On Apr 21, 3:25*am, Cecil Moore wrote:
Keith Dysart wrote:
Despite your
protests to the contrary, ideal voltage sources can, and
do, absorb energy.

*From the "IEEE Dictionary":

"Absorption: (2) A general term for the process by which
incident flux is converted to another form of energy,
usually and ultimately to heat. (4) The irreversible
conversion of the energy of an EM wave into another form
of energy as a result of wave interaction with matter."

By what mechanism does an ideal source with an impedance
of 0+j0 manage to dissipate heat? Since the energy absorption
by the ideal source is *irreversible*, where is the heat
(or other form of energy) stored and for how long?

Just as ideal voltage sources can provide energy to a circuit,
they can also remove energy from a circuit.

Feel free to substitute the word of your choice for 'remove'.

Dissipate is not a good choice since it usually implies
conversion to heat.

Absorb is not a good word for you, since you can find absorption
in the IEEE dictionary and it also suggests conversion to heat.

The thesaurus (http://thesaurus.reference.com/ suggests 'consume',
'assimilate', 'digest', 'imbibe',
'take up', 'sop up', and 'devour'.

Pick the word that you find least confusing.

Recalling that an ideal voltage source can provide (deliver,
furnish, supply, transfer) energy to a circuit, we need a
non confusing word to describe the concept that an ideal
voltage source can also remove energy from a circuit.

A word that gives no hint about where this energy goes would
be best, since, just as we do not know where the energy
that an ideal voltage source delivers to a circuit comes
from, we do not know where the energy that an ideal voltage
source removes from a circuit goes.

...Keith