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Keith Dysart wrote:
So when the edge of the step is travelling towards the right, is there an EM wave to the right of the step, to left of the step, at the step, or all three? Similar question for when the step is travelling back to the generator? You are confusing cause and effect. There is an EM wave wherever there are photons being exchanged among the electrons. Any speed-of-light movement is evidence of the existence of photons. When the line has settled, how do you add the forward and reflected wave to compute the voltage on the line, or does the disappearance of the wave mean this is now impossible? After all the photons have been absorbed or radiated, there is no forward EM wave or reflected EM wave. They simply cease to exist in the DC steady-state where electrons are not being accelerated or decelerated. If only the step itself has an EM wave, how are voltages computed using reflection coefficient after the step has reflected from the open end? If the step is reflected, the reflection consists of photons. As long as anything is flowing at the speed of light in the medium, photons exist. -- 73, Cecil http://www.w5dxp.com |
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