Home |
Search |
Today's Posts |
#12
![]() |
|||
|
|||
![]()
"Antonio Vernucci" wrote in
: I full agree with your statement: If the line section is not exactly a half wave, then the real loss factor might be higher or lower depending on the location of the current and voltage maxima and minima and the relative contribution of R and G to loss. So, the formula may have significant error for short lines that are not exactly a half wave. But I am not certain about this other statement: Straight away, that tells you that the VSWR must be almost the same at both ends for it to not matter which end is the observation point, so therefore the first assumption is that VSWR is approximately equal at both ends of the half wave. If a practical line is very long, it cannot qualify as having a constant VSWR (unless it is 1, in which case the formula is unnecessary), so the formula is not suited. I have a feeling that the ARRL chart makes reference to the SWR at the antenna, and that it DOES take into account that, for a lossy line, the line portions closer to the transmitter are subjected to a lower SWR. Approximations that depend on VSWR as a load metric can: 1. depend on the integral over a half wave of very low loss line then apply it as a constant loss loss per unit length; or 2. treat the forward and reflected waves as waves independently subject to a constant loss per unit length. I explained the sources of error in extending (1) to the general case in my earlier post. Case (2) assumes that the attenuation is the result of (vector) addition of the power that is lost independently from each travelling wave at any point, whereas the power lost is due to the effect of currents and voltage resulting from vector addition of the voltages and currents of the two waves at each point. In some scenarios, they may be good approximations, but there are also scenarios where they are poor approximations. (I gave an example in an earlier posting where they both fail.) The reality is that on a practical mismatched line, loss per unit length is not constant with displacement. See my notes on VSWR at varying displacement on a practical line, see http://www.vk1od.net/VSWR/displacement.htm . Look at Fig 9. Note that the loss vs displacement line does not have a constant slope, and anything that ignores that is ignoring an aspect of the problem. Note that in the example, the red line dips below the blue line (meaning loss under mismatched conditions is LESS than matched line loss at some lengths). Any method that prevents that result is ignoring an aspect of the problem. The loss under mismatch conditions does depend on load impedance, and if you throw away some of the detail and reduce it to load VSWR, then you increase the scope for error. Is there application for the approximations? Certainly, I use them... but in the knowledge that they are approximations and an awareness of where they are not good approximations and may not produce an adequate answer for the current problem. Your original posting was about reconciling the chart with some examples, and I noted that the chart itself is a source of significant error in some scenarios. BTW, your calculations seem to fall into case (2), and if so, are subject to the same errors... though they may reconcile well with a chart based on that approximation. Owen |
Thread Tools | Search this Thread |
Display Modes | |
|
|