![]() |
Superposition
K7ITM wrote:
On Nov 17, 4:03 pm, Cecil Moore wrote: The waves are launched by the external reflection from a Z0-match and the internal reflection from the load. So the waves are going opposite directions along the line?? No, all reflections travel toward the source and therefore, are traveling in the same direction. Their Poynting vectors are all toward the source. Given the following Z0-match impedance discontinuity in a transmission line with the source to the left and the load to the right: Z0-match ------Z01---+---Z02------ Pfor1-- Pfor2-- --Pref1=0 --Pref2 The power reflection coefficient is rho^2 = [(Z02-Z01)/(Z02+Z01)]^2 Pref1 is a combination of two reflected waves 1. P1 = Pfor1(rho^2) "the external reflection from the Z0-match" 2. P2 = Pref2(1-rho^2) "the internal reflection from the load" Pref1 = P1 + P2 + 2*SQRT(P1*P2)cos(A) Pref1 equals zero at a Z0-match so P1+P2 and A=180 deg. -- 73, Cecil http://www.w5dxp.com |
Superposition
Antonio Vernucci wrote:
The extra power measured at the receiver is obviously "created" at the expense of power taken away from other regions of the space (according to the transmit antenna pattern). Too fundamental to deserve further discussions! Almost everyone knows what occurs in free space - constructive interference in the direction of greater gain and destructive interference in the direction of lesser gain. But my posting was not about free space. I thank you for your input so far but please now extend those EM wave concepts to transmission lines. Everyone doesn't agree that constructive and destructive interference also happens at a Z0- match point in a transmission line with reflections. That is the topic that needs "further discussions". Just as constructive interference functions to increase antenna gain in one direction while destructive interference functions to decrease antenna gain in another direction, in a transmission line at a Z0-match point, constructive interference functions to increase the energy flow toward the load while destructive interference functions to decrease the energy flow toward the source. Antonio, please don't bow out now. You are apparently one of the few posters who fully understands interference. -- 73, Cecil http://www.w5dxp.com |
Superposition
On Sun, 18 Nov 2007 12:05:05 -0500, "Stefan Wolfe"
wrote: "Richard Clark" wrote in message .. . On Sun, 18 Nov 2007 00:16:47 -0500, "Stefan Wolfe" wrote: Let's rewind up that list of charades to revisit: Well, power is a vector quanity subject to the rules of vector math. and ponder the implication of a negative power, for simplicity: P1 = 50W @ 90deg P2 = 50W @ 270deg what does the math reveal? I am not trying to define power as negative with respect to zero Negative with respect to zero? What about with respect to positive? Or even a smaller negative! How about half negative (only 90 degrees shift instead of 180)? What happened to: Well, power is a vector quanity subject to the rules of vector math. I was so wanting to see your solution, much less how: Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A) migrated into the negated sine in: = (50 - 0) + (50 - 0) - 2SQRT P1*P2 sine(A) Oh God this is getting frustrating! You are lagging the community by at least 8 to 10 postings. http://math2.org/math/integrals/more/restrig.htm 1. See top equation. THE INTEGRAL OF A COSINE IS A SINE. What you published above is not the integral of the system and it has problems even in isolation. I added a minus sign, I shouldn't have BUT IT DOESN'T MATTER. As so many previous mistakes don't matter either. I also note (and I am full aware of the math) that YOUR reference (see top equation) solves with a constant added - as it should if this were a legitimate exercise. My students didn't get full credit for discarding constants, especially when they didn't have the vaguest notion of how these constants contribute to the outcome. Let me guess, you will say "it doesn't matter" with emphasis. :-) I think you are marginalizing your credibility with each succeeding post in which you dispute freshman caluclus fundamentals. Depending upon your education base, this could be quite a blow to you. I thought you knew math...maybe it was just me getting the wrong impression. Are you pulling our legs? Well, I did think I had mined this troll to completion, but another round may yet bring more fascinating entries. 73's Richard Clark, KB7QHC |
Superposition
Just as constructive interference functions to
increase antenna gain in one direction while destructive interference functions to decrease antenna gain in another direction, in a transmission line at a Z0-match point, constructive interference functions to increase the energy flow toward the load while destructive interference functions to decrease the energy flow toward the source. I cannot follow your reasoning as I cannot understand what is a "Z0-match point". In my understanding: - if the transmission line end is mismatched, in no point impedance can be equal to Z0. - conversely if the transmission line end is matched, impedance is equal to Z0 in all points. But there is no reflected wave and hence no energy flow toward the source Then, your "Z0-match point" must be something else which I cannot figure out. 73 Tony I0JX |
Superposition
Tony, I0JX wrote:
"Then, your "Zo-matchpoint" must be comething else which I cannot figure out." I`ll guess with Tony that in a made-up case of a 50-ohm antenna and a 50-ohm transmitter connected by a 1/2-wavelength of 300-ohm twinlead, we have a Zo-match to 50-ohms because the twin-lead, mismatched at both ends, still looks to source and load like 50-ohms. Best regards, Richard Harrison, KB5WZI |
Superposition
Antonio Vernucci wrote:
I cannot follow your reasoning as I cannot understand what is a "Z0-match point". A Z0-match is defined in my ARRL Antenna Book. Then, your "Z0-match point" must be something else which I cannot figure out. Here is an example of a Z0-match to 50 ohms at point '+': XMTR--50 ohm coax---+---1/2 WL 300 ohm feedline---50 ohm load The SWR on the 300 ohm feedline is 6:1. The SWR on the 50 ohm coax is 1:1. What happens to the energy and momentum of the reflected waves on the 300 ohm feedline? Seems obvious that there is destructive interference toward the XMTR and constructive interference toward the load. -- 73, Cecil http://www.w5dxp.com |
Superposition
On Sun, 18 Nov 2007 14:28:09 -0500, "Stefan Wolfe"
wrote: BTW the constant you saw has nothing to do with the equation at hand since we assume zerop power for that component at t = 0. An unemphatic "it doesn't matter!" :-) I could have made C =100, Hmmm, 0 is as good as 100? what must the value of C be in this equation? Ha! You are right, you have been away from math class too long. The value of the added C as the result of integration is unknown by definition. This constant is, after all, from your own reference supplied by you. Plugging in any value (including your fudge factor of 0) plucked from the air is invalid. Hardly the best way to demonstrate the conservation of energy (power, karma, the trade balance, or what-have-you). 73's Richard Clark, KB7QHC |
Superposition
A Z0-match is defined in my ARRL Antenna Book. Sorry, I have that book, but I do not remember where it is. Here is an example of a Z0-match to 50 ohms at point '+': XMTR--50 ohm coax---+---1/2 WL 300 ohm feedline---50 ohm load OK, understood. The SWR on the 300 ohm feedline is 6:1. The SWR on the 50 ohm coax is 1:1. What happens to the energy and momentum of the reflected waves on the 300 ohm feedline? Seems obvious that there is destructive interference toward the XMTR and constructive interference toward the load. I am not sure on whether I am able to correctly interpret your statement. My understanding is: - reflected power does not reach the transmitter, as it is fully reflected back toward the load - such re-reflected power reaches the load, where it is partially absorbed (thus contributing to the total power delivered to the load) and partially reflected back once more Probably this is what you call destructive interference at the trasmitter and constructive interference at the load. The fact that reflected power is fully re-reflected to the load does not seem to be appreciated by everyone. Many people still attribute their transmitter power transistors failure to reflected power burning them. The failure is instead clearly due to malfunctioning or poor design of the SWR protection circuit that: - does not keep the collector voltage within its maximum allowable value when load impedance is too high - does not keep the collector current and the junction temperature within their maximum allowable values when load impedance is too low 73 Tony I0JX |
Superposition
Cecil, W5DXP wrote:
"Antonio, please don`t bow out now." Why is a principle so trivial as superposition worth a thread in this newsgroup? Best regards, Richard Harrison, KB5WZI |
Superposition
Richard Harrison wrote:
Why is a principle so trivial as superposition worth a thread in this newsgroup? Because most of the posters to this newsgroup do not know what happens to the energy in the waves during superposition inside a transmission line. They seem to understand superposition in free space but not inside a transmission line. Maxwell's laws are the same for EM waves in free space and inside a transmission line. -- 73, Cecil http://www.w5dxp.com |
Superposition
On Sun, 18 Nov 2007 16:10:57 -0500, "Stefan Wolfe"
wrote: When integrating the actual equation at hand over its limits, the value of the constant does not matter because it always subtracts out. This is simply leaning on the Xerox to resuscitate a doomed method. We only have to consider that if this "logic" were applied to the actual equation (again, from you): Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A) = (50 - 0) + (50 - 0) - 2SQRT P1*P2 sine(A) That all terms would be rendered 0. After all, the two leading terms are constants too. Will we hear another chorus of "it doesn't matter?" :-) You are simply compounding errors. 73's Richard Clark, KB7QHC |
Superposition
On Sun, 18 Nov 2007 17:40:53 -0500, "AI4QJ" wrote:
This is funny. A chorus indeed. 73's Richard Clark, KB7QHC |
Superposition
On Sat, 17 Nov 2007 21:46:30 -0500, "Stefan Wolfe"
wrote: Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A) Hi Dan, Now let's return to this equation. It is drawn from the classic optics formula for finding the Intensity of radiation at a point in space that is illuminated by two sources. The intensity is a function of illuminators and their relative (at that point) phase. Phase can also be thought of as distance (which returns us to the point in space). As each path has a different length; then relative phase, their difference in length, is simplified by casting out all full cycles to leave only the remnant, or partial cycle. Of course, keeping count of the complete angular distances can be preserved, nothing will change in the result. A is a single value (as a point in space is 1D) and is expressed as that relative phase. A, thus in the world of all possible variations, can be any single value between 0 and 2·Pi radians. It follows that the cosine operation then renders a single value between +1 and -1. If you were to integrate this over some portion of time, or for all time; then it wouldn't change the answer one iota. The intensity of interference at a fixed spot in space from fixed illuminators does not change with time. If you were to integrate this over some portion of space, or for all space; then you would come up with different solutions. Across all space the intensity would become the sum of the two sources' illumination. There is no necessity of changing cos(A) to -sin(A) + C at all. There is no issue of unknown constants, the original intensities do not disappear. However, Integration does not resurrect Cecil's sucker punch. There is no missing power (energy, calories, what-have-you) as the question was tailored to an illusion that too many bought into. Lest we go 'round the mulberry bush on that again, please respond to my critique posted some time ago if you fault IT. 73's Richard Clark, KB7QHC |
Superposition
On Sun, 18 Nov 2007 20:22:21 -0500, "AI4QJ" wrote:
point to me to where it is? It is my first post to this thread, at level 2, responding directly to Dave. 2. You are saying that A is not a function of time. OK, OF COURSE that changes the appearance of the curve I was using. Still, the total energy expended over one cycle (can be thought of as phase angle - distance, not time), 0 to 2pi radians, is = zero As always, engineering is done by strict language. Look at your own. "Expended" energy is power. Integration of power over time will never result in no power unless no energy was "expended." (It is still valid to integrate and cancel out C ;-)) Over the full cosine power cycle, energy is still conserved, however the model is totally different. The model never changed, the consideration of superposition (partial solutions) may momentarily suspend us, but upon its completion the complete solution resolves to exactly what I've posted. Hence, there is no "missing" power (energy, etc.). Why didn't you mention that A was not a function of time before? Consider the genesis of the formula. It informs us all that this is a point location solution of total illumination from two remote sources. There is no need for me to create a shopping list of all the things this formula is NOT a function of. I am only trying to show conservation of energy which must hold true for any of these power formulas to be correct. And this equation still shows conservation of energy being true, even if A is the phase angle. If it is any different from what is not already in my post, feel free to elaborate. 73's Richard Clark, KB7QHC |
Superposition
On Sun, 18 Nov 2007 21:36:37 -0500, "AI4QJ" wrote:
"Richard Clark" wrote in message .. . On Sun, 18 Nov 2007 20:22:21 -0500, "AI4QJ" wrote: point to me to where it is? It is my first post to this thread, at level 2, responding directly to Dave. I can only handle one issue at a time (regarding what you said, it IS possible to have a zero net energy expenditure as long as energy that was sent out was received back again at a later time or at a different place; that is what the sine/cosine functions essentially tell you, whether they are functions of time or distance): Hi Dan, Well then, your concept of expended is quite different from most and flexible to the point of not really meaning much. So what is the point in using the word? Regarding: "Neither of these artificial conditions actually exist in the reality of superposed waves, and that is the con. The group has been fixated on the separate artificial environments with their partial solutions as though they actually exist independent of the reality of the superposed, complete solution." This is a bit philosophical for me but let me say that I believe that a square wave is definitely the sum of superimposed odd harmonics in accordance with Fourier. I believe each of the superimposed waves exists independently. If you do not believe me, just ask anyway who lives next door to a CB'er with a linear amp and transmits over modulated square waves (due to saturating his amplifier). The square waves exist but so do the component waves. I am not sure if this is related to what you are saying but it seems to be the same thing. I believe that cupiditas is the root of evil; however, both of our beliefs have nothing to do with partial solutions of Superposition posing as real world entities. 73's Richard Clark, KB7QHC |
Superposition
On Nov 18, 7:22 am, Cecil Moore wrote:
K7ITM wrote: On Nov 17, 4:03 pm, Cecil Moore wrote: The waves are launched by the external reflection from a Z0-match and the internal reflection from the load. So the waves are going opposite directions along the line?? No, all reflections travel toward the source and therefore, are traveling in the same direction. Their Poynting vectors are all toward the source. Given the following Z0-match impedance discontinuity in a transmission line with the source to the left and the load to the right: Z0-match ------Z01---+---Z02------ Pfor1-- Pfor2-- --Pref1=0 --Pref2 The power reflection coefficient is rho^2 = [(Z02-Z01)/(Z02+Z01)]^2 Pref1 is a combination of two reflected waves 1. P1 = Pfor1(rho^2) "the external reflection from the Z0-match" 2. P2 = Pref2(1-rho^2) "the internal reflection from the load" Pref1 = P1 + P2 + 2*SQRT(P1*P2)cos(A) Pref1 equals zero at a Z0-match so P1+P2 and A=180 deg. -- 73, Cecil http://www.w5dxp.com Ah, finally you get around to telling us the setup. So to get to the conditions in the original posting, we must have a total power coming into that Z01:Z02 junction exactly equal to the power leaving it. For example, if Z01 = 50 ohms as implied by your numbers, and Z02 = 100 ohms, barring stupid math errors, I make out that the left-to-right power on the Z01 line is 450 watts, and the right-to-left power on the Z02 line is 56.25 watts, for a total of 506.25 watts. Since you've only accounted for 171 watts, the remainder must be going off to the right from that junction. Change the phases, and the power will split differently. This seems to all agree with standard superpostion. So what the heck was the point of the original posting in this thread? Or, why do I even bother reading these things in the first place, since they all turn out to be pretty boring? Once again, we see that everything interesting going on in the system is happening right at the discontinuity where waves arrive and are reflected. Same in a Wilkinson combiner, same in a "magic T" (which I suppose the Wilkinson is, if you look at it the right way), same as in a resistive combining network (if you account for power dissipated in the resistors), ... |
Superposition
AI4QJ wrote:
. . . This is a bit philosophical for me but let me say that I believe that a square wave is definitely the sum of superimposed odd harmonics in accordance with Fourier. I believe each of the superimposed waves exists independently. If you do not believe me, just ask anyway who lives next door to a CB'er with a linear amp and transmits over modulated square waves (due to saturating his amplifier). The square waves exist but so do the component waves. I am not sure if this is related to what you are saying but it seems to be the same thing. This is indeed a philosophical question. A consequence of superposition is that there's *no possible way* to tell if a particular square wave is made from separately generated sinusoids, a single step, or combinations of any of an infinite number of other possible periodic waveforms. With the proper sorts of filters, you can take the square wave apart into any of those infinite sets of functions, "proving" the "independent existence" of each. Sinusoids are mathematically convenient, but they're by far not the only choice. Roy Lewallen, W7EL |
Superposition
Richard Clark wrote:
However, Integration does not resurrect Cecil's sucker punch. There is no missing power (energy, calories, what-have-you) as the question was tailored to an illusion that too many bought into. There's no illusion and no missing power, just interference at a point balanced by the opposite kind of interference somewhere else - just following the conservation of energy principle. It was a rhetorical question. -- 73, Cecil http://www.w5dxp.com |
Superposition
K7ITM wrote:
This seems to all agree with standard superpostion. So what the heck was the point of the original posting in this thread? Some posters deny that destructive interference is associated with zero reflected energy toward the source when a Z0-match exists. If you are not one of those posters, the thread was not aimed at you. -- 73, Cecil http://www.w5dxp.com |
Superposition
Antonio Vernucci wrote:
- reflected power does not reach the transmitter, as it is fully reflected back toward the load The re-reflection is associated with destructive interference toward the source and an equal magnitude of constructive interference toward the load. The energy in the canceled reflected waves is redistributed to a region that allows constructive interference to occur, i.e. in the opposite direction to the direction of reflected wave cancellation toward the source. Probably this is what you call destructive interference at the trasmitter and constructive interference at the load. At a Z0-match *point*, destructive interference *toward* the transmitter and constructive interference *toward* the load. It is akin to the passive elements of a Yagi causing destructive interference to the rear and constructive interference toward the front. What is the front/back ratio of a Z0-match? :-) -- 73, Cecil http://www.w5dxp.com |
Superposition
"Cecil Moore" wrote in message et... Richard Harrison wrote: Why is a principle so trivial as superposition worth a thread in this newsgroup? Because most of the posters to this newsgroup do not know what happens to the energy in the waves during superposition inside a transmission line. They seem to understand superposition in free space but not inside a transmission line. Maxwell's laws are the same for EM waves in free space and inside a transmission line. -- 73, Cecil http://www.w5dxp.com |
Superposition
"Sal M. Onella" wrote in message ... "Cecil Moore" wrote in message et... Richard Harrison wrote: Why is a principle so trivial as superposition worth a thread in this newsgroup? Because most of the posters to this newsgroup do not know what happens to the energy in the waves during superposition inside a transmission line. They seem to understand superposition in free space but not inside a transmission line. Maxwell's laws are the same for EM waves in free space and inside a transmission line. -- 73, Cecil http://www.w5dxp.com Sorry for the blank post, above, -- double-click-itis set in. I like 90% of these technical discussions. I'm a curious person by nature but I don't always know what doors to pull open, so it's nice when a good door is held open for me. 73 "Sal" (KD6VKW) |
Superposition
Sal M. Onella wrote:
I like 90% of these technical discussions. I'm a curious person by nature but I don't always know what doors to pull open, so it's nice when a good door is held open for me. It stands to reason that if interference is associated with a redistribution of EM wave energy in free space, essentially the same thing could happen in a transmission line. Incidentally, interference is also associated with the feedpoint impedance of a standing wave antenna. If the feedpoint impedance of a dipole is 50 ohms, that's a Z0 match to 50 ohm coax for an antenna supporting an SWR far in excess of 1:1. -- 73, Cecil http://www.w5dxp.com |
Superposition
On Nov 18, 7:40 am, Cecil Moore wrote:
Just as constructive interference functions to increase antenna gain in one direction while destructive interference functions to decrease antenna gain in another direction, in a transmission line at a Z0-match point, constructive interference functions to increase the energy flow toward the load while destructive interference functions to decrease the energy flow toward the source. Correction. The Z matching device functions to increase the energy flow toward the load and decreases the energy flow toward the source. Interference is just the mathematical description of the resulting spacial distribution. 73, ac6xg |
Superposition
Jim Kelley wrote:
Correction. The Z matching device functions to increase the energy flow toward the load and decreases the energy flow toward the source. Interference is just the mathematical description of the resulting spacial distribution. The decrease to zero in reflected energy flow toward the source is known as "total destructive interference" in the noun version of the word as used by Hecht. The increase in energy flow toward the load is known as constructive interference. One need not refer to superposition as the cause of interference since the interference *event* implies superposition of two (or more) coherent waves as the *cause* of the interference *process*. I am using "interference" as a noun synonymous with an "interference process" event, not as in "interference rings". The Z0-matching event cannot occur without an interference process (event). "Total destructive interference" as defined by Hecht is *necessary and sufficient* for a Z0-match to occur, i.e. if total destructive interference exists toward the source, a Z0-match has been achieved. From Websters: "interference - n. the *process* in which two coherent EM waves combine to reinforce or cancel each other." The reinforcing or canceling can be partial or total. Thus, I am using Hecht's noun definition of "interference" which "yields a resultant irradiance that deviates from the sum of the component irradiances". Reinforcement or cancellation is the *result* of that *process*. Superposition is the *cause* of that *process*. The *result* of the interference *process* is sometimes wave cancellation if the appropriate conditions exist. That's what happens at a Z0-match. The interference pattern of an antenna is the *result* of the interference *process*. Hecht says interference "corresponds" to the "interaction" of two or more coherent EM waves "yielding a result ...". He clearly considers interference to be in the cause and effect chain of events, as do I. -- 73, Cecil http://www.w5dxp.com |
Superposition
"Antonio Vernucci" wrote in message ... ................ If you instead put your receiver/antenna in a point where the two waves have equal amplitude and same phase, your receiver will measure 200 joules/s (i.e. four times the power produced by each wave alone, not just two times). ..................... 73 Tony I0JX You know that can't be right, because combining two antennas gives 3 db gain. For example, if you connect them in series, you will get twice the voltage, but the impedance also doubles. Tam |
Superposition
Richard Clark wrote:
On Sat, 17 Nov 2007 17:16:11 -0500, "Stefan Wolfe" wrote: snip Then I am sure you will agree that using terms like "taking Cecil's sucker bait" is not the type of "strict language" and "solid logic" appropriate in a technical forum. In fact, it is in the strictest language par excellence! Strict allows for no wiggle room, nothing nebulous. You completely understood what it meant and technical forums are assaulted with a lot of bankrupt theories- sometimes innocently offered, but not in this case. You might complain of style, but not substance. That made me think of a paper that I read a few years ago that summarized: "There would appear to be the possibility of a potential correlation..." Talk about going out on a limb! - 73 de Mike N3LI - |
Superposition
Tam/WB2TT wrote:
"Antonio Vernucci" wrote in message ... ............... If you instead put your receiver/antenna in a point where the two waves have equal amplitude and same phase, your receiver will measure 200 joules/s (i.e. four times the power produced by each wave alone, not just two times). You know that can't be right, because combining two antennas gives 3 db gain. For example, if you connect them in series, you will get twice the voltage, but the impedance also doubles. The constructive interference in free space occurs before the antennas, not after them. Such is the nature of constructive interference which very few posters fully understand. My original posting was designed to expose the beauty of constructive interference. Instead, I was accused of diverting the issue or worse. But it's simply a fact of physics - total constructive interference between two equal amplitude waves results in four times the amplitude of each wave. Of course, the result somewhere else is total destructive interference, i.e. complete absence of energy. No one can fully understand what happens at a Z0-match point without an understanding of interference. -- 73, Cecil http://www.w5dxp.com |
Superposition
Cecil Moore wrote:
Jim Kelley wrote: Correction. The Z matching device functions to increase the energy flow toward the load and decreases the energy flow toward the source. Interference is just the mathematical description of the resulting spacial distribution. The decrease to zero in reflected energy flow toward the source is known as "total destructive interference" in the noun version of the word as used by Hecht. The increase in energy flow toward the load is known as constructive interference. One need not refer to superposition as the cause of interference since the interference *event* implies superposition of two (or more) coherent waves as the *cause* of the interference *process*. I am using "interference" as a noun synonymous with an "interference process" event, not as in "interference rings". The Z0-matching event cannot occur without an interference process (event). "Total destructive interference" as defined by Hecht is *necessary and sufficient* for a Z0-match to occur, i.e. if total destructive interference exists toward the source, a Z0-match has been achieved. From Websters: "interference - n. the *process* in which two coherent EM waves combine to reinforce or cancel each other." The reinforcing or canceling can be partial or total. Thus, I am using Hecht's noun definition of "interference" which "yields a resultant irradiance that deviates from the sum of the component irradiances". Reinforcement or cancellation is the *result* of that *process*. Superposition is the *cause* of that *process*. The *result* of the interference *process* is sometimes wave cancellation if the appropriate conditions exist. That's what happens at a Z0-match. The interference pattern of an antenna is the *result* of the interference *process*. Hecht says interference "corresponds" to the "interaction" of two or more coherent EM waves "yielding a result ...". He clearly considers interference to be in the cause and effect chain of events, as do I. Cecil, You are waaay too concerned with philosophical words like *cause*, *process*, *result*, and *event*. There is no justification for saying that interference causes superposition or that superposition causes interference or any such combinations. Causality is a very important concept in physics, but it has no useful meaning in this situation. The way a physicist solves problems like this is to set up the equations in terms of generic sinusoidal functions with variable parameters. Then the boundary conditions of the problem are applied to determine precisely what the parameters must be. That's it. No worries about *why* something is happening or what is causing what. Those items are impossible to define in any case. If you were to read Born and Wolf you would find that they deal with the multiple interference problem (antireflective glass) in exactly the same manner. They never even mention constructive or destructive interference. There is a reason physicists use this type of problem solving method. It works for a entire range of boundary conditions. Try using your constructive/destructive interference technique when the problem is not quite so simple. For example, 3D problems when the incidence angles are not so tidy, materials with absorption, or multiple films such as those used in *real* AR coatings. You might muddle through with some generic concept of constructive/destructive interference, but you won't be able to get a quantitatively useful answer. By the way, Born and Wolf must have been pretty well connected. It appears that they copied the multiple reflection lattice diagram from your web page. 8-) 73, Gene W4SZ |
Superposition
Tam/WB2TT wrote:
"Antonio Vernucci" wrote in message ... ............... If you instead put your receiver/antenna in a point where the two waves have equal amplitude and same phase, your receiver will measure 200 joules/s (i.e. four times the power produced by each wave alone, not just two times). ..................... 73 Tony I0JX You know that can't be right, because combining two antennas gives 3 db gain. For example, if you connect them in series, you will get twice the voltage, but the impedance also doubles. If you supply your power to two identical antennas instead of one, each antenna gets half the power. If there's no mutual coupling between the antennas (seldom actually true), then each then produces 0.7071 times the field strength that the original antenna did, because each is getting half the original power. At the points where the fields from the two antennas completely reinforce, the sum of the fields is 0.7071 + 0.7071 = 1.4142 times the field produced by the original antenna. This is a field strength gain of 3 dB compared to the original antenna, and it's a field strength gain, as Antonio says, of 2 (6 dB) compared to the field produced by each of the two antennas. Your comments about impedance and voltage makes me wonder if maybe you're confusing feedpoint voltage with field strength. If you connect two antennas in series and supply the same total power as you did with one, both the current and the voltage of each will be 0.7071 times the values the single antenna had. Again, though, all this assumes no mutual coupling between the antennas, which is seldom true. Roy Lewallen, W7EL |
Superposition
Cecil Moore wrote: Hecht says interference "corresponds" to the "interaction" of two or more coherent EM waves "yielding a result ...". I know from corresponding with you for many years that what someone says, and what you understand them to say are not necessarily the same thing. In instances such as this you apparently take whatever meaning you wish from the words. Interference is not the particular kind of "process" that you have in mind. There are many meanings to the words 'interaction' and 'process'. In the case of wave interference , the words do mean that waves are 'doing things' to other waves. 73, ac6xg |
Superposition
Cecil Moore wrote:
The constructive interference in free space occurs before the antennas, not after them. Such is the nature of constructive interference which very few posters fully understand. My original posting was designed to expose the beauty of constructive interference. Cecil, That's the best line of the month. Can you help out with the Hollywood writer's strike? Leno and Letterman need some help. 73, Gene W4SZ |
Superposition
Gene Fuller wrote:
There is no justification for saying that interference causes superposition or that superposition causes interference or any such combinations. That's really good because I didn't say anything like that. Please don't try to imply that I did. Superposition can occur with or without interference. Interference can occur with or without wave cancellation. If you were to read Born and Wolf you would find that they deal with the multiple interference problem (antireflective glass) in exactly the same manner. They never even mention constructive or destructive interference. I've moved and can't find my Born and Wolf but Hecht certainly holds constructive/destructive interference in central position in his classic book. He devotes an entire chapter to interference. -- 73, Cecil http://www.w5dxp.com |
Superposition
Gene Fuller wrote:
Cecil Moore wrote: The constructive interference in free space occurs before the antennas, not after them. Such is the nature of constructive interference which very few posters fully understand. My original posting was designed to expose the beauty of constructive interference. That's the best line of the month. Can you help out with the Hollywood writer's strike? Leno and Letterman need some help. It's in Born and Wolf, Gene. Too bad you missed it. Two one watt coherent waves combine with total constructive interference to a four watt wave. Of course, somewhere else they combine with total destructive interference to a zero watt wave so the average power remains at two watts. -- 73, Cecil http://www.w5dxp.com |
Superposition
Jim Kelley wrote:
In the case of wave interference , the words do mean that waves are 'doing things' to other waves. Thanks Jim, that is exactly what I have been saying for years. For ideal non-reflective thin-film coatings on glass, waves are indeed doing things to other waves, i.e. canceling them. -- 73, Cecil http://www.w5dxp.com |
Superposition
Cecil Moore wrote: Jim Kelley wrote: In the case of wave interference , the words do mean that waves are 'doing things' to other waves. That should read "In the case of wave interference , the words don't mean that waves are 'doing things' to other waves." Thanks for pointing out the typo, Cecil. 73, ac6xg |
Superposition
Roy Lewallen wrote:
At the points where the fields from the two antennas completely reinforce, the sum of the fields is 0.7071 + 0.7071 = 1.4142 times the field produced by the original antenna. This is a field strength gain of 3 dB compared to the original antenna, and it's a field strength gain, as Antonio says, of 2 (6 dB) compared to the field produced by each of the two antennas. That's an example of constructive interference. At the points where the fields from the two antennas are equal and 180 degrees out of phase, the sum of the fields is zero. That's the necessary destructive interference on the flip side of the coin that satisfies the conservation of energy principle. Essentially the same thing happens at a Z0-match in a transmission line. -- 73, Cecil http://www.w5dxp.com |
Superposition
Jim Kelley wrote:
That should read "In the case of wave interference , the words don't mean that waves are 'doing things' to other waves." If waves are not 'doing things' to other waves, how are reflected waves eliminated by thin-films on glass? What happens to the reflection from the thin-film which has a reflectance of 0.01? If something is not done to that real reflection, it must still be there, but we can see that it is not there. -- 73, Cecil http://www.w5dxp.com |
Superposition
Cecil Moore wrote:
Gene Fuller wrote: There is no justification for saying that interference causes superposition or that superposition causes interference or any such combinations. That's really good because I didn't say anything like that. Please don't try to imply that I did. Superposition can occur with or without interference. Interference can occur with or without wave cancellation. Cecil, Your exact words we The decrease to zero in reflected energy flow toward the source is known as "total destructive interference" in the noun version of the word as used by Hecht. The increase in energy flow toward the load is known as constructive interference. One need not refer to superposition as the cause of interference since the interference *event* implies superposition of two (or more) coherent waves as the *cause* of the interference *process*. # Is this not written in English? # Is there some other interpretation of *cause* in the last sentence? # Just what do you mean by, "superposition of two (or more) coherent waves as the *cause* of the interference *process*"? # Are you playing some sort of word game by using *event* and *process*? # Do you have a reference for the rules of that word game? 73, Gene W4SZ |
Superposition
Cecil Moore wrote:
Gene Fuller wrote: Cecil Moore wrote: The constructive interference in free space occurs before the antennas, not after them. Such is the nature of constructive interference which very few posters fully understand. My original posting was designed to expose the beauty of constructive interference. That's the best line of the month. Can you help out with the Hollywood writer's strike? Leno and Letterman need some help. It's in Born and Wolf, Gene. Too bad you missed it. Two one watt coherent waves combine with total constructive interference to a four watt wave. Of course, somewhere else they combine with total destructive interference to a zero watt wave so the average power remains at two watts. Cecil, Sorry. I missed it because it is not there. They don't say any such thing. 73, Gene W4SZ |
All times are GMT +1. The time now is 06:23 PM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
RadioBanter.com