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Distributed capacitance and antennas
How does distributed capacitance harvest the energy given
in sino soidal form and later release it in the same form that it was harvested in? Same question, but now look at distributed inductance and how that works! Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant but the books don't tell me.about the other things! Like the time constant of distributed capacitance Art |
Distributed capacitance and antennas
On Wed, 07 Nov 2007 10:56:13 -0800, art wrote:
Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? |
Distributed capacitance and antennas
On 7 Nov, 11:33, Richard Clark wrote:
On Wed, 07 Nov 2007 10:56:13 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Go away Richard. You never answer questions you only jeer people. If you don't answer the Wood question directly instead of going all over the place I will have to let your posts slip by me You can always start your own posts you know instead of looking for somebody to jeer at! That would be a good way of establishing relationships with like wise thinking people to replace that guy in S America Art |
Distributed capacitance and antennas
On Wed, 07 Nov 2007 11:51:33 -0800, art wrote:
Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Go away Richard. You never answer questions On Tue, 06 Nov 2007 15:12:15 -0800, Richard Clark wrote: On Tue, 06 Nov 2007 11:04:38 -0800, art wrote: Shorten your post and just type one line. I Richard, can show the error of your mathematics Rr = 80 · pi² · (length/wavelength)² To my one line answer to your question, as you asked, you promised to show the error of my math (found in your copy of J&J) and What is the time constant of 50 Ohms? 73's Richard Clark, KB7QHC |
Distributed capacitance and antennas
On 7 Nov, 12:27, Richard Clark wrote:
On Wed, 07 Nov 2007 11:51:33 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Go away Richard. You never answer questions On Tue, 06 Nov 2007 15:12:15 -0800, Richard Clark wrote: On Tue, 06 Nov 2007 11:04:38 -0800, art wrote: Shorten your post and just type one line. I Richard, can show the error of your mathematics Rr = 80 · pi² · (length/wavelength)² To my one line answer to your question, as you asked, you promised to show the error of my math (found in your copy of J&J) and What is the time constant of 50 Ohms? 73's Richard Clark, KB7QHC Richard stop badgering me I am straight and have a family. |
Distributed capacitance and antennas
On Wed, 07 Nov 2007 12:43:25 -0800, art wrote:
On 7 Nov, 12:27, Richard Clark wrote: On Wed, 07 Nov 2007 11:51:33 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Go away Richard. You never answer questions On Tue, 06 Nov 2007 15:12:15 -0800, Richard Clark wrote: On Tue, 06 Nov 2007 11:04:38 -0800, art wrote: Shorten your post and just type one line. I Richard, can show the error of your mathematics Rr = 80 · pi² · (length/wavelength)² To my one line answer to your question, as you asked, you promised to show the error of my math (found in your copy of J&J) and What is the time constant of 50 Ohms? 73's Richard Clark, KB7QHC Richard stop badgering me I am straight and have a family. Sounds like you should discuss those personal issues with your chaplain and stick to technical topics quoted above. This isn't rec.radio.ann.landers. 73's Richard Clark, KB7QHC |
Distributed capacitance and antennas
On 7 Nov, 12:43, art wrote:
On 7 Nov, 12:27, Richard Clark wrote: On Wed, 07 Nov 2007 11:51:33 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Go away Richard. You never answer questions On Tue, 06 Nov 2007 15:12:15 -0800, Richard Clark wrote: On Tue, 06 Nov 2007 11:04:38 -0800, art wrote: Shorten your post and just type one line. I Richard, can show the error of your mathematics Rr = 80 · pi² · (length/wavelength)² To my one line answer to your question, as you asked, you promised to show the error of my math (found in your copy of J&J) and What is the time constant of 50 Ohms? 73's Richard Clark, KB7QHC Richard stop badgering me I am straight and have a family.- Hide quoted text - - Show quoted text - So Radio hams, professional and amateur. Does distributed store energy like other capacitors or is it an animal by another name? Does it store photons for later distribution of radiation? Do photons eat the electrons while they are being stored by the capacitor Do the electrons jump up and down because they know an inductance is ahead? These questions are very important in determining what radiation is all about. And yes I hear waves are often mentioned. Is this the three dimensional wave that is created in the pond when the static particles fall off the antenna in a circular type pattern? Antenna books say the pattern is a figure eight! How can that be? When the energy removes itself from distributed capacitance do the photon march along the antenna in an orderly fashion? or do they rush out as if the movie in the capacitor is over? Last of all has anybody seen a photon and photographed it? I suppose if you believe in ghosts then you could well believe in photons that float in the night. You can't see them but there really is a chill in the air. So back to the original question, What does distributed capacitance do with the oncomming sino soidal wave? Does it let it through unharmed so that we have a time varience that is needed for radiation per the radio books? Art |
Distributed capacitance and antennas
"art" wrote
Antenna books say the pattern is a figure eight! How can that be? When the energy removes itself from distributed capacitance do the photon march along the antenna in an orderly fashion? or do they rush out as if the movie in the capacitor is over? _________ Your intuitive theories may not support this, Arthur, but haven't you noticed that your linear, dipole antennas (whether "short" or 1/2-wave) transmit and receive very poorly in the directions of their longitudinal axis? In fact, radio direction finders make use of this proven reality of radiation physics. How do you explain this, if you believe that the radiation pattern/gain of a dipole is not very low in those directions, as in the nulls of a figure 8, and as easily measured for these antenna configurations on a good test range? Please post your supporting math(s). RF |
Distributed capacitance and antennas
On 7 Nov, 15:33, "Richard Fry" wrote:
"art" wrote Antenna books say the pattern is a figure eight! How can that be? When the energy removes itself from distributed capacitance do the photon march along the antenna in an orderly fashion? or do they rush out as if the movie in the capacitor is over? _________ Your intuitive theories may not support this, Arthur, but haven't you noticed that your linear, dipole antennas (whether "short" or 1/2-wave) transmit and receive very poorly in the directions of their longitudinal axis? In fact, radio direction finders make use of this proven reality of radiation physics. How do you explain this, if you believe that the radiation pattern/gain of a dipole is not very low in those directions, as in the nulls of a figure 8, and as easily measured for these antenna configurations on a good test range? Please post your supporting math(s). RF Ofcourse there is no radiation off the ends. What ever is sitting on the antenna can only fall off one side or the other. As far as the math goes you are not conversant enough with math to get involved. You could redeem your self by pointing out the deliberate mistake made by Dr John E Davis and become an overnight guru. Just think up another lie nobody will challenge you! Art |
Distributed capacitance and antennas
On Wed, 07 Nov 2007 14:38:23 -0800, art wrote:
On 7 Nov, 12:43, art wrote: On 7 Nov, 12:27, Richard Clark wrote: On Wed, 07 Nov 2007 11:51:33 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Go away Richard. You never answer questions On Tue, 06 Nov 2007 15:12:15 -0800, Richard Clark wrote: On Tue, 06 Nov 2007 11:04:38 -0800, art wrote: Shorten your post and just type one line. I Richard, can show the error of your mathematics Rr = 80 · pi² · (length/wavelength)² To my one line answer to your question, as you asked, you promised to show the error of my math (found in your copy of J&J) and What is the time constant of 50 Ohms? 73's Richard Clark, KB7QHC Richard stop badgering me I am straight and have a family.- Hide quoted text - - Show quoted text - So Radio hams, professional and amateur. Does distributed store energy like other capacitors or is it an animal by another name? Does it store photons for later distribution of radiation? Do photons eat the electrons while they are being stored by the capacitor Do the electrons jump up and down because they know an inductance is ahead? These questions are very important in determining what radiation is all about. And yes I hear waves are often mentioned. Is this the three dimensional wave that is created in the pond when the static particles fall off the antenna in a circular type pattern? Antenna books say the pattern is a figure eight! How can that be? When the energy removes itself from distributed capacitance do the photon march along the antenna in an orderly fashion? or do they rush out as if the movie in the capacitor is over? Last of all has anybody seen a photon and photographed it? I suppose if you believe in ghosts then you could well believe in photons that float in the night. You can't see them but there really is a chill in the air. So back to the original question, What does distributed capacitance do with the oncomming sino soidal wave? Does it let it through unharmed so that we have a time varience that is needed for radiation per the radio books? Art Art, I suggested a few weeks ago that you could make a killing in writing humorous lines for either Jay Leno or Dave Letterman. But I guess you had no luck finding an opening in the field. Ah, but Art, are you aware of the writers' strike now ongoing? Those writers are on strike, so what are Leno and Letterman going to do without 'em? They're going to go insane trying to come up on their own with the funny stuff they normally get from their writers. So there's yer chance, Art, go fer it! Yer all geared up fer it as demonstrated in yer writings in the threads here on rraa. Don't miss this golden opportunity! We'll all be listening as Leno and Letterman read yer jewels. Walt, W2DU |
Distributed capacitance and antennas
On 7 Nov, 19:16, Walter Maxwell wrote:
On Wed, 07 Nov 2007 14:38:23 -0800, art wrote: On 7 Nov, 12:43, art wrote: On 7 Nov, 12:27, Richard Clark wrote: On Wed, 07 Nov 2007 11:51:33 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Go away Richard. You never answer questions On Tue, 06 Nov 2007 15:12:15 -0800, Richard Clark wrote: On Tue, 06 Nov 2007 11:04:38 -0800, art wrote: Shorten your post and just type one line. I Richard, can show the error of your mathematics Rr = 80 · pi² · (length/wavelength)² To my one line answer to your question, as you asked, you promised to show the error of my math (found in your copy of J&J) and What is the time constant of 50 Ohms? 73's Richard Clark, KB7QHC Richard stop badgering me I am straight and have a family.- Hide quoted text - - Show quoted text - So Radio hams, professional and amateur. Does distributed store energy like other capacitors or is it an animal by another name? Does it store photons for later distribution of radiation? Do photons eat the electrons while they are being stored by the capacitor Do the electrons jump up and down because they know an inductance is ahead? These questions are very important in determining what radiation is all about. And yes I hear waves are often mentioned. Is this the three dimensional wave that is created in the pond when the static particles fall off the antenna in a circular type pattern? Antenna books say the pattern is a figure eight! How can that be? When the energy removes itself from distributed capacitance do the photon march along the antenna in an orderly fashion? or do they rush out as if the movie in the capacitor is over? Last of all has anybody seen a photon and photographed it? I suppose if you believe in ghosts then you could well believe in photons that float in the night. You can't see them but there really is a chill in the air. So back to the original question, What does distributed capacitance do with the oncomming sino soidal wave? Does it let it through unharmed so that we have a time varience that is needed for radiation per the radio books? Art Art, I suggested a few weeks ago that you could make a killing in writing humorous lines for either Jay Leno or Dave Letterman. But I guess you had no luck finding an opening in the field. Ah, but Art, are you aware of the writers' strike now ongoing? Those writers are on strike, so what are Leno and Letterman going to do without 'em? They're going to go insane trying to come up on their own with the funny stuff they normally get from their writers. So there's yer chance, Art, go fer it! Yer all geared up fer it as demonstrated in yer writings in the threads here on rraa. Don't miss this golden opportunity! We'll all be listening as Leno and Letterman read yer jewels. Walt, W2DU- Hide quoted text - - Show quoted text - Gee Walter don'tyou consider yourself lucky to have got out of hospital or what ever it was to get asylum. Why don't YOU write a book and send it to Leno? Ofcourse like other people they wont believe it and look at it like a joke. Call it Reflections #4 1/2 that should get a laugh By the way stop that heavy drinking otherwise that asylum will be beckoning you again and you will have to deal with those elephant droppings again. Art |
Distributed capacitance and antennas
"art"
Of course there is no radiation off the ends. What ever is sitting on the antenna can only fall off one side or the other. _____________ Not that I agree with your theory of why this happens, but note that you have now acknowledged a condition that you had disputed just a bit less than 3 hours earlier in this thread. Quoting from that post of yours, "Antenna books say the pattern is a figure eight! How can that be?" RF |
Distributed capacitance and antennas
On 8 Nov, 06:58, "Richard Fry" wrote:
"art" Of course there is no radiation off the ends. What ever is sitting on the antenna can only fall off one side or the other. _____________ Not that I agree with your theory of why this happens, but note that you have now acknowledged a condition that you had disputed just a bit less than 3 hours earlier in this thread. Quoting from that post of yours, "Antenna books say the pattern is a figure eight! How can that be?" RF No. I asked a question as to how that can be To which I later theorised that one can have "sliding" electrons as well as those that are pushed over board. The matter of "sliding" comes into play when you have a tipping force to overcome the tenacity of inertia in the face of a moving fulcrum. But when you get down to the mathematical analysis it becomes obvious that the summation of all vectors involved with radiation produces a vector that does not align with the radiating axis which reinforces the notion of "sliding electrons" or should I say sliding staic or passive particles? Still waiting for you to point to the error in Dr Davis's mathematics such that the existing radiation theory can stay intact !. I would point out that all computor programs on radiation show that for maximising radiation of a particular polarity the summation vector of all vectors involved with radiation is different to that of the axis of the radiator which forces a shift in parallelism to the earth's surface. This is an evolution of Gaussian law which provides further insight to the laws of Maxwell who somehow overlooked the connection between dynamic and static forces. If the Gaussian mathematics is at fault then by logic all computor programs must be suspect. The tipping point is that computor programs ingnored a condition that must be imposed if one is to view Maxwells collections as a series of laws. It was this error which lead to viewing the sino soidal shape of electrical current as constituting the time varience required per Lorentz and others for the production of radiation where as the time varience factor is that obtained by the time constant of energy release of distributed inductance and capacitance. The saving grace for computor programing was its adherrence to the conservation of energy theorem, energy in equals energy out which is basically what the leanings of Gauss was. Sowith elements that are resonant olone and in their entirety in a array produces a smaller array than that for a planar array such as a yagi. On top of the reduction of element spacings it allows for helices or the action of "slow waves" to reduce the htree dimensions of freedom for any array down to a size of a half wave per side noting at the same time one has only to feed one element and yet gain the aperature presented by a stack of beams with separate feed points So I believe it behooves all to reexamine the mathematics because if they are correct thben the rewards are humoungua. Or play with your computor programs with non planar radiating elements Art Unwin KB9MZ.....xg |
Distributed capacitance and antennas
"art" wrote
No. I asked a question as to how that can be To which I later theorised etc etc ___________ That was an interesting read. I suggest you send your work to the IEEE to see what they make of it. If it all goes your way, you will have earned parity with all the "masters" you refer to so frequently. RF |
Distributed capacitance and antennas
On 8 Nov, 11:37, "Richard Fry" wrote:
"art" wrote No. I asked a question as to how that can be To which I later theorised etc etc ___________ That was an interesting read. I suggest you send your work to the IEEE to see what they make of it. If it all goes your way, you will have earned parity with all the "masters" you refer to so frequently. RF That cannot be done. There are legitimate guru's on this net and very near the top I would put Richard despite his arrogance, jeering and painfull use of english. But the fact is that those endowed with a knoweledge of radiation have been bitten so many times by wishfull thinking of new antennas that they have wandered firmly into the camp that all is known and now dismiss all without the thought aplied that they are capable of I first started talk of radiation occurring in pulsatic form on this forum many years ago when I first applied myself to the science of antennas. This mere notion of mine started off this adventure where every adjective is being used to describe me. However as somebody who came from the docklands of East Londonyou are given the natural ability of sticking to your guns regardless of what it does to your self esteem. I suspect I will go to my grave before my work is taken seriously. And that is a shame. Not for me but for the continuance of ham radio where we can again convince all that ham radio is still at the cusp of new discoveries and have a useful purpose in society. I am not asking for recognition of any sort since as a former cockney I can handle adversity regardless how it is formed I can take it and I surely can give it out.( I remember Goring and his bombers) Regards Art KB9MZ...XG (uk) |
Distributed capacitance and antennas
Stefan Wolfe wrote:
Hello Art, this is an easy one that any amateur could answer and which I would think is well below your level of the physics (so the reason for your question confuses me): If the antenna is perfectly resonant, then it, as a total charge distribution system or "circuit", has a time constant of zero. At any point along the length of the antenna, there are time constants that could apply, RC or R/L depending upon reactivity of the section in question. But you are asking about the distributed capacitance; what does that mean, let's say in terms of any point at a designated distance from feed point? Where do you want to calculate the time constant? Otherwise, once the antenna is resonant either by design or by the addition of reactive components (such as a coil in the center), as a whole it is a resonant circuit where reactive impedances cancel out and you are only left with resistance (ohmic + radiation resistance) and the time constant of the whole circuit must be zero. In a resonant circuit containing R, L, and C, there most definitely is a time constant. Related to Q, it describes the time taken for the circuit to respond to a transient. The higher the Q, the longer the time constant, and the longer it takes the circuit to come to equilibrium after a step or sinusoid is applied, and to decay after it's removed. Failure to understand this has resulted in some very poorly designed audio filters for CW, among other things. The reactances in a resonant circuit cancel only at a single frequency. That means if you apply a sinusoidal signal at the resonant frequency for a very long time, and don't change anything about it (phase, amplitude, frequency, or waveshape), the resonant circuit will act like a resistor. But it won't under any other circumstances. As soon as you say "time constant", you're speaking of the response to a changing, not steady state sinusoidal, signal. And the response of the resonant circuit containing L and C to any change in the signal will be very different from the response of a resistor. And it will exhibit a time constant. (This can bee seen in the time domain equations for i(t) and v(t) which contain an exponential term multiplying the sinusoidal term. The time constant is in the exponent. See any text on electrical circuits for more detail.) Roy Lewallen, W7EL |
Distributed capacitance and antennas
On 10 Nov, 19:36, Roy Lewallen wrote:
Stefan Wolfe wrote: Hello Art, this is an easy one that any amateur could answer and which I would think is well below your level of the physics (so the reason for your question confuses me): If the antenna is perfectly resonant, then it, as a total charge distribution system or "circuit", has a time constant of zero. At any point along the length of the antenna, there are time constants that could apply, RC or R/L depending upon reactivity of the section in question. But you are asking about the distributed capacitance; what does that mean, let's say in terms of any point at a designated distance from feed point? Where do you want to calculate the time constant? Otherwise, once the antenna is resonant either by design or by the addition of reactive components (such as a coil in the center), as a whole it is a resonant circuit where reactive impedances cancel out and you are only left with resistance (ohmic + radiation resistance) and the time constant of the whole circuit must be zero. In a resonant circuit containing R, L, and C, there most definitely is a time constant. Related to Q, it describes the time taken for the circuit to respond to a transient. The higher the Q, the longer the time constant, and the longer it takes the circuit to come to equilibrium after a step or sinusoid is applied, and to decay after it's removed. Failure to understand this has resulted in some very poorly designed audio filters for CW, among other things. Agreed to. Especially the reference to equilibrium. You are the first to acknoweledge that tenent The reactances in a resonant circuit cancel only at a single frequency. That means if you apply a sinusoidal signal at the resonant frequency for a very long time, and don't change anything about it (phase, amplitude, frequency, or waveshape), the resonant circuit will act like a resistor. Hold it right there. Ohio state university placed that as a added assumtion to Maxwells laws and as you well know that it started to produce errors. This is the reason that "moments" was brought into calculations because of the way it averages or deals with errors. I suspect that an engineer said get rid of that assumption if it doesn't work but like the saga of the "O ring" with Nasa enegineers were ignored. This was at the time I was wrestling with fortran and punched cards for computor generated BOM's that put me off of programming per say.You and others bandy with the words inductance and capacitance but you must know or should know that both of these will not allow a sino soidal voltage or current to pass intact thus one has to review where the time varience factor comes from.especially when the used premise was found to be faulty. But it won't under any other circumstances. As soon as you say "time constant", you're speaking of the response to a changing, not steady state sinusoidal, signal. And the response of the resonant circuit containing L and C to any change in the signal will be very different from the response of a resistor. And it will exhibit a time constant. (This can bee seen in the time domain equations for i(t) and v(t) which contain an exponential term multiplying the sinusoidal term. The time constant is in the exponent. See any text on electrical circuits for more detail.) I cannot look at texts for an answer because the texts use a prohibited method by adding a premise to a law. You take the sinosoidal wave shape as the time varient despite the errors it produces where as I do not. I do accept the laws of Maxwell as stated as laws without the need to change things because of outside pressures especially when it is accepted that it produces errors by all concerned. Roy Lewallen, W7EL- Hide quoted text - - Show quoted text - |
Distributed capacitance and antennas
On 10 Nov, 19:12, "Stefan Wolfe" wrote:
"art" wrote in message ps.com... How does distributed capacitance harvest the energy given in sino soidal form and later release it in the same form that it was harvested in? Same question, but now look at distributed inductance and how that works! Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant but the books don't tell me.about the other things! Like the time constant of distributed capacitance Art Hello Art, this is an easy one that any amateur could answer and which I would think is well below your level of the physics (so the reason for your question confuses me): If the antenna is perfectly resonant, then it, as a total charge distribution system or "circuit", has a time constant of zero. Where on earth did you get that from? The circuit has two components that will not allow the sino soidal circuit to pass intact and radiation occurs because of a time varient. So if the sino soidal current is changed to something else then we have to look for an alternative for the time varience factor. You have to start from a strong footing and you are not At any point along the length of the antenna, there are time constants that could apply, RC or R/L depending upon reactivity of the section in question. But you are asking about the distributed capacitance; what does that mean, let's say in terms of any point at a designated distance from feed point? Where do you want to calculate the time constant? Otherwise, once the antenna is resonant either by design or by the addition of reactive components (such as a coil in the center), as a whole it is a resonant circuit where reactive impedances cancel out and you are only left with resistance (ohmic + radiation resistance) and the time constant of the whole circuit must be zero. You may neutralise the effect of components but you can't get rid of the components themselves. They still have properties that come into play with respect to the circuit Best Regards Art Unwin KB9MZ......Xg |
Distributed capacitance and antennas
Stefan Wolfe wrote:
"Roy Lewallen" wrote in message ... Stefan Wolfe wrote: In a resonant circuit containing R, L, and C, there most definitely is a time constant. Related to Q, it describes the time taken for the circuit to respond to a transient. The higher the Q, the longer the time constant, and the longer it takes the circuit to come to equilibrium after a step or sinusoid is applied, and to decay after it's removed. Failure to understand this has resulted in some very poorly designed audio filters for CW, among other things. But Roy, I must first clear up that we are talking about apples and oranges. I was referencing a sinusoidal source of a frequency that is resonant to the circuit. You are talking about a transient can be treated as the sum of sinusoids which will not be resonant at the same curcuit. I was also referring to the antenna as a L-C-R circuit that does have time constants along its lengths (but I was asking 'where' along the length) but as a whole system the time contant of the antenna, when fed by a signal at resonant frequency is zero. . . . You've lost me. What is the meaning of a "time constant" in steady state? What effect does it have? With a single frequency of constant amplitude, how could you tell whether a circuit, resonant or not, has a "time constant"? How could you measure it? Roy Lewallen, W7EL |
Distributed capacitance and antennas
On 11 Nov, 01:54, Roy Lewallen wrote:
Stefan Wolfe wrote: "Roy Lewallen" wrote in message ... Stefan Wolfe wrote: In a resonant circuit containing R, L, and C, there most definitely is a time constant. Related to Q, it describes the time taken for the circuit to respond to a transient. The higher the Q, the longer the time constant, and the longer it takes the circuit to come to equilibrium after a step or sinusoid is applied, and to decay after it's removed. Failure to understand this has resulted in some very poorly designed audio filters for CW, among other things. But Roy, I must first clear up that we are talking about apples and oranges. I was referencing a sinusoidal source of a frequency that is resonant to the circuit. You are talking about a transient can be treated as the sum of sinusoids which will not be resonant at the same curcuit. I was also referring to the antenna as a L-C-R circuit that does have time constants along its lengths (but I was asking 'where' along the length) but as a whole system the time contant of the antenna, when fed by a signal at resonant frequency is zero. . . . You've lost me. What is the meaning of a "time constant" in steady state? What effect does it have? With a single frequency of constant amplitude, how could you tell whether a circuit, resonant or not, has a "time constant"? How could you measure it? Roy Lewallen, W7EL- Hide quoted text - - Show quoted text - Is this a prelude to your normal comment when you walk away? This I don't understand is a cop out but I will answer you anyway. The meaning of time constant. You are aware that the addition of other things that was not part of Maxwells laws such as the assumption of a sino soidal current at every point taken for the calculation produced errors. As one who sells the NEC work you must know that. If it produces errors then the assumption is in correct yet Maxwells laws are based on radiation from the time varient phenomina. Thus it behooves all to impose the correct or alternative time varient.An alternative time varient is exposed when one adds a time varient to the law of statics which is shown to equal or be the same as Maxwells laws( see the math in the archives. Using Gauss's method of analysis which is based around flux and an arbitary field shows radiation is formed in pulses during times that equilibrium is broken and the arbitary borders fracture momentarily. The only way therefore is the circuit is one of a tank circuit. The tank circuit mby use of the radiators constituent capacitance and inductance revolves the time constant associated with a sino soidal property and with the syncroness of energy release according to the time constant of the energy storage imposes a time varient. Now the math is there so next we allow a computor program with unknown viability to compare with Gauss's law extension that I imposed. What does this show? Using the optimiser version it allways migrates to a non planar form and not the planar form which scientists have mimiced from the yagi. Doing this it supplies the angle for a helix that is mathematically supplied by Maxwell where prior to this it was emperically found. One can overcheck this by placing a non planar form into any passive antenna program and it verifies the results of a Gaussian apoproach. Since using the time varience associated with a sino soidal produces errors and the time constant of heat storage release does not produce errors to Maxwells laws it behooves all to review the significance of what I did which is to add a time variable to the same proven situation that Gauss applied for statics. a proven method which does not violate Maxwells laws. .. For your part you can examine the mathematical aproach taken for error since it is at the core of what I present. If you wish to modify it so it conforms with the books I will give it a fair hearing without defaulting to the "all is known" syndrome.I cannot agree to adding any assumptions to Maxwells laws since that delegitamises any law as we know it. Science demands impartial examination without imposing pre supposed conditions or the involvement of personal feelings since it is continually found that what is unlikely to happen does actually happen! Questions to ask yourself. How is it that Maxwell defined the angle for a helix that matches thatfound by Kraus empirically by not using the time varient assumptions that we presently used associated with the sino soidal wave? Art Unwin KB9MZ....XG |
Distributed capacitance and antennas
On Sun, 11 Nov 2007 05:22:21 -0800, art wrote:
Is this a prelude to your normal comment when you walk away? Arthur, such an amusing criticism coming from you considering the longstanding, and simple question offered to your own comment: On Wed, 07 Nov 2007 10:56:13 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Longwinded explanations are not sought, just a simple number (you don't even have to show your math). 73's Richard Clark, KB7QHC |
Distributed capacitance and antennas
On 11 Nov, 08:16, Richard Clark wrote:
On Sun, 11 Nov 2007 05:22:21 -0800, art wrote: Is this a prelude to your normal comment when you walk away? Arthur, such an amusing criticism coming from you considering the longstanding, and simple question offered to your own comment: On Wed, 07 Nov 2007 10:56:13 -0800, art wrote: Distributed resistance is easy, it changes the energy to heat, stores it and releases it according to its time constant What is the time constant of 50 Ohms? Longwinded explanations are not sought, just a simple number (you don't even have to show your math). 73's Richard Clark, KB7QHC It just goes to show that I don't have an answer to every question that you have in your efforts to supply a platform for your jeering. I do know that a resistor stores energy applied while it changes to heat. I also known that the temperature change is not instantaneous thus time must be a factor depending on the environment. But you present questions that do not deal directly with the subject posed in your attempts to jeer. Look at your many exchanges with Dr John E Davis, you never did provide an instance where the subject in hand was incorrect or otherwise. Yet your exchanges with him were long and so disagreeable and disrespectfull that after several attempts while remaining polite did not line up with an arguement that you often want he was forced to leave.The thread has been provided again such that other can determine whether Dr Davis was treated with respect by you Actually nobody including you accepted his mathematics in any way which he proffered in an effort to show that I was correct. The only interest of this group was to treat him the same way that they treat outhers on this newsgroup. I will not respond to any more of your efforts that defray from the discussion at hand so that you can jeer. Art |
Distributed capacitance and antennas
On Sun, 11 Nov 2007 08:38:38 -0800, art wrote:
What is the time constant of 50 Ohms? Longwinded explanations are not sought, just a simple number (you don't even have to show your math). It just goes to show that I don't have an answer It took you quite a while to come to same conclusion everyone else has. I do know that a resistor stores energy applied while it changes to heat. How much energy does 50 Ohms store? 73's Richard Clark, KB7QHC |
Distributed capacitance and antennas
On 11 Nov, 08:58, "Stefan Wolfe" wrote:
"Roy Lewallen" wrote in message ... Stefan Wolfe wrote: "Roy Lewallen" wrote in message ... Stefan Wolfe wrote: In a resonant circuit containing R, L, and C, there most definitely is a time constant. Related to Q, it describes the time taken for the circuit to respond to a transient. The higher the Q, the longer the time constant, and the longer it takes the circuit to come to equilibrium after a step or sinusoid is applied, and to decay after it's removed. Failure to understand this has resulted in some very poorly designed audio filters for CW, among other things. But Roy, I must first clear up that we are talking about apples and oranges. I was referencing a sinusoidal source of a frequency that is resonant to the circuit. You are talking about a transient can be treated as the sum of sinusoids which will not be resonant at the same curcuit. I was also referring to the antenna as a L-C-R circuit that does have time constants along its lengths (but I was asking 'where' along the length) but as a whole system the time contant of the antenna, when fed by a signal at resonant frequency is zero. . . . You've lost me. What is the meaning of a "time constant" in steady state? What effect does it have? With a single frequency of constant amplitude, how could you tell whether a circuit, resonant or not, has a "time constant"? How could you measure it? The meaning of a time constant is not dependent upon steady state sinusoids or transient; it is merely a characteristic that dependent upon the *physical* properties of the components in the circuit. You know that of course. Let us say we design a power supply for use in consumer appliances. The power supply of course has a capacitor across line and neutral for EMI filtering, along with a bleeder resistor in parallel with this capacitor. Together, the bleeder resistor and phase/phase capacitor filter have a time constant. Now the time constant is meaningless with respect to steady state input voltage (other than wave shaping high f emi components) and with respect to transients. It is meaningful with respect to safety. If the consumer pulls out the plug, the bleeder resistor must discharge the phase to phase cap safely to prevent the consumer from being shocked when touching the L-N pins. The time constant RC in this case MUST meet certain specifications, that is it must be less than 0.1sec. That is essentially required legally (since standard compliance is compulsory). The time constant exists is chosen for a worse case value, ie that the consumer unplugs the power supply at the peak of the AC cycle. Actually, it is the DC discharge characteristic that we care about here. Transient suppression is not relevant nor is its ability to shape the incoming sinusoid.- Hide quoted text - - Show quoted text - I read thru all and it wasn't until thelast sentence did you state anything that is relevent. The Dc discharge characteristic when the terminals are shorted. Discouting the spike at the beginning the discharge is dependent on the size of the vessel and restrictions applied by the circuit. The larger the vessel the sharper the curve with respect to time. This goes for both the inductance and the capacitance and it is only the losses which are small take away the perpetual motion. I suggest you go to google and look up a "tank circuit" where they will I am sure take you thru the phase changes that create the pendulum like action. But then you knew that all along, anything but review the math. Hot air once again. Why not discuss it with the broadcast engineer with his long time service at switching on a transmitter every morning,every day plus turn the lights out. As Vanna White would say in defence of her salary status You have to know the alphabet Art Art |
Distributed capacitance and antennas
"art" wrote
Why not discuss it with the broadcast engineer with his long time service at switching on a transmitter every morning, every day plus turn the lights out. __________ As I told you once already, the last 30 years of my professional background was in the field and applications engineering groups of the two largest designers/manufacturers of broadcast radio and television transmitter and antenna systems in the US: RCA and Harris. My experience working directly for broadcast stations was early in my career, including with a stint at WJR, a 50 kW, non-directional AM station using a 195° monopole (700 ft high). And what is your commercial experience in the field of r-f systems? RF |
Distributed capacitance and antennas
"Richard Fry" wrote in message And what is your commercial experience in the field of r-f systems? RF Richard: Concerning Art's experience with RF energy, I believe that he often microwaves with the door open. Mike W5CHR |
Distributed capacitance and antennas
On 11 Nov, 12:30, "Stefan Wolfe" wrote:
"art" wrote in message ups.com... On 11 Nov, 08:58, "Stefan Wolfe" wrote: "Roy Lewallen" wrote in message ... In a resonant circuit containing R, L, and C, there most definitely is a time constant. Related to Q, it describes the time taken for the circuit to respond to a transient. The higher the Q, the longer the time constant, and the longer it takes the circuit to come to equilibrium after a step or sinusoid is applied, and to decay after it's removed. Failure to understand this has resulted in some very poorly designed audio filters for CW, among other things. But Roy, I must first clear up that we are talking about apples and oranges. I was referencing a sinusoidal source of a frequency that is resonant to the circuit. You are talking about a transient can be treated as the sum of sinusoids which will not be resonant at the same curcuit. I was also referring to the antenna as a L-C-R circuit that does have time constants along its lengths (but I was asking 'where' along the length) but as a whole system the time contant of the antenna, when fed by a signal at resonant frequency is zero. . . . You've lost me. What is the meaning of a "time constant" in steady state? What effect does it have? With a single frequency of constant amplitude, how could you tell whether a circuit, resonant or not, has a "time constant"? How could you measure it? The meaning of a time constant is not dependent upon steady state sinusoids or transient; it is merely a characteristic that dependent upon the *physical* properties of the components in the circuit. You know that of course. Let us say we design a power supply for use in consumer appliances. The power supply of course has a capacitor across line and neutral for EMI filtering, along with a bleeder resistor in parallel with this capacitor. Together, the bleeder resistor and phase/phase capacitor filter have a time constant. Now the time constant is meaningless with respect to steady state input voltage (other than wave shaping high f emi components) and with respect to transients. It is meaningful with respect to safety. If the consumer pulls out the plug, the bleeder resistor must discharge the phase to phase cap safely to prevent the consumer from being shocked when touching the L-N pins. The time constant RC in this case MUST meet certain specifications, that is it must be less than 0.1sec. That is essentially required legally (since standard compliance is compulsory). The time constant exists is chosen for a worse case value, ie that the consumer unplugs the power supply at the peak of the AC cycle. Actually, it is the DC discharge characteristic that we care about here. Transient suppression is not relevant nor is its ability to shape the incoming sinusoid.- Hide quoted text - - Show quoted text - I read thru all and it wasn't until thelast sentence did you state anything that is relevent. I really am trying to find out in what way that "time constants" are relevant to your hypothesis or theory or whatever it is. I am surprized that i hit something relevant. Now, you were talking about the time constant of distributed capacitance and inductance with resistance along an antenna radiator. I was thinking about this and I do think there "may" (or may not) be some interesting concepts when considering an RC or R/L time contant when the "R" is "radiation resitance"...it could be fun to think about and I will .. But Art, how can what you have posted help me to understand why electrons jump off the antenna wire (they are very smart because they know just when and where to jump) and cause an effective phased array of guassian static antennae that line themselves up in maxwelling time varying electric and magnetic fields propagating at the speed of light, at least until gravitational forces take over and they hit the ground :-)) ? Pardon me if this sounds ridiculous. That is why I say, please show me the math for whatever it is you are proposing. The Dc discharge characteristic when the terminals are shorted. Discouting the spike at the beginning the discharge is dependent on the size of the vessel and restrictions applied by the circuit. The larger the vessel the sharper the curve with respect to time. This goes for both the inductance and the capacitance and it is only the losses which are small take away the perpetual motion. I suggest you go to google and look up a "tank circuit" Geeze, come on Art... where they will I am sure take you thru the phase changes that create the pendulum like action. But then you knew that all along, anything but review the math. Hot air once again. Well, it all comes from the heat stored in the resistor when the distributed capacitance along the antenna discharges in the ohmic resistance in your 50 ohm antenna :-))) (god this is getting ridiculous)....show me your math. Why not discuss it with the broadcast engineer You mean some guy who learned electronics in the Navy and he 'knows all there is to know and what he don't know ain't worth knowin' anyway'? Your theory supposedly rises about all that! Now show us the math. with his long time service at switching on a transmitter every morning,every day plus turn the lights out. As Vanna White would say in defence of her salary status You have to know the alphabet I am getting ready to drop out of the conversation...the math please?- Hide quoted text - - Show quoted text - By all means drop out. Until somebody comes along and faults the math I am doomed to accept it. Please please do as you said, that you can handle the math and prove it in error so I can remove myself from this mess.Many have said they can but none have shown that they are capable Considering all the postings on this subject there must have been somebody who can actually do mathematics so why are they reluctant to come forward. Is the math really to difficult for the average student or is there some fear associated with it that imposes silence? We have college teachers among this group so certainly if it was in error they would be quick to say so. Doesn't their absence bother you? Just state that the math is in error as presented by Dr Davis and why then everything comes to a halt. The subject which is causing anger falls completely apart when that fact comes to light.You ask for the math and I give you the math, what's holding you up? Subject closed until the math is subjected beyond the past peer review which states that it is accurate and correct. Talk is just not capable of destroying the truth of mathematics. |
Distributed capacitance and antennas
Art wrote:
"Talk is just not capable of destroying the truth of mathematics." Math is an exact tool. A product owes more to the expertise of the artist than it does to the tools he uses. Best regards, Richard Harrison, KB5WZI |
Distributed capacitance and antennas
On Sun, 11 Nov 2007 13:05:05 -0800, art wrote:
Please please do as you said, that you can handle the math and prove it in error Tsk, tsk, Arthur, You cannot do as you say, yourself! Let's consider one of your "promises:" On Tue, 06 Nov 2007 11:04:38 -0800, art wrote: Shorten your post and just type one line. I Richard, can show the error of your mathematics Rr = 80 · pi² · (length/wavelength)² 73's Richard Clark, KB7QHC |
Distributed capacitance and antennas
Stefan Wolfe wrote: "Roy Lewallen" wrote in message ... You've lost me. What is the meaning of a "time constant" in steady state? What effect does it have? With a single frequency of constant amplitude, how could you tell whether a circuit, resonant or not, has a "time constant"? How could you measure it? The meaning of a time constant is not dependent upon steady state sinusoids or transient; it is merely a characteristic that dependent upon the *physical* properties of the components in the circuit. You know that of course. Let us say we design a power supply for use in consumer appliances. The power supply of course has a capacitor across line and neutral for EMI filtering, along with a bleeder resistor in parallel with this capacitor. Together, the bleeder resistor and phase/phase capacitor filter have a time constant. Now the time constant is meaningless with respect to steady state input voltage (other than wave shaping high f emi components) and with respect to transients. It is meaningful with respect to safety. If the consumer pulls out the plug, the bleeder resistor must discharge the phase to phase cap safely to prevent the consumer from being shocked when touching the L-N pins. The time constant RC in this case MUST meet certain specifications, that is it must be less than 0.1sec. That is essentially required legally (since standard compliance is compulsory). The time constant exists is chosen for a worse case value, ie that the consumer unplugs the power supply at the peak of the AC cycle. Actually, it is the DC discharge characteristic that we care about here. Transient suppression is not relevant nor is its ability to shape the incoming sinusoid. Sorry, you've completely baffled me again. I can't find any relationship at all between what I asked and what you wrote. There's nothing more I can contribute, so I'll return the readers to their regularly scheduled programming. Roy Lewallen, W7EL |
Distributed capacitance and antennas
Art wrote:
"Same question, but now look at distributed inductaance and how that works!" On page 2 of Terman`s 1955 opus is written: "The strength of the wave mmeasured in terms of microvolts per meter of stress in space is also exactly the same voltage that the magnetic flux of the wave induces in a conductor 1 m long when sweeping across this conductor with the velocity of light." Remember reciprocity and the fact that only a perfectly matched antenna can extract as much as half the power in the wave. The antenna`s radiatiation resistance acts as a Thevenin source when receiving and reradiates the other half of the power received but not delivered to the load. The description of magnetic flux inducing signal into a receiving antenna may be the cause of describing transmitting antennas as creating from current in the wire a magnetic flux around the wire which almost simultaneously produces an electric field which almost simultaneously produces a magnetic field ad infinitum. Best regards, Richard Harrison, KB5WZI |
Distributed capacitance and antennas
On Sun, 11 Nov 2007 19:12:25 -0500, "Stefan Wolfe"
wrote: There is nothing in "time constant" that relates to frequency, transient rise time etc.. A Time Constant is also the -3dB point in a frequency response, hence there is a frequency relation. A Time Constant is proportional to square root of the rise time of a transient, hence there is a transient relation. It is not related. Ask any ham. That is my answer. Find a ham that knows the answers (and it isn't Art). 73's Richard Clark, KB7QHC |
Distributed capacitance and antennas
I spent a good part of my career as part of a team designing samplers,
step generators, TDR systems, and associated circuitry with rise times down to a few ps. Among the projects I designed were two delay line compensators which compensated for the distortion of a fast step by the skin effect loss in transmission lines (one to 2 GHz bandwidth and the other to 9, both to very high precision). These designs were used in production Tektronix instruments. I also often helped the customer support group with difficult TDR application problems, and I wrote and taught several classes on TDR techniques. One of the many skills necessary to succeed at this was to gain a very good understanding of rise times, time constants, frequency responses, the relationships among them, and the physical factors which influence them. From that background, the discussion in this newsgroup seems to be taking place in an alternate universe. I feel out of place there, so I'll leave it to its usual and rightful inhabitants, and bow out. Roy Lewallen, W7EL Everything should be made as simple as possible, but not simpler. -Albert Einstein |
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