"Stefan Wolfe" wrote in message
...

"Cecil Moore" wrote in message
...
Stefan Wolfe wrote:
I see no other means this energy can be imparted other then via
electrons (ON AVERAGE) exchanging orbital states in the antenna copper
(etc.) atoms resulting in a release of this total energy per photon.
How can photons otherwise be manufactured by passing an analog
wavelike-field forcing function through another field?

Above you are referring to tight-binding electrons. But
Our RF antennas make use of *free electrons* which are
thought to exist in the outer orbits of conductors.
Instead of changing orbits within a single atom, these
free electrons jump from atom to atom and from groups
of atoms to other groups of atoms. When a free electron
emits a photon, it is not associated with an orbit
change and so is not quantized to any orbit change. The
photon is instead quantized to the frequency of the
energy source and is therefore coherent with that source
which is our RF transmitters.

Thanks! That does help me understand the effect much better. I was hung up
on the electrons jumping between the shells (s, p etc.) and I was having
problems with that because it dawned on me that the energy levels for the
tight binding electrons are associated with very specific quantum
energies, depending on the type of atom, so how could we produce any
desired frequency that we wanted? I considered that simultaneous "jumps"
of multiple electrons could produce quantum energies for any frequency we
wanted but that is too complicated and it is much more easily explained by
your free electron concept.


The wave function of free electrons is uniform over the conductor.
They may be found anywhere.

73
H.
NQ5H