Cecil Moore wrote:
Roy Lewallen wrote:
These aren't "standing wave" voltage, current, and power, but simply
the total voltage and current, and the power, at that point.

Good Grief, Roy, no wonder you are clueless about standing
waves. In a lossless open-circuit line, the total voltage and
current *ARE* the standing-wave voltage and current because
traveling wave current and voltage doesn't exist. Good Grief!

Hmmm, Like Roy, I thought there was still a traveling wave in this
situation. The voltage at the far end of the line must reverse polarity
as time passes, so the waves must continue to travel, or so I would think.

Maybe it could be said better, but I thought Roy was trying to say that
although power could not be detected at the center or ends, it was
flowing as a result of the initial impetus charged into the system. I
would understand that this power would be the power needed to charge the
impedance and capacity of the line as it continually reversed polarity.
This would be real power from energy stored (but constantly moving) on
the 1/2 wavelength line so long as the system is active. We know we
have power present because we find energy distributed as V and I on the
time plot (viewed as a "standing wave" on the time plot).

Is this a "tongue-in-cheek" comment?

73, Roger, W7WKB