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On Apr 11, 9:25*am, Cecil Moore wrote:
Keith Dysart wrote: The computation using energy instead of power has also been done (and published here) and found also to demonstrate that the reflected is not dissipated in the source resistor. Well, that certainly violates the conservation of energy principle. We know the reflected energy is not dissipated in the load resistor, by definition. The only other device in the entire system capable of dissipation is the source resistor. Since the reflected energy is not dissipated in the load resistor and you say it is not dissipated in the source resistor, it would necessarily have to magically escape the system or build up to infinity (but it doesn't). You seem to have forgotten that a voltage source can absorb energy. This happens when the current flows into it rather than out. Recall the equation Ps(t) = Prs(t) + Pg(t) When the voltage source voltage is greatr than the voltage at the terminals of the line (Vg(t)), energy flows from the source into the resistor and the line. When the voltage at the line terminals is greater than the voltage source voltage, energy flows from the line into the resistor and the voltage source. At all times Ps(t) = Prs(t) + Pg(t) holds true. Conservation of energy at work. No lost energy. gartuitous comment snipped How many joules are there in 100 watts of instantaneous power? Obviously. It depends on how long you let the 100 W of instantaneous power flow. Integrate and the answer shall be yours. I'm not the one making the assertions. How many joules of energy exist in *YOUR* instantaneous power calculations? We have been down that path; the spreadsheet has been published. The flows of energy described by Ps(t) = Prs(t) + Pg(t) always balance. The integration of these energy flows over any interval also balance. Energy is conserved. The world is as it should be. ...Keith |
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