Here's a request to anyone capable of performing the
necessary math. Can anyone verify or disprove my
two voltage values in the following example?

Shortened Stub Example:

rho = -0.7143
--43.4 deg 600 ohm line--+--10 deg 100 ohm line--open
Vfor1--|--Vfor2 Vi--|
Vref1--|--Vref2

Assume the RMS voltage, Vi, incident upon the open
end of the stub is: Vi = 100 volts at 0 degrees

At point '+' 10 degrees back from the open,
Vfor2 = 100 volts at -10 degrees
Vref2 = 100 volts at +10 degrees

Vfor1 = 143.33 volts at -46.6 degrees
Vref1 = 143.33 volts at +46.6 degrees

The phase shift between Vfor1 and Vfor2 is 36.6 degrees.

The phase shift between Vref2 and Vref1 is 36.6 degrees.

The total RMS voltage at all points up and down the line
is 200 volts at 0 deg.
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73, Cecil http://www.w5dxp.com