![]() |
The Rest of the Story
OK Cecil. I understand that none of your discussion applies to instantaneous values, only average values.
I am examining Keith's spread sheet carefully. I found that Open Calc will open the spreadsheet so I can read Keith's cell directions. (Thanks for making the spread sheet available Keith.) I want to make sure that I fully understand what is happening here, to the best of my ability and time available. On Fri, 07 Mar 2008 12:13:45 -0600 Cecil Moore wrote: Roger Sparks wrote: On Fri, 07 Mar 2008 15:15:08 GMT Cecil Moore wrote: My formula applies *only to average power*. I find myself surprised at your insistance that the instantaneous case must be seperated from the average case in our example of waves on a transmission line. You have misunderstood what I am objecting to - which is: Please don't say or imply that I have said or implied anything about instantaneous values. I have NOT done so! The formulas and concepts being used in the discussion of instantaneous values are NOT mine! My objection is to the false statements being made about what I have posted. Please go ahead and have your instantaneous discussion with Keith but please don't say or imply that anything associated with that discussion is about anything I have posted. Saying or implying such a thing is simply false. It is informative to look at each problem from many angles. I agree - just stop saying that it is based on my assertions. You or Keith may be right or wrong but either way, it is not associated with anything I have posted. Please leave my name out of any discussion concerning instantaneous values. Did I misunderstand your premise, and you were really trying to say that the inclusion of a 50 ohm source resistor would prevent the source from ever 'seeing' anything but a 100 ohm load? I don't think that was your intent. Please add a dimension to your thinking. No matter what the value of the load resistor, the source delivers 100 watts. There are an infinite number of loads that the source could "see" besides 100+j0 ohms that will make that condition true. When the load is 0 ohms, the source "sees" 50+j50 ohms. When the load is 12.5 ohms, the source "sees" 73.5+j44.1 ohms. When the load is 25 ohms, the source "sees" 90+j30 ohms. Only when the load is 50 ohms, does the source "see" 100+j0 ohms. -- 73, Cecil http://www.w5dxp.com -- 73, Roger, W7WKB |
The Rest of the Story
On Mar 7, 12:14 pm, Cecil Moore wrote:
.... OK Tom, here's a challenge for you. The only thing more foolish than the "challenge" that followed that would be the person who accepted it. Since I don't suppose you think me a fool, I'll just ignore it. |
The Rest of the Story
On Mar 7, 2:34 pm, Gene Fuller wrote:
Cecil Moore wrote: K7ITM wrote: Certainly, those who design and build FTIR spectrometers know perfectly well that interference does not depend on a narrow-band coherent source. How narrow-band? How coherent? In the irradiance (power density) equation, Ptot = P1 + P2 + 2*sqrt(P1*P2)cos(A), if the angle 'A' is varying rapidly, what value do you use for cos(A)? A constant average sustained level of destructive interference cannot be maintained between two waves unless they are coherent. If they are not coherent the interference will average out to zero. Gee, I wonder if the experts may have moved beyond the elementary optics textbook descriptions? Are you suggesting that FTIR cannot work unless one has your nice 1-D configurations with perfectly monochromatic waves? Does everything need to be collinear and coherent? 73, Gene W4SZ So--I have a classic Michelson interferometer, and I see the classic ring pattern on the screen at the "output" port. I also have a sensitive microchannel plate detector system that I propose to put in place of the screen, so that I can reduce the light amplitude to where it makes sense to be observing it with the very sensitive detector. In fact, I propose to reduce the light level to the point that the short wavelength light I'm using is only putting a few photons per second into the interferometer. I'll count a significant fraction of those photons and identify where they landed on the microchannel plate. Do you suppose, Gene, that I'll still see the same interference pattern that I saw with the much higher intensity light? Is there any limit to how low a light level I can use and still see the pattern? If I do still see the pattern, there must be yet another "dimension" I need to add to my understanding of the situation -- not rooted in classical Maxwell e&m. And of course a dimension that is removed if you think only of average quantities is time; one who thinks only in terms of averages removes the possibility of the deeper understanding that resolution as a function of time allows. Cheers, Tom |
The Rest of the Story
Keith Dysart wrote:
You are *not* claiming that the *energy* from the reflected wave is dissipated in the source resistor, because for the *energy* in the reflected wave to be dissipated in the source resistor, the *energy* would have to dissipate at the same time that the reflected wave delivered the *energy*, and the analysis of instantaneous *energy* flows shows that this is not the case. I clearly stated that my claim is based on a special case zero interference condition - it's even in the title of the article. The instantaneous energy that you (not I) introduced, does not meet the zero interference precondition. Therefore, anything that does not meet the zero interference precondition that I enumerated is an irrelevant diversion. You introduced that irrelevant straw man and tried to make hay out it. :-) you are saying that the average reflected power is numerically equal to the increase in the average dissipation in the source resistor. I can accept that as correct. Finally, after a million words. :-) You might consider rewriting the sentence "reflected energy from the load is flowing through the source resistor, RS, and is being dissipated there" since it refers to the energy in the reflected wave and may mislead others in the same way it mislead me. Since "average reflected power" is dependent upon the "reflected energy", I don't see any problem. Would "average reflected energy" work for you? It should be obvious that, associated with interference during each cycle, destructive interference energy is stored during part of the cycle and delivered back as constructive interference energy during another part of the cycle. The intra-cycle interference averages out to zero. Many have objected to the term "reflected power" saying it is not power that is reflected but instead is "reflected energy". So I stopped talking about "reflected power" and started talking about "reflected energy". Now you object to the use of the term "reflected energy". Would you and the rest of the guru attack gang please get together on what term you would like for me to use? -- 73, Cecil http://www.w5dxp.com |
The Rest of the Story
Roger Sparks wrote:
OK Cecil. I understand that none of your discussion applies to instantaneous values, only average values. Indeed, instantaneous values are a diversion away from my discussion/article/example using average values. I am examining Keith's spread sheet carefully. I found that Open Calc will open the spreadsheet so I can read Keith's cell directions. (Thanks for making the spread sheet available Keith.) I want to make sure that I fully understand what is happening here, to the best of my ability and time available. Given the superposition of two voltages, when the two voltages have the same sign, constructive interference is present. When the two voltages have opposite signs, destructive interference is present. The destructive interference during each cycle exactly equals (and supplies) the constructive interference during the same cycle so the average interference is zero. -- 73, Cecil http://www.w5dxp.com |
The Rest of the Story
K7ITM wrote:
Cecil Moore wrote: OK Tom, here's a challenge for you. The only thing more foolish than the "challenge" that followed that would be the person who accepted it. Since I don't suppose you think me a fool, I'll just ignore it. Tom, you are the one who implied that coherency or incoherency doesn't matter. The challenge would have proved it doesn't matter. Since you refused the challenge, can we assume that it does matter? -- 73, Cecil http://www.w5dxp.com |
The Rest of the Story
K7ITM wrote:
On Mar 7, 2:34 pm, Gene Fuller wrote: Cecil Moore wrote: K7ITM wrote: Certainly, those who design and build FTIR spectrometers know perfectly well that interference does not depend on a narrow-band coherent source. How narrow-band? How coherent? In the irradiance (power density) equation, Ptot = P1 + P2 + 2*sqrt(P1*P2)cos(A), if the angle 'A' is varying rapidly, what value do you use for cos(A)? A constant average sustained level of destructive interference cannot be maintained between two waves unless they are coherent. If they are not coherent the interference will average out to zero. Gee, I wonder if the experts may have moved beyond the elementary optics textbook descriptions? Are you suggesting that FTIR cannot work unless one has your nice 1-D configurations with perfectly monochromatic waves? Does everything need to be collinear and coherent? 73, Gene W4SZ So--I have a classic Michelson interferometer, and I see the classic ring pattern on the screen at the "output" port. I also have a sensitive microchannel plate detector system that I propose to put in place of the screen, so that I can reduce the light amplitude to where it makes sense to be observing it with the very sensitive detector. In fact, I propose to reduce the light level to the point that the short wavelength light I'm using is only putting a few photons per second into the interferometer. I'll count a significant fraction of those photons and identify where they landed on the microchannel plate. Do you suppose, Gene, that I'll still see the same interference pattern that I saw with the much higher intensity light? Is there any limit to how low a light level I can use and still see the pattern? If I do still see the pattern, there must be yet another "dimension" I need to add to my understanding of the situation -- not rooted in classical Maxwell e&m. And of course a dimension that is removed if you think only of average quantities is time; one who thinks only in terms of averages removes the possibility of the deeper understanding that resolution as a function of time allows. Cheers, Tom Tom, One step at a time. Cecil has not yet accepted the real world in the classical state. The quantum state will need to wait. 8-) 73, Gene W4SZ |
The Rest of the Story
Gene Fuller wrote:
Cecil has not yet accepted the real world in the classical state. I know there is no such thing as a lossless transmission line, Gene. That doesn't prohibit me from using lossless transmission lines in an example, does it? Every textbook on transmission lines that I have ever seen does the same thing. -- 73, Cecil http://www.w5dxp.com |
The Rest of the Story
On Sat, 8 Mar 2008 10:12:04 -0800 (PST), K7ITM wrote:
Is there any limit to how low a light level I can use and still see the pattern? Hi Tom, The Quantum Efficiency of the eye is between 40% and 50%. The time to convert one photon in a visual receptor is roughly 14 femtoseconds. I have seen no component that can match the bandwidth, dynamic range, AND sensitivity of the eye. 73's Richard Clark, KB7QHC |
The Rest of the Story
On Sat, 08 Mar 2008 14:21:59 -0800, Richard Clark wrote:
On Sat, 8 Mar 2008 10:12:04 -0800 (PST), K7ITM wrote: Is there any limit to how low a light level I can use and still see the pattern? Hi Tom, The Quantum Efficiency of the eye is between 40% and 50%. The time to convert one photon in a visual receptor is roughly 14 femtoseconds. I have seen no component that can match the bandwidth, dynamic range, AND sensitivity of the eye. Side note: Back in the day, when I did a lot of color processing and printing, I would spend log hours in the darkroom in total darkness. The only light shedding items were the old Gra-Lab timers, and luminescent tape on the dangerous corners. After several hours, the light output from them was just about nil. My eyes were totally adapted, full visual purple. At this time, the luminescent tape and dials seemed to scintillate discretely, not the typical overall glow. I always wondered if I was possibly seeing individual photon effects. - 73 de Mike N3LI - |
All times are GMT +1. The time now is 03:01 PM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
RadioBanter.com