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Keith Dysart wrote:
Regardless, if you use the snippet above to support your claim, you have effectively modified your claim. False. My claim is what it has always been which is: An amateur radio antenna system obeys the conservation of energy principle and abides by the principles of superposition (including interference) and the wave reflection model. Everything I have claimed falls out from those principles. Your claims, however, are in direct violation of the principles of superposition and of the wave reflection model, e.g. waves smart enough to decide to be reflected when the physical reflection coefficient is 0.0. Your claims even violate the principles of AC circuit theory, e.g. a reactance doesn't store energy and deliver it back to the system at a later time in the same cycle. You are now saying that the reflected energy is dissipated in the source resistor only at particular times, such as when the source voltage is 0, and that you are not interested in what happens during the rest of the cycle. You haven't read my article yet, have you? Here's a quote: "For this *special case*, it is obvious that the reflected energy from the load is flowing through the source resistor, RS, and is being dissipated there. But remember, we chose a special case (resistive RL and 1/8 wavelength feedline) in order to make that statement true and it is *usually not true* in the general case." If there is one case where your assertion is wrong, then your assertion is false. I found that special case when the source voltage is zero that makes your assertions false. For example, if you were to do the same analysis, except do it for t such that wt equals 100 degrees, instead of 90, you would find that you need more terms than just Pr.g to make the energy flows balance. Yes, you have realized that destructive and constructive interference energy must be accounted for to balance the energy equations. I have been telling you that for weeks. I repeat: The *only time* that reflected energy is 100% dissipated in the source resistor is when the two component voltages satisfy the condition: (V1^2 + V2^2) = (V1 + V2)^2. None of your examples have satisfied that necessary condition. All it takes is one case to prove the following assertion false: "Reflected energy is *always* re-reflected from the source and redistributed back toward the load." You appear to think that if you can find many cases where an assertion is true, then you can simply ignore the cases where it is not true. I have presented some special cases where it is not true. It may be true for 99.9% of cases, but that nagging 0.1% makes the statement false overall. Equally false is the assertion: "Reflected energy is always dissipated in the source resistor." The amount of reflected energy dissipated in the source resistor can vary from 0% to 100% depending upon network conditions. That statement has been in my article from the beginning. So are you now agreeing that it is not the energy in the reflected wave that accounts for the difference in the heating of the source resistor but, rather, the energy stored and returned from the line, i.e. Pg(t)? I have already presented a case where there is *zero* power dissipated in the source resistor in the presence of reflected energy so your statement is obviously just false innuendo, something I have come to expect from you when you lose an argument. -- 73, Cecil http://www.w5dxp.com |
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