On Jan 2, 8:39*am, Cecil Moore wrote:
Keith Dysart wrote:
It happens without effort because the output impedance
of the Norton/Thevenin equivalent circuit is the same
as the circuit it replaces, otherwise it is not an
equivalent.

False. There can be a large difference in the output
impedance of an amplifier designed to drive a 50 ohm
load and a 50 ohm Thevenin equivalent circuit.

Then your Thevenin circuit is not an equivalent
for the amplifier, is it?

Please study "equivalent circuit" and report back.

...Keith