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#911
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Dave wrote:
if the frequency is fixed, is sinusoidal, and steady state, then every box that measures -j567 ohms is perfectly equal. If the goal is to measure the phase shift at an impedance discontinuity in a transmission line, why would someone deliberately put the impedance discontinuity inside a black box? That defeats the goal of measuring the phase shift. -- 73, Cecil http://www.w5dxp.com |
#912
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#913
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Roy Lewallen wrote:
Let me reiterate that the contents of the boxes can certainly be distinguished with tests made at multiple frequencies. But the objective of my comments has been to counter the claim that there's some terminal property such as "electrical degrees" which the various lines (box contents) have which is different at the single frequency at which their reactances are the same. I hear this claim still being made, but so far not any evidence to support it. I provided the evidence in the thread titled, "Please verify (or disprove)". You have yet to respond to it. Here's your chance to nail me to the wall for good, Roy. Why are you so silent on that thread? -- 73, Cecil http://www.w5dxp.com |
#914
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On Thu, 20 Dec 2007 18:21:28 -0600, Cecil Moore
wrote: Why Everyone knows "why" but you, apparently. This has been explained many times, and quite clearly with a very simple explanation. No theory is involved, no proofs required, no data needs to be offered, a simple statement has resolved "why" a loooooooong time ago. Ask "why" again. Confirm the stereotype and pick up the doorprize. ;-) |
#915
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Roy Lewallen wrote:
When such evidence (not including typical Cecil-style hand-waving, but real numbers) is presented, I'll be glad to point out where it's in error. OK Roy, here's your chance. From the previous example: --43.4 deg 600 ohm line--+--10 deg 100 ohm line--open Vfor1--|--Vfor2 Vf--| Vref1--|--Vref2 Vr--| Given Vf = 100 volts at 0 deg. Vfor2 = 100 volts at -10 deg Vref2 = 100 volts at +10 deg Vfor2 = tau1*Vfor1 + rho2*Vref2 = 100 volts at -19 deg Solving for Vfor1 = 143.33 volts at -46.6 degrees Vref1 = rho1*Vfor1 + tau2*Vref2 = 143.33 volts at +46.6 deg Note that the two above equations are equivalent to the s-parameter equations: b1 = s11*a1 + s12*a2 and b2 = s21*a1 + s22*a2 -- 73, Cecil http://www.w5dxp.com |
#916
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Cecil Moore wrote:
Vfor2 = tau1*Vfor1 + rho2*Vref2 = 100 volts at -19 deg Obvious Typo: should be 100 volts at -10 deg -- 73, Cecil http://www.w5dxp.com |
#917
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AI4QJ wrote:
"Cecil Moore" wrote in message ... wrote: It isn't just "any" -j567 ohm impedance that can cause resonance with a 43 degree 600 ohm line. Dan, I believe you will find that any -j567 impedance in the black box will put the forward and reflected waves back in phase, i.e. resonant. OK but if you can measure Zo of whatever is in the box, then you know the length by virtue of it being -j567. It should only take 2 terminals to measure Zo. Knowing Zo, then I can normalize the smith chart and directly read the electrical length in degrees. True, it would help to know that the box contains a transmission line. The "other side" will not allow you to assume a transmission line. The "other side" will not even allow you four terminals on your black box. The entire purpose of the black box, in this present context, is to confuse and confound the unwashed masses so the "other side" can maintain their guru status. -- 73, Cecil http://www.w5dxp.com |
#918
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On Dec 20, 11:35*am, Cecil Moore wrote:
Keith Dysart wrote: On Dec 20, 11:02 am, Cecil Moore wrote: Michael Coslo wrote: Just a phase they are going through............. Exactly what is the reference for that phase? :-) Fire hydrant. Hey Keith, have you been able to disprove my figures in my other thread "Please verify (or disprove)"? If not, why not? Seems it would be an ideal time to nail me to the wall with some math that disagrees with mine. Your math is typically fine (although you messed up big time with your use of "reference"), when you allow yourself to use it. It is the interpretations, conclusions, and allocations of importance that are flawed. But now that you have declared black boxes a conspiracy to hide "the facts", I'm thinking maybe you should go join the MI5 guy. Anyway, along the way you learned (or maybe already knew and just articulated) that the effect on the 600 ohm line is the same regardless of the content of the black box producing -j567, and for the black boxes, the phase shift at the terminals is undecidable. And since the problem can be solved without this information, it is also irrelevant. A bit of progress. ...Keith 8 to go. |
#919
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Keith Dysart wrote:
Your math is typically fine ... Aha, so you agree that there is a 36.6 degree phase shift between Vfor1 and Vfor2? That is certainly progress. Now if you can only convince the gurus. But now that you have declared black boxes a conspiracy to hide "the facts", I'm thinking maybe you should go join the MI5 guy. I didn't say all black boxes are a conspiracy to hide the facts. But consider that when the goal is to measure the phase shift at an impedance discontinuity and someone insists on putting the impedance discontinuity inside a black box where the phase shift cannot possibly be measured, then that person desperately wants to keep the results from that measurement from being known. Anyway, along the way you learned (or maybe already knew and just articulated) that the effect on the 600 ohm line is the same regardless of the content of the black box producing -j567, There was never any argument there so that statement is just a straw man - go ahead and knock it down and get it over with. Nobody disagrees with you. and for the black boxes, the phase shift at the terminals is undecidable. And since the problem can be solved without this information, it is also irrelevant. The phase shift at the impedance discontinuity *CANNOT* be solved without information about the impedance discontinuity. Exactly what is it that you are so afraid that someone is going to discover? The technical facts? You already admitted that my calculations were accurate and valid. What more could you possibly want to hide? -- 73, Cecil http://www.w5dxp.com |
#920
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On Thu, 20 Dec 2007 21:09:53 -0500, "AI4QJ" wrote:
But I am only trying to find out what is in the box so it is a mental exercize. Hi Dan, Then you have missed the entire point. I know it is a transmission line, open, and the impedance at 4MHz is -j567. You know? Then why try to find out? This is a contradiction on the face of it. And what if it is not what you know it to be, and it still presents -j567 at 4MHz? If Zo for example were 100 Ohms, then -j567 would correspond to -j5.67 on a smith chart normalized to 100 ohms and it is 10 degrees long. If indeed! What electrical length corresponds to -j567 if Zo measures 200 ohms? 300 ohms? They will all be different right? Of course, any one of an infinite number of different possible contents could reside within the box; but you don't know which one is inside the box unless you look. This reminds me of an argument I had with a Chief Boatswain's Mate when I challenged him that "you can't make a horse drink water." His (like Cecil's) solution was: "You hold his head under water and suck on his ass!" I hear this particular solution has been used to solve an unrelated problem: a way of curing chapped lips (it keeps you from licking them). The better part of the members here use chapstick. 73's Richard Clark, KB7QHC |
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