emissions from antennas?
art wrote:
... Art Art: You seek to answer the unanswerable, you seek to explain the unexplainable ... this is far from "being wrong." It simply proves that our knowledge is incomplete, at present. This is something we all hope to cure in the future. Now, we simply debate the different explanations which exist. Magnetic fields certainly play a prominent part in manipulations of EM waves/particles, and the opposite ... what is going on precisely is up for grabs, again, in my humble opinion. The fact is, although I think we can see the stress lines in the ether with the simple iron filings, paper and magnet, we know nothing about it--indeed, the "proof of its' existence" I am citing might have yet another explanation. Indeed, at this point, ether almost requires a "leap of faith" such as necessary with a belief in God. By sheer definition we cannot even devise a bottle to hold a sample of ether. However, cowards will run from the unknown, brave men will sit and discuss how to attempt to prove it, one way or another. A system with equilibrium will, at some point, cease movement, unless there is an input of energy from an external source, this energy might appear cloaked in many forms. Can we at least agree upon this single point, first? Regards, JS |
Photon vs Wave emissions from antennas?
art wrote:
... I believe we view aether differently as well as the term equilibrium. ... Art Art: I found an interesting fellow on the net, here is a .pdf of his free ebook: (chapter 8 I found very interesting) http://www.teslaphysics.com/files/Detection.pdf If you would like to read it in .html instead: http://www.teslaphysics.com/ Look near the bottom of the page for the book, but this page itself is interesting. He has done some experimenting and claims to have detected the ether. He cites another fellows experiments which his own experiments followed. Beware and be warned, his thinking challenges Einsteins' own ... Regards, JS |
Photon vs Wave emissions from antennas?
On Thu, 06 Sep 2007 16:07:09 -0700, Jim Kelley
wrote: Richard Clark wrote: On Thu, 06 Sep 2007 12:47:46 -0700, K7ITM wrote: On Sep 5, 5:02 pm, Jim Kelley wrote: ... I'd like to offer m = E/c^2 as a guess. 73, ac6xg "E=pc." Yes, and p=mv, Hi Jim, Tom opines about my reading, but it is about the writing from the good doctor that we find (in regard to your snippet above): "we find that the momentum relation p=mv is only an approximation. It is only correct when speed (v) is much smaller than the speed of light (c). which distinctly contradicts your tie-in: so when v=c as is true for photons, and we substitute mc for p in the equation above and then solve for m (the mass of a photon was the original question), we're back at the equation offered previously. The circularity of Dr. Ken Mellendorf's foggy writing might suggest it, if it weren't otherwise nipped in the bud by the bald statement. "For a particle with no mass, the relation reduces to E=pc. This works for a photon." Hence the proximity of this to p=mv is textual, not factual. What is the term p? Could it be (p)hoton? I've speculated about Planck's constant (which you comment upon, below), but I find it very sloppy writing for Dr. Mellendorf to wander into his own naming conventions. Migrating through E = mc˛ something all can agree is a fair basis to begin with, we then have expressly for a (p)hoton: E = pc Substituting for the previous E pc = mc˛ divide both sides by c p = mc which to me is new territory. What is mass times the speed of light for a particle that has no mass? Perhaps Tom's special reading skills can rescue this p term from the oblivion of E = 0 for a (p)hoton. But we usually relate more directly to the frequency (or wavelength) of the photon rather than its energy or momentum, so in such a case E=h*nu would provide a more direct route to its mass equivalent. Yes, and it seems your daughter trumped me on Planck once before. ;-) It is exceedingly obvious that the link offered amounts to considerable wool gathering. Or maybe its the late hour.... 73's Richard Clark, KB7QHC |
Photon vs Wave emissions from antennas?
Richard Clark wrote:
What is mass times the speed of light for a particle that has no mass? A nonsense question since "no mass" for a photon is associated with it being *at rest*, i.e. *not moving at the speed of light*. Perhaps Tom's special reading skills can rescue this p term from the oblivion of E = 0 for a (p)hoton. For a photon possessing zero rest mass, traveling at the speed of light yields a finite measurable mass. -- 73, Cecil http://www.w5dxp.com |
Photon vs Wave emissions from antennas?
On Sep 7, 12:51 am, Richard Clark wrote:
The circularity of Dr. Ken Mellendorf's foggy writing might suggest it, if it weren't otherwise nipped in the bud by the bald statement. On the other hand perhaps Dr. Mellendorf has some expertise in the subject. What is the term p? Could it be (p)hoton? I've speculated about Planck's constant (which you comment upon, below), but I find it very sloppy writing for Dr. Mellendorf to wander into his own naming conventions. I think you should make those comments directly to him so that he an opportunity to respond. Shall I forward them for you? :-) What is mass times the speed of light for a particle that has no mass? Seems like something is wrong in that sentence, doesn't it. Perhaps Tom's special reading skills can rescue this p term from the oblivion of E = 0 for a (p)hoton. It's also possible that since E=0 is wrong, the assumption that p=0 might also be wrong. If not, then you'll need to explain radiation pressure in an all new way. Yes, and it seems your daughter trumped me on Planck once before. ;-) She's better at math than I ever was. 73, ac6xg |
Photon vs Wave emissions from antennas?
On 6 Sep, 22:21, John Smith wrote:
art wrote: ... I believe we view aether differently as well as the term equilibrium. ... Art Art: I found an interesting fellow on the net, here is a .pdf of his free ebook: (chapter 8 I found very interesting) http://www.teslaphysics.com/files/Detection.pdf If you would like to read it in .html instead: http://www.teslaphysics.com/ Look near the bottom of the page for the book, but this page itself is interesting. He has done some experimenting and claims to have detected the ether. He cites another fellows experiments which his own experiments followed. Beware and be warned, his thinking challenges Einsteins' own ... Regards, JS John, I have only stated how I as an individual views things. Since I have not studied physics all that much it can be seen as just guessing. Reading Planck at the moment while wife is in hospital ICU so time is limited all the way around Regards Art |
Photon vs Wave emissions from antennas?
John Smith wrote:
way... (no Virginia, that is not a vacuum inside the radiometer, just high altitude - and yes there is no Santa Claus - now come over here and sit on my lap) denny Really? So, someone should tell the engineers who have proposed the "solar sail?" A massive silvered mylar sail which would be unfolded in space and sail spacecraft on the "solar winds", photons reflected mass--actually. You guys missed your calling ... you could have been "fact debunkers!" I'm no expert (although play one on TV), but I thought that the process at work was reflection of the photon, which shows a measurable doppler shift. The doppler shift lowers it's wavelength. The wavelength increases, and energy decreases. That energy has to go somewhere, and it goes into the sail and takes the spacecraft or whatever is attached along for the ride. So it really isn't a mass issue - although it is possible that the solar wind which does have mass and may contribute some small push on the sail. But that is another issue.Photon push is a radiation pressure energy transfer mechanism. - 73 de Mike KB3EIA - |
Photon vs Wave emissions from antennas?
Richard Clark wrote:
On Sat, 01 Sep 2007 06:00:46 -0700, Denny wrote: Uhhh, gawd, I hate to even get into THIS mess... But, somebody has gotta do it... Hi Denny, Well, for such a melodramatic dip of your toe into this cesspool, I hope you brought your snorkel. Or at least a fork and spoon... - 73 de Mike KB3EIA - |
Photon vs Wave emissions from antennas?
Michael Coslo wrote:
... some small push on the sail. But that is another issue.Photon push is a radiation pressure energy transfer mechanism. - 73 de Mike KB3EIA - Ahhh, you are such a "jokester!" I always enjoy a good laugh, ha ha ha. JS |
Photon vs Wave emissions from antennas?
On Sep 7, 9:08 am, Jim Kelley wrote:
On Sep 7, 12:51 am, Richard Clark wrote: The circularity of Dr. Ken Mellendorf's foggy writing might suggest it, if it weren't otherwise nipped in the bud by the bald statement. On the other hand perhaps Dr. Mellendorf has some expertise in the subject. What is the term p? Could it be (p)hoton? I've speculated about Planck's constant (which you comment upon, below), but I find it very sloppy writing for Dr. Mellendorf to wander into his own naming conventions. I think you should make those comments directly to him so that he an opportunity to respond. Shall I forward them for you? :-) What is mass times the speed of light for a particle that has no mass? Seems like something is wrong in that sentence, doesn't it. Perhaps Tom's special reading skills can rescue this p term from the oblivion of E = 0 for a (p)hoton. It's also possible that since E=0 is wrong, the assumption that p=0 might also be wrong. If not, then you'll need to explain radiation pressure in an all new way. Yes, and it seems your daughter trumped me on Planck once before. ;-) She's better at math than I ever was. 73, ac6xg For the lurkers who may care to sift a tiny bit of wheat from the chaff, see common physics symbol usage at http://www.alcyone.com/max/reference...s/symbols.html, http://selland.boisestate.edu/jbrenn...cs_symbols.htm, http://www.hazelwood.k12.mo.us/~gric...b/formulas.htm and others. If you're reading physics writings, it helps to have an understanding of the language of the physicist. See concise explanations about photon momentum and relativistic momentum, energy and mass in general at http://hyperphysics.phy-astr.gsu.edu...iv/relmom.html, http://physics.mtsu.edu/~phys2020/Le..._momentum.html and others. |
Photon vs Wave emissions from antennas?
John Smith wrote:
Michael Coslo wrote: ... some small push on the sail. But that is another issue.Photon push is a radiation pressure energy transfer mechanism. - 73 de Mike KB3EIA - Ahhh, you are such a "jokester!" I always enjoy a good laugh, ha ha ha. At your service! - 73 de Mike KB3EIA - |
Photon vs Wave emissions from antennas?
Hi Denny, Well, for such a melodramatic dip of your toe into this cesspool, I hope you brought your snorkel. Or at least a fork and spoon... - 73 de Mike KB3EIA - Yeah, there are rather large chunks floating in the effluent... denny / k8do |
Photon vs Wave emissions from antennas?
John Smith wrote:
"The photon/wave properties of rf still remains a mystery ... and proof is hard to come by." Osama, Obama, and Chelsea`s mama are real, alive and on TV. The particle theory of light, like the myth that Elvis lives, should only be accepted to the level that gives us comfort. We don`t need light particles to calculate antenna dimensions. Best regards, Richard Harrison, KB5WZI |
Photon vs Wave emissions from antennas?
Dave Oldridge wrote:
... Quite so. And there is no "vs." here. Just two different ways of looking at the same physical phenomena. Yeah, exactly, and LDE is just a figment of the imagination! And, all the antennas possible have already been built, etc. ... :-) Regards, JS |
Photon vs Wave emissions from antennas?
John Smith wrote:
... And, no, this motor doesn't come apart at this speed--the metal the motor is made of came from the UFO crash in Roswell NM ;-) Regards, JS OK. So now you are all setting there with a big fat carrier right around 1 Mhz, and peering out yer windows. However, and by the way, the answer was I was charged with creating a disturbance in the gravitational ether ... just in case you were wondering :) But, 'ya already knew that! :) Regards, JS |
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