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![]() "Cecil Moore" wrote in message et... The following is from an email to which I replied today. Given two coherent EM waves superposed in a 50 ohm environment at considerable distance from any source: Wave#3 = Wave#1 superposed with Wave#2 Wave#1: V = 50v at 0 deg, I = 1.0a at 0 deg, P = 50 joules/sec Wave#2: V = 50v at 45 deg, I = 1.0a at 45 deg, P = 50 joules/sec These two waves superpose to V = 92.38v and I = 1.85a Note: P = 171 joules/sec *During each second*, Wave#1 supplies 50 joules of energy and Wave#2 supplies 50 joules of energy for a total of 100 joules of energy being supplied *every second* to the superposition process. Yet the results of that superposition process yields 171 joules of energy *during each second*, 71 joules more than is being supplied to the process. Where are the extra 71 joules per second coming from? -- 73, Cecil http://www.w5dxp.com Cecil Congratulations, you appear to have solved the world's energy problems for ever! Electricity will now be too cheap to meter, just like they promised when nuclear power plants were first built. Mike G0ULI |
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