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Tam/WB2TT wrote:
"Cecil Moore" wrote in message It does that by not allowing reflected energy to reach the transmitter and redistributing the reflected energy back toward the antenna as part of the forward wave. Thus a transmitter can be sourcing 100 watts while the forward power on the transmission line is 200 watts. What it really is is an impedance matching network. You adjust the antenna tuner so that the transmitter sees 50 Ohms. If your SWR meter is calibrated for 50 Ohms, that means an SWR of 1:1 (between the tuner and the radio). Yes, and that is a Z0-match to 50 ohms. What happens at a Z0-match is wave cancellation of reflected waves through destructive interference which redistributes the reflected energy back toward the antenna in the form of constructive interference energy that joins the forward wave. micro.magnet.fsu.edu/primer/java/scienceopticsu/interference/waveinteractions/index.html "... when two waves of equal amplitude and wavelength that are 180-degrees ... out of phase with each other meet, they are not actually annihilated, ... All of the photon energy present in these waves must somehow be recovered or redistributed in a new direction, according to the law of energy conservation ... Instead, upon meeting, the photons are redistributed to regions that permit constructive interference, so the effect should be considered as a redistribution of light waves and photon energy rather than the spontaneous construction or destruction of light." The reason that the transmitter is protected is that the Z0-match *causes* that redistribution of the reflected energy back toward the antenna. Protecting the transmitter is a side-effect of tuning the entire antenna *system* to resonance. -- 73, Cecil http://www.w5dxp.com |
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