On Mar 7, 5:31*pm, Cecil Moore wrote:
Keith Dysart wrote:
My understanding of your claim was that for the special case of
a 45 degree line supplied from a matched source, the energy
in the reflected wave is dissipated in the source resistor.

I have told you time and again that your understanding is
wrong. My claim is that for the special case of a 45 degree
phase difference between the forward wave and reflected wave,
the *average* power in the reflected wave is dissipated in the
source resistor. Irradiance is an *average* power density as
defined by Hecht, in "Optics". I have told you previously (many
times) that when I use the word "power", I am talking about
*average* power. I agree with Hecht that instantaneous power
is "of limited utility" and is therefore mostly irrelevant.

For the record - for the umteenth time: When I say "power", I
am talking about "*average* power". If I ever talk about
instantaneous power, I will say "instantaneous power". If
you still don't understand, you need professional help.

This sentence fragment from your document suggests this:
"reflected energy from the load is flowing through the source
resistor, RS, and is being dissipated there".

I left no doubt as to what I meant in my document. Here is
a quote from the second paragraph in my document:
"Please note that any power referred to in this paper
is an *average power*. Nothing is being asserted or implied about
instantaneous powers. In fact, instantaneous powers are completely
irrelevant to the following discussion."

I simply don't know how to say it any plainer than that.

I really resent your lack of ethics in this matter.
If you are forced to create a Big Lie about what I have
said in order to try to win, is it really worth it?

OK. I think I've got it now.

You are *not* claiming that the *energy* from the reflected wave
is dissipated in the source resistor, because for the *energy*
in the reflected wave to be dissipated in the source resistor,
the *energy* would have to dissipate at the same time that the
reflected wave delivered the *energy*, and the analysis of
instantaneous *energy* flows shows that this is not the case.

Rather, you are saying that the average reflected power is
numerically equal to the increase in the average dissipation
in the source resistor.

I can accept that as correct.

You might consider rewriting the sentence "reflected energy
from the load is flowing through the source resistor, RS, and
is being dissipated there" since it refers to the energy in
the reflected wave and may mislead others in the same way it
mislead me.

...Keith