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#1
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I always assumed having more 1/2 elements in a collinear was best,
because that obviously raises gain and lowers angle. So from that point of view, I was thinking that it would actually be better to use a low VF coax, since that would give you shorter length elements, thus being able to fit more elements in a shorter space. But I've also read that having the element lengths closer to actual 1/2 length (longer) is actually more efficient than having more elements at a shorter (low VF) length. Just wondering what people's opinion is on this... So lets say you have a choice between using the insulated center conductor of a VF 78 coax through brass tube outer elements and having room for a few extra elements in a given length, verses using just an insulated wire that has a 99 VF through brass tube outer elements, thereby allowing slightly less elements because they're longer, but the elements you do have are closer to actual 1/2 length. Which would be best? And this is basically various UHF bands we're talking about. Thanks for any opinions, Dave |
#2
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![]() wrote in message ... I always assumed having more 1/2 elements in a collinear was best, because that obviously raises gain and lowers angle. So from that point of view, I was thinking that it would actually be better to use a low VF coax, since that would give you shorter length elements, thus being able to fit more elements in a shorter space. But I've also read that having the element lengths closer to actual 1/2 length (longer) is actually more efficient than having more elements at a shorter (low VF) length. Just wondering what people's opinion is on this... So lets say you have a choice between using the insulated center conductor of a VF 78 coax through brass tube outer elements and having room for a few extra elements in a given length, verses using just an insulated wire that has a 99 VF through brass tube outer elements, thereby allowing slightly less elements because they're longer, but the elements you do have are closer to actual 1/2 length. Which would be best? And this is basically various UHF bands we're talking about. Thanks for any opinions, Dave Hi Dave Opinion -- If your options are either 5 radiating elements, all slightly shorter than 1/2 wave, or 4 longer elements, there wil be no decernable difference in which is best. If you are contemplating the construction of an antenna much longer than several wavelengths, you will encounter problems much more siginificant than efficiency,. So, in my opinion, the "best" is whatever you find convenient. Jerry KD6JDJ |
#3
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#4
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Thanks for the info... My main concern between my two examples was
ease of construction I guess... After stripping the coax and throwing the braid and jacket away, I starting feeling like it was kind of a waste. Then I thought... why not just use insulated wire. But that would bring the element sizes up and not allow as much room for as many elements. Maybe two less elements, which wouldn't be huge, but it would be a difference in specs. One version is 10 half wave elements using a 78 VF center conductor in brass tube, along with a free space 1/4 on the bottom and one on the top. No short at the top as my tests showed this actually lowered performance. I actually am not sure why. Independent tests done by a reputable company that does this stuff full time showed this one to be about a 10 degree angle and about 8 db gain at peak angle. Which is pretty decent and it does perform quite well in real world tests. But of course there's always room for improvement. But anything more than that and there might be some pretty bad nulls on top. |
#5
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![]() wrote in message ... Thanks for the info... My main concern between my two examples was ease of construction I guess... After stripping the coax and throwing the braid and jacket away, I starting feeling like it was kind of a waste. Then I thought... why not just use insulated wire. But that would bring the element sizes up and not allow as much room for as many elements. Maybe two less elements, which wouldn't be huge, but it would be a difference in specs. One version is 10 half wave elements using a 78 VF center conductor in brass tube, along with a free space 1/4 on the bottom and one on the top. No short at the top as my tests showed this actually lowered performance. I actually am not sure why. Independent tests done by a reputable company that does this stuff full time showed this one to be about a 10 degree angle and about 8 db gain at peak angle. Which is pretty decent and it does perform quite well in real world tests. But of course there's always room for improvement. But anything more than that and there might be some pretty bad nulls on top. Hi Dave Again, opinion -- It is really difficult to gt a 4 or 5 wavelength long colinear antenna to work as well as the modeling predicts. Have you modeled the antenna you plan to build? Jerry KD6JDJ |
#6
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Hi Owen
I would like to put a question regarding a previous discussion. Not having your e-mail address, I have to catch you on another thread. I report below what you wrote at that time: QUOTE From TLLC, the matched line loss in dB of LMR400 (a foam coax of similar OD to RG213) is 3.941e-6*f^0.5 +1.031e-11*f The first term is due to R and the second due to G. At 144MHz, the percentage of power lost per meter due to R is (1-10^-(3.941e-6*f^0.5)/10)*100 is 1.08%. If you do similar for G, the loss is 0.034%, so loss in R is more than 30 times loss in G UNQUOTE I put those formulas on a spreadsheet, but I only obtain the 0.034% figure if I change the second formula into +1.031e-5*f (instead of +1.031e-11*f) Any comment? Thanks and 73 Tony I0JX Rome-Italy |
#7
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"Antonio Vernucci" wrote in
: Hi Owen I would like to put a question regarding a previous discussion. Not having your e-mail address, I have to catch you on another thread. I report below what you wrote at that time: QUOTE From TLLC, the matched line loss in dB of LMR400 (a foam coax of similar OD to RG213) is 3.941e-6*f^0.5 +1.031e-11*f The first term is due to R and the second due to G. At 144MHz, the percentage of power lost per meter due to R is (1-10^-(3.941e-6*f^0.5)/10)*100 is 1.08%. If you do similar for G, the loss is 0.034%, so loss in R is more than 30 times loss in G UNQUOTE I put those formulas on a spreadsheet, but I only obtain the 0.034% figure if I change the second formula into +1.031e-5*f (instead of +1.031e-11*f) Any comment? Thanks and 73 Tony I0JX Rome-Italy Ok, firstly, there was a mistake in my formula... it is missing a pair of parentheses, and should be (1-10^(-(3.941e-6*f^0.5)/10))*100. That correctly finds 1.08%/m for R loss. From my spreadsheet check, =(1-10^(-(0.00000000001031*f)/10))*100 correctly calculates 0.034%/m. Note the exponent of f is 1 in the G case. Apologies for the parenthesis omission. I wrote down what I 'did' on an RPN calculator rather than copying an expression that evaluated properly. Does this answer your question? Owen |
#8
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Ok, firstly, there was a mistake in my formula... it is missing a pair of
parentheses, and should be (1-10^(-(3.941e-6*f^0.5)/10))*100. That correctly finds 1.08%/m for R loss. From my spreadsheet check, =(1-10^(-(0.00000000001031*f)/10))*100 correctly calculates 0.034%/m. Note the exponent of f is 1 in the G case. Apologies for the parenthesis omission. I wrote down what I 'did' on an RPN calculator rather than copying an expression that evaluated properly. Does this answer your question? Owen, I simply pasted and copied your formulas in my Excel. For f=144: - the first formula gives me 0.00108893 that is 0.108%, which is 10 times lower than your figure - the second formula gives me 3.41851e-08 that is 0.0000034%, which is 10,000 times lower than your figure I did that three times, same results..... I cannot understand what can be wrong.... Tony I0JX |
#9
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"Antonio Vernucci" wrote in
: Ok, firstly, there was a mistake in my formula... it is missing a pair of parentheses, and should be (1-10^(-(3.941e-6*f^0.5)/10))*100. That correctly finds 1.08%/m for R loss. From my spreadsheet check, =(1-10^(-(0.00000000001031*f)/10))*100 correctly calculates 0.034%/m. Note the exponent of f is 1 in the G case. Apologies for the parenthesis omission. I wrote down what I 'did' on an RPN calculator rather than copying an expression that evaluated properly. Does this answer your question? Owen, I simply pasted and copied your formulas in my Excel. For f=144: - the first formula gives me 0.00108893 that is 0.108%, which is 10 times lower than your figure - the second formula gives me 3.41851e-08 that is 0.0000034%, which is 10,000 times lower than your figure I did that three times, same results..... I cannot understand what can be wrong.... Tony I0JX Ok, you have calculated for 144Hz. Try f=144e6 and don't format the cells with %. Owen |
#10
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On Apr 5, 6:50*pm, Owen Duffy wrote:
wrote in news:a706ece1-d519-47d0-8ffe-8e76cf03ff66 @z16g2000prd.googlegroups.com: I always assumed having more 1/2 elements in a collinear was best, because that obviously raises gain and lowers angle. So from that point of view, I was thinking that it would actually be better to use a low VF coax, since that would give you shorter length elements, thus being able to fit more elements in a shorter space. But I've also read that having the element lengths closer to actual 1/2 length (longer) is actually more efficient than having more elements at a shorter (low VF) length. Just wondering what people's opinion is on this... So lets say you have a choice between using the insulated center conductor of a VF 78 coax through brass tube outer elements and having room for a few extra elements in a given length, verses using just an insulated wire that has a 99 VF through brass tube outer elements, thereby allowing slightly less elements because they're longer, but the elements you do have are closer to actual 1/2 length. Which would be best? And this is basically various UHF bands we're talking about. Dave, The popular explanation for these things constructed with reversing coax sections is that the currents all along the vertical are (exactly) in phase. That explanation doesn't seem consistent with the nominal half wave elements being in fact a halfwave at VF=0.67, ie about two thirds the length. Nor does it deal with the fact that the element ends are connected to each other, ie no charge difference permitted. I have been playing with an NEC model of eight half wave elements using RG213. The currents are certainly not exactly in phase, not nearly, and the gain in freespace at 6dBi is less than I see claimed for this antenna. People seem to justify a claim of dB gain as 3dB for 2 elements, 6dB for 4 elements, 9dB for 8 elements... in which case they must mean gain to be wrt a dipole, and therefore gain of 8 half waves would be 11.2dBi... very sus, too simplistic. You asked specifically about efficiency. The efficiency in my NEC model (which includes internal loss in the RG213) is very good, 99%. Confusing part is that some of the designs have a half wave sticking out the top, and others a quarter wave, similarly different treatments at the bottom, and they aren't consistent about whether the coax breaks at or near voltage maxima or minima. I am still working on this, I suspect the antenna doesn't quite work as often explained, and not nearly as good as claimed. Owen Owen you make a very good point by alluding that the zero cross over point is not 50% of a the time for a full period but 0.67 % of a period.Thus if a tank circuit is inclusive of a radiation period this represent a difference in speed or time with respect to charging and discharging of lumped loads both of which must be included to achieve equilibrium in the absence of friction ( perpetual motion) Thus the peak amplitude of the resulting occillation at a particular frequency determines the characteristic impedance when resonance occurs at that frequency. In the real world on Earth occillation without friction is impossible thus frequency losses are in parabolic or additive form with the change in the number of periods which equates to frequency. Thus the 0.67 cross over point represents the difference of time between kinetic and potential energy accomodation which produces a curve that deviates from a true sinosoidal curve. Since NEC is formed on the condition that the exchange time between potential and kinetic exchange are equal i.e sinosoidal then the results obtained have an inherrent error ie assumtion is different from the factual. ie not truelly sinosoidal. Regards Art |
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