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Antonio Vernucci wrote:
But if both waves are sumultaneouly present, the power carried by each wave when alone is no longer a meaningful number. Why is the ExB Poynting vector of each wave no longer proportional to the energy content? Why does the energy content of the component waves have to change when they superpose? Where does that energy change go? Do the necessary joules disappear and/or appear from thin air? As a matter of fact when superposing two coherent waves (same frequency, fixed phase relationship), one MUST first sum voltages (or currents) and then calculate power. That's what I did and the result was 171 joules/sec. The Poynting vector for each of the two source waves is 50 joules/sec. Why is the energy content of the component waves not a meaningful number? Summing wave powers could only be done in case of incoherent waves. No, there is a special equation to be used for summing coherent waves, i.e. the irradiance equation from optical physics. For power density: Ptotal = P1 + P2 + 2*SQRT(P1*P2)cos(A) where 'A' is the angle between the two E-fields. In conclusion, the answer to your question is that the apparent extra 71 joules/s come front the fact that 100 joules/s taken as reference is a number having no physical meaning. For every second that passes, 50 + 50 = 100 joules has no physical meaning? Are you saying that an EM wave is not associated with ExB joules/sec? -- 73, Cecil http://www.w5dxp.com |
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