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#1
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Keith Dysart wrote:
In a stub driven with a step function, where is the energy stored? Depends upon which valid model one is using. 1. Reflection Model - the energy is stored in the forward and reflected traveling waves. 2. The LCLCLC transmission line model - the energy is alternately stored in the L's and C's. 3. The Sloshing Model - I'll let Roy handle that one. -- 73, Cecil http://www.w5dxp.com |
#2
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On Jan 2, 3:44*pm, Cecil Moore wrote:
Keith Dysart wrote: In a stub driven with a step function, where is the energy stored? Consider the state of the open circuited line after settling. Depends upon which valid model one is using. 1. Reflection Model - the energy is stored in the forward and reflected traveling waves. So it is stored only in the E field. Is it an EM wave when only an E field is present? 2. The LCLCLC transmission line model - the energy is alternately stored in the L's and C's. Since there is no current, it is stored only in the capacitance of the line. 3. The Sloshing Model - I'll let Roy handle that one. The sloshing has stopped, so the answer is the same as 2. But the important question is: Do you consider it to be an EM wave when only an E field is present? ...Keith |
#3
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Keith Dysart wrote:
Cecil Moore wrote: 1. Reflection Model - the energy is stored in the forward and reflected traveling waves. So it is stored only in the E field. Wrong! Please reference a book on EM waves. An EM wave CANNOT have a stationary E-field in an ordinary transmission line or in free space. But the important question is: Do you consider it to be an EM wave when only an E field is present? No, that violates the definition of an EM wave. If only an E-field is present in a transmission line or in free space, it is NOT an EM wave, by definition. For a single EM wave to exhibit a zero H-field, the Z0 would have to be infinite which is clearly impossible for free space or ordinary transmission lines. -- 73, Cecil http://www.w5dxp.com |
#4
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On Jan 3, 12:43*pm, Cecil Moore wrote:
Keith Dysart wrote: Cecil Moore wrote: 1. Reflection Model - the energy is stored in the forward and reflected traveling waves. So it is stored only in the E field. Wrong! Please reference a book on EM waves. An EM wave CANNOT have a stationary E-field in an ordinary transmission line or in free space. But the important question is: Do you consider it to be an EM wave when only an E field is present? No, that violates the definition of an EM wave. If only an E-field is present in a transmission line or in free space, it is NOT an EM wave, by definition. For a single EM wave to exhibit a zero H-field, the Z0 would have to be infinite which is clearly impossible for free space or ordinary transmission lines. Good answers. Exactly as I expected. Now please explain the applicability of EM waves to the state of an open circuited line excited with a step function, especially after it settles to a constant voltage (where only an E field will be present). ...Keith |
#5
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Keith Dysart wrote:
Good answers. Exactly as I expected. Now please explain the applicability of EM waves to the state of an open circuited line excited with a step function, especially after it settles to a constant voltage (where only an E field will be present). Before it settles to a constant voltage, there is acceleration of electrons that results in an EM photonic wave. After it settles to a constant voltage, there is no acceleration of electrons and the EM photonic wave disappears. Please see Maxwell's equations for further enlightenment. -- 73, Cecil http://www.w5dxp.com |
#6
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On Jan 3, 2:15*pm, Cecil Moore wrote:
Keith Dysart wrote: Good answers. Exactly as I expected. Now please explain the applicability of EM waves to the state of an open circuited line excited with a step function, especially after it settles to a constant voltage (where only an E field will be present). Before it settles to a constant voltage, there is acceleration of electrons that results in an EM photonic wave. After it settles to a constant voltage, there is no acceleration of electrons and the EM photonic wave disappears. So when the edge of the step is travelling towards the right, is there an EM wave to the right of the step, to left of the step, at the step, or all three? Similar question for when the step is travelling back to the generator? When the line has settled, how do you add the forward and reflected wave to compute the voltage on the line, or does the disappearance of the wave mean this is now impossible? If only the step itself has an EM wave, how are voltages computed using reflection coefficient after the step has reflected from the open end? ...Keith |
#7
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Keith Dysart wrote:
So when the edge of the step is travelling towards the right, is there an EM wave to the right of the step, to left of the step, at the step, or all three? Similar question for when the step is travelling back to the generator? You are confusing cause and effect. There is an EM wave wherever there are photons being exchanged among the electrons. Any speed-of-light movement is evidence of the existence of photons. When the line has settled, how do you add the forward and reflected wave to compute the voltage on the line, or does the disappearance of the wave mean this is now impossible? After all the photons have been absorbed or radiated, there is no forward EM wave or reflected EM wave. They simply cease to exist in the DC steady-state where electrons are not being accelerated or decelerated. If only the step itself has an EM wave, how are voltages computed using reflection coefficient after the step has reflected from the open end? If the step is reflected, the reflection consists of photons. As long as anything is flowing at the speed of light in the medium, photons exist. -- 73, Cecil http://www.w5dxp.com |
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