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On Nov 2, 1:20*pm, John Smith wrote:
Art Unwin wrote: * ... Best regards Art Of course, I am always open to "new proof" (heck, even old proof will do!) However, in a capacitor, I do believe that power and/or current does travel the surface of the plate(s.) * But of course John it will travel along the plate that is natures way of seeking the point of least resistance to cross. Remember that the plate of a capacitor represents an inductor which in combination with a capacitor has the same constituents as a tank circuit except that it is not being subject to a time varying field. I would like to say that I was in error stating that the when programers made the computor program on antennas on the premise of a contunuous sine wave they are quite correct when viwing it from yhe stand point of a tank circuit. To make a jump from this acceptance, to one accepting the same occurs at rf, where a signal actually leaves the antenna and enters/"rides"/travels/propagates the ether, is easily made, at least by me. I think the case is slightly different, it needs a continued varied current to achieve a stable eddy current which gives the ability for levitated charge movement and in the capacitor case the point of least resistance is pre established after the first varient in current and it is the current movement inconjunction with the eddy current that provides the essential spin needed for inline projection Since, obviously, the signal MUST leave the surface, why not just travel it (shortest distance between two points--and all that) to begin with? Exactly . After the first pulse of current flow the point of least resistance is attained so yes the charge will travel at that specific point. When a capacitor breaks down you cannot see the path taken by the current on the initiating plate but you can see a point trace where the charge impinges on the reeiving plate as opposed to the whole area of the plate. Remember convention if correct states that a capacitor does not radiate I do believe it does travel the surface, if at all possible; *however, given a very thin radiator and/or a very large PA, it would not surprise me if you can't force the current/power/VA to another route ... I don't see how that could happen except when a charge is released it produces a lesser resistance route by ironizing of the medium travelled either in the initial case or of a resultant discharge travelling thu ozone. Regards, JS Interesting Regards Art |
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