On Jan 3, 1:48*pm, Cecil Moore wrote:
Keith Dysart wrote:
Can photons explain the state of a transmission
line driven with a step function after the line
has settled to a constant voltage?

Of course, photons can be used to explain all
EM wave action. A step function accelerates
electrons which then emit photons as EM waves.
Hint: electrons cannot move at the speed of
light. EM waves move at the speed of light.

Please describe the final state of the step
excited open circuited line using photons.

Thanks,

Keith

Keith Dysart wrote:
Please describe the final state of the step
excited open circuited line using photons.

Photons are emitted and absorbed by the electrons
as the electrons lose/gain energy. Photons are not
conserved. Only the energy in photons is conserved.

In a DC system with no accelerating or decelerating
electrons, all of the photons have been absorbed
back into the electrons (or lost to radiation).
Of course, this describes an ideal system.
--
73, Cecil http://www.w5dxp.com

On Thu, 3 Jan 2008 11:19:26 -0800 (PST), Keith Dysart
wrote:

Hint: electrons cannot move at the speed of
light. EM waves move at the speed of light.

I love these built-in failures of argument. :-)

Shine the sun on a pie pan. How fast is light moving in getting
through it? How fast is an electron moving in getting through it?

Is light traveling at the speed of light? Would it travel faster than
an electron if we took out the pie? Would it travel faster than an
electron if we kept the pie and took out the pan?

73's
Richard Clark, KB7QHC

Richard Clark wrote:
Shine the sun on a pie pan. How fast is light moving in getting
through it? How fast is an electron moving in getting through it?
Is light traveling at the speed of light? Would it travel faster than
an electron if we took out the pie? Would it travel faster than an
electron if we kept the pie and took out the pan?

There, there, Richard, everything is going to be OK.
(Somebody get the net!)
--
73, Cecil http://www.w5dxp.com