On Sun, 18 Nov 2007 20:22:21 -0500, "AI4QJ" wrote:

point to me to where it is?
It is my first post to this thread, at level 2, responding directly to
Dave.

2. You are saying that A is not a function of time. OK, OF COURSE that
changes the appearance of the curve I was using. Still, the total energy
expended over one cycle (can be thought of as phase angle - distance, not
time), 0 to 2pi radians, is = zero

As always, engineering is done by strict language. Look at your own.
"Expended" energy is power. Integration of power over time will never
result in no power unless no energy was "expended."

(It is still valid to integrate and
cancel out C ;-)) Over the full cosine power cycle, energy is still
conserved, however the model is totally different.

The model never changed, the consideration of superposition (partial
solutions) may momentarily suspend us, but upon its completion the
complete solution resolves to exactly what I've posted. Hence, there
is no "missing" power (energy, etc.).

Why didn't you mention
that A was not a function of time before?

Consider the genesis of the formula. It informs us all that this is a
point location solution of total illumination from two remote sources.
There is no need for me to create a shopping list of all the things
this formula is NOT a function of.

I am only trying to show conservation of energy which must hold true for any
of these power formulas to be correct. And this equation still shows
conservation of energy being true, even if A is the phase angle.

If it is any different from what is not already in my post, feel free
to elaborate.

73's
Richard Clark, KB7QHC