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#1
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On Apr 11, 3:30*pm, Cecil Moore wrote:
Roger Sparks wrote: You write "The only other device in the entire system capable of dissipation is the source resistor." which is a correct statement. Therefore, all power dissipated in the circuit must be dissipated in the load resistor and the source resistor because there is nowhere else for it to go. Please do not forget the source. It can absorb energy. Since the reflected power is not dissipated in the load, by definition, it has to be dissipated in the source resistor but not at the exact time of its arrival. There is nothing wrong with delaying power dissipation for 90 degrees of the cycle. If you can't identify where the energy is stored for those 90 degrees you do not have a complete story. Or you are violating conservation of energy and therefore have no story what-so-ever. In Parts 2 and 3 of my articles, I will show how the source decreases it power output to compensate for destructive interference and increases it power output to compensate for constructive interference. Unfortunately, the circuit is intended to illustrate the absence of [AVERAGE] interference under special circumstances but an instant analysis shows that all the power can not be accounted for. * Not surprising since there is no conservation of power principle. Conservation of energy means that energy flows must be conserved. Therefore, conservation of power. We can only conclude that [instantaneous] interference is present. Not good because the circuit was intended to illustrate a case of NO [AVERAGE] interference. I took the liberty of adding adjectives in brackets[*] to your above statements. It doesn't matter about the instantaneous values of power since not only do they not have to be conserved, but they are also "of limited usefulness", according to Eugene Hecht, since the actual energy content of instantaneous power is undefined even when the instantaneous power is defined. Are you sure that is why Hecht wrote what he did? He would, in all likelihood, have an apoplexy if he knew how his words were being used. The circuit is very useful to investigate interference more carefully because on the AVERAGE, the interference IS zero. *Using spreadsheets, we can see how the interference both adds and subtracts from the instantaneous applied voltage, resulting in cycling variations in the power applied to the resistor and other circuit elements. *A very instructive exercise. Instructive as long as we remember that a conservation of power principle doesn't exist and therefore, equations based on instantaneous powers do not have to balance. The joules, not the watts, are what must balance. Since the total energies in your equations do not balance either, there is still a problem with your hypothesis. It would be helpful, however, if you could actually demonstrate a system where the energies balance, but the flows do not. This would settle the matter once and for all. (You won't find one, since balanced flows are a consequence of conservation of energy). ...Keith |
#2
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Keith Dysart wrote:
It would be helpful, however, if you could actually demonstrate a system where the energies balance, but the flows do not. That's obviously easy to demonstrate in a distributed network system. We can have energy flowing into both ends of a loading coil at the same time and 180 degrees later, energy flowing out of both ends at the same time. The energies balance but the flows are completely unbalanced and indeed defy the lumped circuit model. -- 73, Cecil http://www.w5dxp.com |
#3
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On Apr 12, 3:39*pm, Cecil Moore wrote:
Keith Dysart wrote: It would be helpful, however, if you could actually demonstrate a system where the energies balance, but the flows do not. That's obviously easy to demonstrate in a distributed network system. We can have energy flowing into both ends of a loading coil at the same time and 180 degrees later, energy flowing out of both ends at the same time. The energies balance but the flows are completely unbalanced and indeed defy the lumped circuit model. You are not quite looking at the system correctly. It is a system with two ports (bottom and top) where energy can enter or leave, and one element (coil) which can store energy. The energy that flows in the bottom either flows out the top or increases the energy stored in the coil. The energy flowing into the bottom is equal to the sum of the energy flowing out the top plus the increase in the energy stored in the coil. Expressed arithmetically Pbottom(t) = Pcoil(t) + Ptop(t) For the specific situation you describe above: "energy flowing out of both ends at the same time" means that the energy stored in the ooil is being reduced to supply the energy leaving the top and the bottom. The sum of the energy flows out of the top and the bottom is exactly equal to the rate at which the stored energy is being reduced. Lumped or not lumped is moot. The same analysis can be applied to a transmission line. The energy flow into the left is exactly equal to the energy flow out on the right plus the rate of increase in the energy stored in the line. Energy flows (aka power) do indeed balance, though you certainly have to correctly pick the flows that should balance. ...Keith |
#4
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Keith Dysart wrote:
For the specific situation you describe above: "energy flowing out of both ends at the same time" means that the energy stored in the ooil is being reduced to supply the energy leaving the top and the bottom. The sum of the energy flows out of the top and the bottom is exactly equal to the rate at which the stored energy is being reduced. Yes, the energy obviously balances but the instantaneous powers are in opposite directions and therefore cannot balance. Lumped or not lumped is moot. Energy cannot flow out of both ends of a lumped circuit inductor. The current is, by definition, exactly the same at both ends as it is for the lumped inductors in EZNEC. You might find these class notes informative. http://www.ttr.com/corum/ -- 73, Cecil http://www.w5dxp.com |
#5
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On Apr 13, 9:45*am, Cecil Moore wrote:
Keith Dysart wrote: For the specific situation you describe above: "energy flowing out of both ends at the same time" means that the energy stored in the ooil is being reduced to supply the energy leaving the top and the bottom. The sum of the energy flows out of the top and the bottom is exactly equal to the rate at which the stored energy is being reduced. Yes, the energy obviously balances but the instantaneous powers are in opposite directions and therefore cannot balance. Lumped or not lumped is moot. Energy cannot flow out of both ends of a lumped circuit inductor. The current is, by definition, exactly the same at both ends as it is for the lumped inductors in EZNEC. You might find these class notes informative. It is well known that if one builds the wrong model one will get the wrong answer. You build the wrong model, then claim that flows do not balance. Unbalanced flows are the expected result from incomplete models. Your imcompleteness is that you forgot to include the energy flow into the electric and magnetic fields around the coil. When one does not forget this flow, all of the flows will balance at every instant. ...Keith |
#6
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Keith Dysart wrote:
Your imcompleteness is that you forgot to include the energy flow into the electric and magnetic fields around the coil. When one does not forget this flow, all of the flows will balance at every instant. Sorry, it may or may not be a coil. It is in a black box whose contents are unknown. Including the energy flows inside the black box is impossible. The instantaneous power into the black box does not balance the instantaneous power out of the black box. -- 73, Cecil http://www.w5dxp.com |
#7
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On Apr 13, 8:41*pm, Cecil Moore wrote:
Keith Dysart wrote: Your imcompleteness is that you forgot to include the energy flow into the electric and magnetic fields around the coil. When one does not forget this flow, all of the flows will balance at every instant. Sorry, it may or may not be a coil. It is in a black box whose contents are unknown. Including the energy flows inside the black box is impossible. The instantaneous power into the black box does not balance the instantaneous power out of the black box. Black boxes are an excellent way to set problems which help us learn about the meaning of theories. Conservation of energy and its corollary, conservation of power, is used in a different way for analyzing black boxes than it is when we analyzed the fully specified circuit in your Fig 1-1. With the black box, knowing the power function on the two ports, we can compute the energy flow into the storage elements within the box. If the flow out of one port is not always exactly balanced by the flow into the other, then we know that the black box is storing some energy and therefore that it has some elements which store energy. In a more typical situation, we do not have a completely black box, but we know some of its elements. We can use the balance of energy flows to help us decide if we have all the elements. If some of the energy flow is unaccounted for, then we have not yet found all the elements. If the box is truly opague, then all we can say is that it has some energy storage elements and that collectively, the flow into these elements is described by Pport1(t) - Pport2(t) The situation is somewhat different in Fig 1-1. All the elements of the system are completely specified in Fig 1-1 and we used circuit theory to compute the energy flows. Not surprisingly, they completely balanced: Ps(t) = Prs(t) + Pg(t) Associated with Fig 1-1, there is a secondary hypothesis that it should be possible to account for another energy flow, the imputed flow in the reflected wave on the line. The inability to account for this flow, given the conservation of power corollary to the conservation of energy law, is a very strong indicator that the energy flow imputed to the reflected wave is not an actual energy flow. ...Keith |
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