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On Jan 2, 2:59*am, Richard Clark wrote:
On Tue, 1 Jan 2008 18:44:17 -0800 (PST), Keith Dysart wrote: Since the experiment ends before the reflection returns to the generator, Is it a step, or is it a pulse? As stated, a step. Makes a huge difference in the analysis. the impedance of the generator is irrelevant. The impedance perhaps, but not the voltage. *I specifically offered a difference of sources (Norton vs. Thevenin). *The impedance is the same either way, the voltage is not. *As you introduce power later in this response, power at the source is even more contentious. *As such, we can drop this altogether. The generality of the specified voltage (V) would seem to adequately cover both the Thevenin and Norton generators. Ah. The challenge of written precisely. Consider the generator to be on the left end of the line and the open to be at the right end. When the capacitance at the right end charges to 2 * V, the current now has to stop a little bit more to the left. Still doesn't make sense, and I wouldn't attribute it to precision seeing that you've written the same thing twice. Given your previous writings, I suspect that you have a solid understanding of the behaviour of an open-circuited transmission line excited with a step function. Perhaps you could make an attempt at writing a clear description of the behaviour of such a system in terms of charge flow and storage. Since "wave" is a word overloaded with meanings, it would be good not to use it in the description. Once a clear description exists, I can extend it using the same clear terminology to illustrate the points of interest. ...Keith |
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