Home |
Search |
Today's Posts |
|
#1
![]() |
|||
|
|||
![]()
Walter Maxwell wrote:
It appears to me that even with all the successive posts on the subject of power in the standing wave, you all seem to be missing the ingredient that proves why there is no useable power in the standing wave. It is because the current and voltage in the standing wave are 90° out of phase. Multiplying E x I under this condition results in zero power. In addition to another comment above that implies that reflected power is reactive power, this is not true--reflected power is as real as forward power. The only differences are that they are traversing in opposite directions, and that while the voltage and current travel in phase in the forward direction, they are traveling 180° out of phase in the rearward direction. Multiplying voltage and current while 180° different in phase results in the same power as when they are in phase. Seems to me everything would be made clear by the addition of the word "net". There is no net power in pure standing waves. There is no net energy transfer in pure standing waves. -- 73, Cecil http://www.w5dxp.com |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Standing Wave Phase | Antenna | |||
Standing wave on feeders | Antenna | |||
Dipole with standing wave - what happens to reflected wave? | Antenna | |||
Newbie ?: I've Built A Simple 1/4 Wave Dipole for 2 Mtrs. Could IMake a1/2 Wave? | Homebrew | |||
What is a traveling-wave antenna? | Antenna |