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On Jun 1, 9:14*pm, tom wrote:
Art Unwin wrote: On Jun 1, 6:44 am, Cecil Moore wrote: Art Unwin wrote: Does that mean that a radiator reduces mass with use because the electrons orbiting around the atom are losing mass? Since mass and energy are equivalent, I suppose the mass of the radiator increases with increasing power input. The increase in mass can be calculated but the average ham has no way of measuring the increase. No need to worry about the tower falling down due to additional mass from energized electrons. :-) The antenna is charged up to a certain energy level during the key-down transient state. Since the energy content of the antenna cannot increase forever, it must lose energy as photonic radiation and/or as heat during steady-state. Free electrons in a conductor travel at much less than the speed of light. Photons are emitted from the electrons at the speed of light. A quote from: http://c2.com/cgi/wiki?SpeedOfElectrons "For example, for a copper wire of radius 1 mm carrying a steady current of 10 Amps, the drift velocity is only about 0.024 cm/sec!" i.e. about 0.01 inch/second. Ignoring random movements, the electrons at our RF transmitter never reach the antenna. At 10 MHz, the electrons move less than 0.000000001 inch during a 100 nS cycle involving a 100 watt transmitter, i.e. they mostly oscillate in place. However, other electrons, traveling at a large percentage of the speed of light, are quite massive as observed in particle accelerators and radioactive decay. -- 73, Cecil, IEEE, OOTC, *http://www.w5dxp.com Cecil The above is confusing unbound particles with bound particles both of snip Good, but not one of your great Carrollesque. *this collection of particles are in a state of three dimensional equilibrium in relation to other similar clusters of particles which provides a mass that in total is in static equilibrium within its own boundary. If you supply energy to this mass in equilibrium the frequency of rotation of particles increases and could increase to the point of the frequency of light where, if it continues, could become vaporised such that we now have a new medium consisting of partial pressures of gasses. Just amazing in it's wrongness, but it could easily convince the ignorant masses our schools now create. *This is just incredible fiction! How do you do it? snip Art tom K0TAR I think it is convincing too. Science is wonderfull when you connect every thing together and a picture becomes visible. Same goes for cross word puzzles. My UK born son was educated in American schools starting with Montessori. He now earns a good living at La Hoya so education in America is not the culprit for your observations. Maybe you are over estimating your own abilities when comparing. However, now is your chance to correct the "wrongness" that I quote. I am all ears. After all you have won competitions with your antenna designed but garnished from the many text books. Note that David is now comfortable in giving displacement current some credit for propagation so he must be younger than I thought according to your interpretations. Now how does a wave traverse the Earth without collapsing? What is the connection to light? Does the "belts" that surround the World act as breakwaters which accounts for the rainy seasons?I suspect that it is explained in the books somewhere except that somebody removed a page! Actually, I dreamt most of it and also made antennas following the small print, and they worked ! Well at least in my dreams. It must be a miracle. What do you think? Art Art |
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Art Unwin wrote:
I think it is convincing too. Science is wonderfull when you connect every thing together and a picture becomes visible. Same goes for cross word puzzles. My UK born son was educated in American schools starting with Montessori. He now earns a good living at La Hoya so education in America is not the culprit for your observations. Maybe you are over estimating your own abilities when comparing. However, now is your chance to correct the "wrongness" that I quote. snip Art Art You really don't get how science works, do you? WE DON'T HAVE TO PROVE YOU WRONG. YOU HAVE TO PROVE YOU ARE RIGHT. You haven't done that. In fact, you haven't even started to do that. tom K0TAR Not G and proud of it if Art is an example |
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On Jun 1, 10:54*pm, tom wrote:
Art Unwin wrote: I think it is convincing too. Science is wonderfull when you connect every thing together and a picture becomes visible. Same goes for cross word puzzles. My UK born son was educated in American schools starting with Montessori. He now earns a good living at La Hoya so education in America is not the culprit for your observations. Maybe you are over estimating your own abilities when comparing. However, now is your chance to correct the "wrongness" that I quote. snip Art Art You really don't get how science works, do you? WE DON'T HAVE TO PROVE YOU WRONG. YOU HAVE TO PROVE YOU ARE RIGHT. You haven't done that. In fact, you haven't even started to do that. tom K0TAR Not G and proud of it if Art is an example Where does it say I have to prove it ? Maxwell proved it 150 years ago, so why does it have to happen all over again? Either way, everybody says it can't work or it doesn't work so what are you asking for, a drum roll? Why don't you write a book on antennas like David so at last the truth is revealed with respect to antennas. You could steal my thunder if I decided to become an author If you are happy with what you have then be satisfied and live happily ever after. You have proved yourself a winner with the multiple antenna building awards that you have in the many shoot outs that you have entered. Isn't that enough for you, the antenna king? When you decided to pick a fight with me did you really believe I would run away and hide? Art Art KB9MZ......xg ( uk) just for you Tom |
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"tom" wrote in message . net... Sal M. Onella wrote: Just a guess, but maybe it deals with the Wullenweber [or Wullenwever] antenna, described here http://en.wikipedia.org/wiki/Wullenweber and elsewhere. Actually, unlike Wullenweber, they have multiple concentric rings of verticals in the array with a complex phasing system. My guess is that this may have been a contributor to the methods eventually used in phased array radars. But also something that was an engineering study, and not necessarily practical. Our Wullenweber at Hanza had two concentric rings of antennas, the high band and the low band. And it did have a phasing system to form a beam. The pattern was very sharp. Oddly, most of what shows in a Wullenweber photograph isn't antennas, at all, but the passive screens that give the array its characteristic of seeing just off to one side. In some photos the ring of monopole antennas can be tough to spot. Unfortunately for this discussion, I didn't work in any of the DF shops. I was in the Comm Shop -- crypto, TTY, telephone & mux maintenance. What I learned about DF was just picked up along the way. "Sal" |
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"Registered User" wrote ... On Mon, 1 Jun 2009 20:25:06 +0200, Szczepan Białek wrote: That are speculations only. Everybody know that at the end of an antenna the high voltage appears. Even for a controlled current distribution dipole? All time I am writing about the original Hertz apparatus. See: (http://people.seas.harvard.edu/~jone...Hertz_exp.html There the ends of the dipole are named "capacitor plates". In the center of the dipole the sparks jump. The question is which part of the Hertz apparatus radiate? The capacitor plates (voltage pulses) or the sparks (AC current). AC current create the transverse waves. The capacitor plates (or balls) longitudinal waves. What are the radio waves: transversal or longitudinal? S* |
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"Art Unwin" wrote ... On Jun 1, 2:39 am, Szczepan Białek wrote: "1861 - Maxwell publishes a mechanical model of the electromagnetic field. Magnetic fields correspond to rotating vortices with idle wheels between them and electric fields correspond to elastic displacements, hence displacement currents. The equation for now becomes , where is the total current, conduction plus displacement, and is conserved: . This addition completes Maxwell's equations and it is now easy for him to derive the wave equation exactly as done in our textbooks on electromagnetism and to note that the speed of wave propagation was close to the measured speed of light. Maxwell writes, ``We can scarcely avoid the inference that light in the transverse undulations of the same medium which is the cause of electric and magnetic phenomena.'' Thomson, on the other hand, says of the displacement current, ``(it is a) curious and ingenious, but not wholly tenable hypothesis.'' "1864 - Maxwell reads a memoir before the Royal Society in which the mechanical model is stripped away and just the equations remain. He also discusses the vector and scalar potentials, using the Coulomb gauge. He attributes physical significance to both of these potentials. He wants to present the predictions of his theory on the subjects of reflection and refraction, but the requirements of his mechanical model keep him from finding the correct boundary conditions, so he never does this calculation." From:http://maxwell.byu.edu/~spencerr/phys442/node4.html Try understand: "the mechanical model is stripped away and just the equations remain." Now engineers are using model with compressible, massive electrons. The equations are used by teacher to teach the math. According to Maxwell model the radio waves are transversal. Are such in your radio reality? S* Hi S, Interesting to read what you say as there are many similarities to my antenna work. Yes. But I do not try to work out a new theory. For me the 200 years old "acoustic analogy" is enough. A small addition with respect to light formation. Displacement current Displacement current is necessary in the model with electricity in form of the incompressible fluid. Incompressible fluid is a history. is the action required of three dimensional equilibrium which is why I often point to the helicopter as an example, same thing goes for a gyroscope or the Sedgway scooter. It is this circular motion that holds to the understanding of light since this provides the spin of a particle such that it has straight line trajectory. Straight line trajectory is normal phnomenon at the high frequences. The ultrasonic waves are like radii (see sonar) The frequency of circular motion is what changes when the particle enters a medium that is resistive where the spin increases to maintain the straight line projection. The energy for this increase in spin is the latent energy that is removed from the particles potential energy similar to latent heat with liquids. Thus energy is conserved by the increase in spin which is analogous to change in frequency! This change in frequency brings the particle into the area of color , light and X rays ie higher frequencies and the latent energy shows up as light until there is no more energy left and the particle has vaporized such that light progresses to invisiblity. This being similar to the effects shown of a meteorite as it comes into contact with the resistive environment of Earth. Each new theory is very difficult for me. I prefer descriptions of experiments and observations. With respect to radiation from the ends of a radiator. This can only happen when the radiator is a fraction of a wavelength when the law of equilibrium is violated. The accellaration of charge at the end is without spin applied and tho there is radiation it becomes non directional and unable to overcome the gravitational force and falls within a short distance. Try the acoustic analogy. Here the all is easy. Quite opposite as in the Maxwell model: "He wants to present the predictions of his theory on the subjects of reflection and refraction, but the requirements of his mechanical model keep him from finding the correct boundary conditions, so he never does this calculation". The only reason for Maxwell model is the light polarisation. In his era the polarisation was explained with transverse waves. Now we know (from Clark) that the apparatus is polarised not waves. Regards, S* |
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Szczepan Białek wrote:
AC current create the transverse waves. The capacitor plates (or balls) longitudinal waves. What are the radio waves: transversal or longitudinal? The radial currents on the capacitor plates are 180 degrees out of phase. A lot of the radiation from the plates simply cancels. Ramo and Whinnery say that radiation is "primarily TEM", i.e. TEM is the "principle mode". -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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Szczepan Białek wrote:
Displacement current is necessary in the model with electricity in form of the incompressible fluid. Incompressible fluid is a history. It may be that you are using a lumped-circuit model when you should be using a distributed network model. According to Drs. Corum, the lumped-circuit model starts to fall apart at 15 degrees, i.e. 0/04WL. These web pages may be of interest to you. http://www.ttr.com/TELSIKS2001-MASTER-1.pdf http://www.ttr.com/corum/index.htm -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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"Cecil Moore" wrote ... Szczepan Białek wrote: AC current create the transverse waves. The capacitor plates (or balls) longitudinal waves. What are the radio waves: transversal or longitudinal? The radial currents on the capacitor plates are 180 degrees out of phase. A lot of the radiation from the plates simply cancels. Electrical dipole radiation is known from Gauss time. For us the two plates (or balls - Hertz used them also) are the two sources of electric longitudinal waves. For this reason in 1933 the frequency doubling was observed. Ramo and Whinnery say that radiation is "primarily TEM", i.e. TEM is the "principle mode". It is easy to say. Tell me if you have ever seen the emitting antenna which has the "current zone" exposed and the ends covered? According to Maxwell the tranversal waves MUST be created by AC current. DC current create the magnetic whirl. AC current create oscillating whirl. Such oscillating whirl starts the transverse wave. But this Maxwell proposition is not verified to now. S* |
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"Cecil Moore" wrote ... Szczepan Białek wrote: Displacement current is necessary in the model with electricity in form of the incompressible fluid. Incompressible fluid is a history. It may be that you are using a lumped-circuit model when you should be using a distributed network model. According to Drs. Corum, the lumped-circuit model starts to fall apart at 15 degrees, i.e. 0/04WL. These web pages may be of interest to you. http://www.ttr.com/TELSIKS2001-MASTER-1.pdf http://www.ttr.com/corum/index.htm There are details. For me interesting are only fundamentals. It starts from: "Maxwell wrote: The conception of the propagation of transverse magnetic disturbances to the exclusion of normal ones is distinctly set forth by Professor Faraday in his "Thoughts on Ray Vibrations." The electromagnetic theory of light, as proposed by him, is the same in substance as that which I have begun to develop in this paper, except that in 1846 there were no data to calculate the velocity of propagation." From: http://en.wikipedia.org/wiki/Line_of_force The TRANSVERSAL magnetic disturbances have beautifull math. The most beauty math element is the displacement current. But the magnetic disturbances are creates by AC CURRENT (not voltage). So if the radio waves are emitted from the current zone of antenna Maxwell is right. If from ends - not. Maxwell admired Ampere. But each genius works out his own theories. We can choose between them. S* -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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"Dave" wrote ... "Szczepan Bialek" wrote in message ... both. when the current is high in the center it is creating a stronger magnetic field, and when that current reaches the end it creates the highest voltage so makes more electric field... both are part of the electro-magnetic wave. It is not Maxwell model. In it current create magnetic field and THIS field create the electric field. AND SO ON. ah, you believe 'and so on'?? the 'so on' means the changing electric field creates a magnetic field... both conditions are required for electromagnetic propagation. without the time varying displacement current there would be no propagation. so yes, you can create a magnetic field from the time varying electric field. Your (engineering people) model is O.K. but it is quite different from the Maxwell model. This is the reason that Art can wrote: " "For your information you have never built an antenna that conforms in its entirety to Maxwell';s laws thus you cannot possibly understand radiation as presented by Maxwell." the maxwell equations completely describe radiation from an antenna, so all antennas, even arts, 'conform' to the maxwell equations. Maxwell equations were modified by Heaviside and the next. Tell us if Maxwell model is O.K. (radio waves are the transverse waves). S* |
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In article ,
Szczepan Białek wrote: The TRANSVERSAL magnetic disturbances have beautifull math. The most beauty math element is the displacement current. But the magnetic disturbances are creates by AC CURRENT (not voltage). So if the radio waves are emitted from the current zone of antenna Maxwell is right. If from ends - not. Maxwell admired Ampere. But each genius works out his own theories. We can choose between them. So, the obvious thing for you to do (as the proponent of an alternative, nontraditional theory) is to devise an experiment which can distinguish between these two cases. Remember, that when a responsible scientist proposes a theory, that scientist tries as hard as possible to come up with ways to *dis*prove the theory - that is, experiments which predict a testable result, which differs from the predictions of other theories. If the new theory can survive such testing, then it's got some meat on its bones... and choosing it would make sense. If it fails to survive the testing, it's wrong... and choosing it would be mistaken. If the scientist can't use the theory to make testable predictions, it's useless... and choosing it would be futile. If all of the predictions of the new theory are indistinguishable from the predictions of prevailing theory, then perhaps it isn't really new.. It may just be a restatement of the prevailing theory in different words... and if so, choosing it would be entirely a matter of taste or preference. If the scientist won't even *try* to use the theory to make testable predictions which might prove the theory wrong, then s/he isn't a scientist. So... how would *you* construct and measure an antenna (and perhaps modify it and then measure again), in order to demonstrate that your theory predicts the actual behavior of the antenna better than the standard theory? Here's a suggestion: start out with a model of a straight half-wave dipole. Predict its radiation pattern and feedpoint impedance, based on Maxwell's current-based theory and on your own voltage-at-the-end theory. Measure the pattern and impedance. Now, "bend" the antenna into different shapes. For example - leave the center portion of the dipole in a straight line. Bend the ends in various directions, shaping the antenna into a U, or into a Z, or a C (with the tips close together but not touching). Shorten the center section and split the ends, forming an H (e.g. short radiator with capacity loads on each end). In each case, predict the pattern and feedpoint impedance based on Maxwell's theory and on your own. Can you find cases in which the predictions vary? If so, which matches the actual (measured) behavior of the antenna better? Mathematical beauty is great... but if it doesn't predict the actual behavior of real-world phenomena, it's just beautiful math. -- Dave Platt AE6EO Friends of Jade Warrior home page: http://www.radagast.org/jade-warrior I do _not_ wish to receive unsolicited commercial email, and I will boycott any company which has the gall to send me such ads! |
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"Szczepan Bialek" wrote in message ... "Art Unwin" wrote ... On Jun 1, 2:39 am, Szczepan Białek wrote: "1861 - Maxwell publishes a mechanical model of the electromagnetic field. Magnetic fields correspond to rotating vortices with idle wheels between them and electric fields correspond to elastic displacements, hence displacement currents. The equation for now becomes , where is the total current, conduction plus displacement, and is conserved: . This addition completes Maxwell's equations and it is now easy for him to derive the wave equation exactly as done in our textbooks on electromagnetism and to note that the speed of wave propagation was close to the measured speed of light. Maxwell writes, ``We can scarcely avoid the inference that light in the transverse undulations of the same medium which is the cause of electric and magnetic phenomena.'' Thomson, on the other hand, says of the displacement current, ``(it is a) curious and ingenious, but not wholly tenable hypothesis.'' "1864 - Maxwell reads a memoir before the Royal Society in which the mechanical model is stripped away and just the equations remain. He also discusses the vector and scalar potentials, using the Coulomb gauge. He attributes physical significance to both of these potentials. He wants to present the predictions of his theory on the subjects of reflection and refraction, but the requirements of his mechanical model keep him from finding the correct boundary conditions, so he never does this calculation." From:http://maxwell.byu.edu/~spencerr/phys442/node4.html Try understand: "the mechanical model is stripped away and just the equations remain." Now engineers are using model with compressible, massive electrons. The equations are used by teacher to teach the math. According to Maxwell model the radio waves are transversal. Are such in your radio reality? S* Hi S, Interesting to read what you say as there are many similarities to my antenna work. Yes. But I do not try to work out a new theory. For me the 200 years old "acoustic analogy" is enough. A small addition with respect to light formation. Displacement current Displacement current is necessary in the model with electricity in form of the incompressible fluid. Incompressible fluid is a history. is the action required of three dimensional equilibrium which is why I often point to the helicopter as an example, same thing goes for a gyroscope or the Sedgway scooter. It is this circular motion that holds to the understanding of light since this provides the spin of a particle such that it has straight line trajectory. Straight line trajectory is normal phnomenon at the high frequences. The ultrasonic waves are like radii (see sonar) The frequency of circular motion is what changes when the particle enters a medium that is resistive where the spin increases to maintain the straight line projection. The energy for this increase in spin is the latent energy that is removed from the particles potential energy similar to latent heat with liquids. Thus energy is conserved by the increase in spin which is analogous to change in frequency! This change in frequency brings the particle into the area of color , light and X rays ie higher frequencies and the latent energy shows up as light until there is no more energy left and the particle has vaporized such that light progresses to invisiblity. This being similar to the effects shown of a meteorite as it comes into contact with the resistive environment of Earth. Each new theory is very difficult for me. I prefer descriptions of experiments and observations. With respect to radiation from the ends of a radiator. This can only happen when the radiator is a fraction of a wavelength when the law of equilibrium is violated. The accellaration of charge at the end is without spin applied and tho there is radiation it becomes non directional and unable to overcome the gravitational force and falls within a short distance. Try the acoustic analogy. Here the all is easy. Quite opposite as in the Maxwell model: "He wants to present the predictions of his theory on the subjects of reflection and refraction, but the requirements of his mechanical model keep him from finding the correct boundary conditions, so he never does this calculation". The only reason for Maxwell model is the light polarisation. In his era the polarisation was explained with transverse waves. Now we know (from Clark) that the apparatus is polarised not waves. Regards, S* i knew getting you and art together would be interesting... good for a whole evening full of laughs! the waves must be polarized to interact as observed with polarized antennas. |
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"tom" wrote in message . net... Art Unwin wrote: On Jun 1, 6:09 pm, "Dave" wrote: "Dave" wrote in message ... "Dave" wrote in message ... "Dave" wrote in message ... "Dave" wrote in message ... "Art Unwin" wrote in message ... Gauss's law of Statics is the subject law. Ok, you capitalize that as if it were a specific law... provide a reference, other than your own posts, for "Gauss's law of Statics". If you can't do that, provide the specific equation you are refering to. come on art, cite the specific reference for "Gauss's law of Statics". can't answer a specific simple question art?? you much prefer to handwave and berate others, i ask a simple direct question that is at the core of all your ranting and you can't even answer it. without that answer the rest of your posts are just empty shells. give us this magical "Gauss's law of Statics" that you base everything on! come on art, one specific simple question...cite the specific reference for "Gauss's law of Statics". or are you going to pull another vanishing act and come back later just to start fresh with more bafflegab? thats right art, keep ignoring me... you can't answer the central question that all your theory is built on, so that makes the rest of it just so much more nonsense. David I am not ignoring you. I have responded to lots and lots of your Yes he is, and no he can't answer the question. snip more of the normal nonsense Have a very happy day and sleep tight and don't get your knickers in a twist Regards Art With total disregard tom K0TAR I know, but its fun asking the one pertinent question that he can't answer. he keeps saying i reject his addition of the (t) term to Gauss' Law, and won't accept the answer that it is redundant since the law is not dependent on time, it is true for all time. So the (t) is not necessary at best and misleading at worst... you can put it there, but it doesn't mean anything... its kind of like saying f(t)=f(t), a simple truism. |
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Dave wrote:
"tom" wrote in message snip With total disregard tom K0TAR I know, but its fun asking the one pertinent question that he can't answer. he keeps saying i reject his addition of the (t) term to Gauss' Law, and won't accept the answer that it is redundant since the law is not dependent on time, it is true for all time. So the (t) is not necessary at best and misleading at worst... you can put it there, but it doesn't mean anything... its kind of like saying f(t)=f(t), a simple truism. I know, but I couldn't resist. tom K0TAR |
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Sal M. Onella wrote:
Our Wullenweber at Hanza had two concentric rings of antennas, the high band and the low band. And it did have a phasing system to form a beam. The pattern was very sharp. In this system all antennas were active, and all were quarter wave verticals at the design frequency. Unfortunately for this discussion, I didn't work in any of the DF shops. I was in the Comm Shop -- crypto, TTY, telephone & mux maintenance. What I learned about DF was just picked up along the way. Still, must have been interesting and fun with the variety you got to deal with. "Sal" tom K0TAR |
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"tom" wrote in message . net... Sal M. Onella wrote: snip Unfortunately for this discussion, I didn't work in any of the DF shops. I was in the Comm Shop -- crypto, TTY, telephone & mux maintenance. What I learned about DF was just picked up along the way. Still, must have been interesting and fun with the variety you got to deal with. Absolutely! My first duty station was an intercept site in the Philippines, then Hanza, then sea duty on an admiral's staff (Second Fleet Commander). There wasn't much I hadn't seen by the time I was 25. I made CPO the next year and was dubbed "The Teenage Chief" for my youthful appearance. I'm 66 now and smiling slightly, content at how well things have worked out, thanks to that lucky beginning. "Sal" (KD6VKW) |
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"Dave" wrote ... "Szczepan Bialek" wrote in message ... The only reason for Maxwell model is the light polarisation. In his era the polarisation was explained with transverse waves. Now we know (from Clark) that the apparatus is polarised not waves. Regards, S* i knew getting you and art together would be interesting... good for a whole evening full of laughs! the waves must be polarized to interact as observed with polarized antennas. But here are the two possibilities. 1. The dipole radiates the transverse wave from centre, 2. The dipole radiate the two COUPLED longitudinal waves from the two ends. In the both cases the antennas (emitting and receiving) must be parallel. Which place radiate the radio waves? S* |
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"Dave Platt" wrote ... In article , Szczepan Białek wrote: The TRANSVERSAL magnetic disturbances have beautifull math. The most beauty math element is the displacement current. But the magnetic disturbances are creates by AC CURRENT (not voltage). So if the radio waves are emitted from the current zone of antenna Maxwell is right. If from ends - not. Maxwell admired Ampere. But each genius works out his own theories. We can choose between them. So, the obvious thing for you to do (as the proponent of an alternative, nontraditional theory) is to devise an experiment which can distinguish between these two cases. The traditional theory is the acoustic theory. The nontraditional theory is the Maxwell model. In his model the transverse waves propagate in a solid body. Maxwell devised many experiments. One of them was the famous MM experiment. But Maxwell dead before the result. Remember, that when a responsible scientist proposes a theory, that scientist tries as hard as possible to come up with ways to *dis*prove the theory - that is, experiments which predict a testable result, which differs from the predictions of other theories. Maxwell ended his life at 47. He was responsible but he had not enough time. If the new theory can survive such testing, then it's got some meat on its bones... and choosing it would make sense. If it fails to survive the testing, it's wrong... and choosing it would be mistaken. The teachers choose it. The engineering people choose electrons. If the scientist can't use the theory to make testable predictions, it's useless... and choosing it would be futile. It is the excelent "piece to teach". If all of the predictions of the new theory are indistinguishable from the predictions of prevailing theory, then perhaps it isn't really new.. It may just be a restatement of the prevailing theory in different words... and if so, choosing it would be entirely a matter of taste or preference. Maxwell theory was really new. If the scientist won't even *try* to use the theory to make testable predictions which might prove the theory wrong, then s/he isn't a scientist. Maxwell had not enough time to do it. So... how would *you* construct and measure an antenna (and perhaps modify it and then measure again), in order to demonstrate that your theory predicts the actual behavior of the antenna better than the standard theory? Standard theory is the acoustic theory. All YOUR antennas demonstrate that the acoustic analogy is O.K. Here's a suggestion: start out with a model of a straight half-wave dipole. Predict its radiation pattern and feedpoint impedance, based on Maxwell's current-based theory and on your own voltage-at-the-end theory. Measure the pattern and impedance. I am here to encourage you all to do it. Now, "bend" the antenna into different shapes. For example - leave the center portion of the dipole in a straight line. Bend the ends in various directions, shaping the antenna into a U, or into a Z, or a C (with the tips close together but not touching). Shorten the center section and split the ends, forming an H (e.g. short radiator with capacity loads on each end). In each case, predict the pattern and feedpoint impedance based on Maxwell's theory and on your own. Can you find cases in which the predictions vary? If so, which matches the actual (measured) behavior of the antenna better? I am sure that somebody young do it. Maxwell would be happy. Mathematical beauty is great... but if it doesn't predict the actual behavior of real-world phenomena, it's just beautiful math. Math is still necessary in schools. But in this case the math will be saved. The Maxwell equations were the same like the Helmholtz for the fluid mechanics. Now the same math is taught in the two subjects (fluids and EM). Very often the same teacher do it. S* |
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Sal M. Onella wrote:
I'm 66 now and smiling slightly, content at how well things have worked out, thanks to that lucky beginning. "Sal" (KD6VKW) Thanks to you and everyone else for their service. tom K0TAR |
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All that bright Mississippi Sun and heat and humidity around here,
sometimes when I am working in my yard, I see Sun Spots in my eyes. I am 67, or maybe 68 years young, I don't know how old I am. It's RUFF on me! cuhulin |
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"Szczepan Bialek" wrote in message ... "Dave Platt" wrote ... In article , Szczepan Białek wrote: The TRANSVERSAL magnetic disturbances have beautifull math. The most beauty math element is the displacement current. But the magnetic disturbances are creates by AC CURRENT (not voltage). So if the radio waves are emitted from the current zone of antenna Maxwell is right. If from ends - not. Maxwell admired Ampere. But each genius works out his own theories. We can choose between them. So, the obvious thing for you to do (as the proponent of an alternative, nontraditional theory) is to devise an experiment which can distinguish between these two cases. The traditional theory is the acoustic theory. The nontraditional theory is the Maxwell model. only if you are still living in the 1800's. |
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"Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... both. when the current is high in the center it is creating a stronger magnetic field, and when that current reaches the end it creates the highest voltage so makes more electric field... both are part of the electro-magnetic wave. It is not Maxwell model. In it current create magnetic field and THIS field create the electric field. AND SO ON. ah, you believe 'and so on'?? the 'so on' means the changing electric field creates a magnetic field... both conditions are required for electromagnetic propagation. without the time varying displacement current there would be no propagation. so yes, you can create a magnetic field from the time varying electric field. Your (engineering people) model is O.K. but it is quite different from the Maxwell model. This is the reason that Art can wrote: " "For your information you have never built an antenna that conforms in its entirety to Maxwell';s laws thus you cannot possibly understand radiation as presented by Maxwell." the maxwell equations completely describe radiation from an antenna, so all antennas, even arts, 'conform' to the maxwell equations. Maxwell equations were modified by Heaviside and the next. Tell us if Maxwell model is O.K. (radio waves are the transverse waves). S* Maxwell is ok. |
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"Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... The only reason for Maxwell model is the light polarisation. In his era the polarisation was explained with transverse waves. Now we know (from Clark) that the apparatus is polarised not waves. Regards, S* i knew getting you and art together would be interesting... good for a whole evening full of laughs! the waves must be polarized to interact as observed with polarized antennas. But here are the two possibilities. 1. The dipole radiates the transverse wave from centre, 2. The dipole radiate the two COUPLED longitudinal waves from the two ends. In the both cases the antennas (emitting and receiving) must be parallel. Which place radiate the radio waves? S* the whole antenna radiates. |
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On Wed, 03 Jun 2009 22:50:25 GMT, "Dave" wrote:
Maxwell is ok. Heaviside rocks! 73's Richard Clark, KB7QHC |
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"tom" wrote in message . net... Sal M. Onella wrote: I'm 66 now and smiling slightly, content at how well things have worked out, thanks to that lucky beginning. "Sal" (KD6VKW) Thanks to you and everyone else for their service. You're certainly welcome but I have to say I got as much out of it as I put in. The training, experience, maturity and travel were incomparable. (Living conditions far from cruise ship standards, but it was usually comfy.) "Sal" |
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"Dave" wrote ... "Szczepan Bialek" wrote in message ... "Dave Platt" wrote ... In article , Szczepan Białek wrote: The TRANSVERSAL magnetic disturbances have beautifull math. The most beauty math element is the displacement current. But the magnetic disturbances are creates by AC CURRENT (not voltage). So if the radio waves are emitted from the current zone of antenna Maxwell is right. If from ends - not. Maxwell admired Ampere. But each genius works out his own theories. We can choose between them. So, the obvious thing for you to do (as the proponent of an alternative, nontraditional theory) is to devise an experiment which can distinguish between these two cases. The traditional theory is the acoustic theory. The nontraditional theory is the Maxwell model. only if you are still living in the 1800's. Exactly in 1638: "1638 - Rene Descartes theorizes that light is a pressure wave through the second of his three types of matter of which the universe is made. He invents properties of this fluid that make it possible to calculate the reflection and refraction of light. The ``modern'' notion of the aether is born. " From: http://maxwell.byu.edu/~spencerr/phys442/node4.html The next: "1717 - Newton shows that the ``two-ness'' of double refraction clearly rules out light being aether waves. (All aether wave theories were sound-like, so Newton was right; longitudinal waves can't be polarized.) " In the History you find how many people analysed the issue: longitudinal vs. transversal. In 1905 all stop. But after 1905 peole build antennas. And they do not worry what the radiation is like. Sunner or later the issue appears again. S* |
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"Dave" wrote ... "Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... The only reason for Maxwell model is the light polarisation. In his era the polarisation was explained with transverse waves. Now we know (from Clark) that the apparatus is polarised not waves. Regards, S* i knew getting you and art together would be interesting... good for a whole evening full of laughs! the waves must be polarized to interact as observed with polarized antennas. But here are the two possibilities. 1. The dipole radiates the transverse wave from centre, 2. The dipole radiate the two COUPLED longitudinal waves from the two ends. In the both cases the antennas (emitting and receiving) must be parallel. Which place radiate the radio waves? S* the whole antenna radiates. But what radiate? Magnetic whirls or pressure-like electric wave? S* |
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Szczepan Białek wrote:
But what radiate? Particles called photons radiate. Photons are emitted by decelerating electrons. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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"Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... The only reason for Maxwell model is the light polarisation. In his era the polarisation was explained with transverse waves. Now we know (from Clark) that the apparatus is polarised not waves. Regards, S* i knew getting you and art together would be interesting... good for a whole evening full of laughs! the waves must be polarized to interact as observed with polarized antennas. But here are the two possibilities. 1. The dipole radiates the transverse wave from centre, 2. The dipole radiate the two COUPLED longitudinal waves from the two ends. In the both cases the antennas (emitting and receiving) must be parallel. Which place radiate the radio waves? S* the whole antenna radiates. But what radiate? Magnetic whirls or pressure-like electric wave? S* magnets don't whirl and 'electric waves' are not like pressure... they magnetic and electric field vectors are at right angles to each other and the direction of propagation... both the electric and magnetic components are needed for propagation... you can't have one without the other. |
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"Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... "Dave Platt" wrote ... In article , Szczepan Białek wrote: The TRANSVERSAL magnetic disturbances have beautifull math. The most beauty math element is the displacement current. But the magnetic disturbances are creates by AC CURRENT (not voltage). So if the radio waves are emitted from the current zone of antenna Maxwell is right. If from ends - not. Maxwell admired Ampere. But each genius works out his own theories. We can choose between them. So, the obvious thing for you to do (as the proponent of an alternative, nontraditional theory) is to devise an experiment which can distinguish between these two cases. The traditional theory is the acoustic theory. The nontraditional theory is the Maxwell model. only if you are still living in the 1800's. Exactly in 1638: "1638 - Rene Descartes theorizes that light is a pressure wave through the second of his three types of matter of which the universe is made. He invents properties of this fluid that make it possible to calculate the reflection and refraction of light. The ``modern'' notion of the aether is born. " From: http://maxwell.byu.edu/~spencerr/phys442/node4.html The next: "1717 - Newton shows that the ``two-ness'' of double refraction clearly rules out light being aether waves. (All aether wave theories were sound-like, so Newton was right; longitudinal waves can't be polarized.) " In the History you find how many people analysed the issue: longitudinal vs. transversal. In 1905 all stop. But after 1905 peole build antennas. And they do not worry what the radiation is like. Sunner or later the issue appears again. S* only when time travelers bring back scientists from the 1800's... or people like you try to reinvent the discarded theories of old. |
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Dave wrote:
"Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... The only reason for Maxwell model is the light polarisation. In his era the polarisation was explained with transverse waves. Now we know (from Clark) that the apparatus is polarised not waves. Regards, S* i knew getting you and art together would be interesting... good for a whole evening full of laughs! the waves must be polarized to interact as observed with polarized antennas. But here are the two possibilities. 1. The dipole radiates the transverse wave from centre, 2. The dipole radiate the two COUPLED longitudinal waves from the two ends. In the both cases the antennas (emitting and receiving) must be parallel. Which place radiate the radio waves? S* the whole antenna radiates. But what radiate? Magnetic whirls or pressure-like electric wave? S* magnets don't whirl and 'electric waves' are not like pressure... they magnetic and electric field vectors are at right angles to each other and the direction of propagation... both the electric and magnetic components are needed for propagation... you can't have one without the other. It's hard to tell, but he's probably referring to the curl of a magnetic field which he obviously doesn't understand. The idea of a "pressure-like electric wave" is pure fantasy. 73, Tom Donaly, KA6RUH |
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"Tom Donaly" wrote ... Dave wrote: "Szczepan Bialek" wrote in message ... "Dave" wrote ... But what radiate? Magnetic whirls or pressure-like electric wave? S* magnets don't whirl and 'electric waves' are not like pressure... they magnetic and electric field vectors are at right angles to each other and the direction of propagation... both the electric and magnetic components are needed for propagation... you can't have one without the other. It's hard to tell, but he's probably referring to the curl of a magnetic field which he obviously doesn't understand. The idea of a "pressure-like electric wave" is pure fantasy. There is the fantastic example: http://www.radartutorial.eu/06.antennas/an14.en.html S* |
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"Dave" wrote ... "Szczepan Bialek" wrote in message ... In the History you find how many people analysed the issue: longitudinal vs. transversal. In 1905 all stop. But after 1905 peole build antennas. And they do not worry what the radiation is like. Sunner or later the issue appears again. S* only when time travelers bring back scientists from the 1800's... or people like you try to reinvent the discarded theories of old. Some theories are taught some not. But people after 25 can use what they want. It seems to me that engineering people do not use the EM theory. S* |
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"Szczepan Bialek" wrote in message ... "Tom Donaly" wrote ... Dave wrote: "Szczepan Bialek" wrote in message ... "Dave" wrote ... But what radiate? Magnetic whirls or pressure-like electric wave? S* magnets don't whirl and 'electric waves' are not like pressure... they magnetic and electric field vectors are at right angles to each other and the direction of propagation... both the electric and magnetic components are needed for propagation... you can't have one without the other. It's hard to tell, but he's probably referring to the curl of a magnetic field which he obviously doesn't understand. The idea of a "pressure-like electric wave" is pure fantasy. There is the fantastic example: http://www.radartutorial.eu/06.antennas/an14.en.html S* and how are you misinterpreting what that is showing? |
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"Dave" wrote ... "Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... In the History you find how many people analysed the issue: longitudinal vs. transversal. In 1905 all stop. But after 1905 peole build antennas. And they do not worry what the radiation is like. Sunner or later the issue appears again. S* only when time travelers bring back scientists from the 1800's... or people like you try to reinvent the discarded theories of old. Some theories are taught some not. But people after 25 can use what they want. It seems to me that engineering people do not use the EM theory. S* Theories that aren't taught have probably been dropped for a good reason. usually because they are wrong or don't do anything useful. I don't know about other engineers but i use EM theory, all my antennas were designed using it, and i test it regularly with my own equipment... it has never failed me. You do not use the EM theory. In EM no electrons. You use electrons: "Electronics is a branch of science and technology that deals with the flow of electrons through nonmetallic conductors, mainly semiconductors such as silicon. It is distinct from electrical science and technology, which deal with the flow of electrons and other charge carriers through metal conductors such as copper. This distinction started around 1906 with the invention by Lee De Forest of the triode. Until 1950 this field was called "radio technology" because its principal application was the design and theory of radio transmitters, receivers and vacuum tubes." Electrons never failed us. S* |
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"Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message ... In the History you find how many people analysed the issue: longitudinal vs. transversal. In 1905 all stop. But after 1905 peole build antennas. And they do not worry what the radiation is like. Sunner or later the issue appears again. S* only when time travelers bring back scientists from the 1800's... or people like you try to reinvent the discarded theories of old. Some theories are taught some not. But people after 25 can use what they want. It seems to me that engineering people do not use the EM theory. S* Theories that aren't taught have probably been dropped for a good reason. usually because they are wrong or don't do anything useful. I don't know about other engineers but i use EM theory, all my antennas were designed using it, and i test it regularly with my own equipment... it has never failed me. You do not use the EM theory. In EM no electrons. You use electrons: "Electronics is a branch of science and technology that deals with the flow of electrons through nonmetallic conductors, mainly semiconductors such as silicon. It is distinct from electrical science and technology, which deal with the flow of electrons and other charge carriers through metal conductors such as copper. This distinction started around 1906 with the invention by Lee De Forest of the triode. Until 1950 this field was called "radio technology" because its principal application was the design and theory of radio transmitters, receivers and vacuum tubes." Electrons never failed us. if you want to talk with MODERN engineers, then you should use MODERN definitions. i don't know who wrote that wikipedia definition but you would find it very hard to work with just non-metalic stuff in the electronics I know. even the smallest integrated circuits use metalic conductors to connect components and for connections to the outside world. All radios (aren't radios electronic) use metallic antennas in one form or another... check some other definitions: the branch of physics that deals with the emission and effects of electrons and with the use of electronic devices wordnet.princeton.edu/perl/webwn electronic - of or relating to electronics; concerned with or using devices that operate on principles governing the behavior of electrons; "electronic devices" wordnet.princeton.edu/perl/webwn the branch of technology concerned with the development and application of circuits or systems using electron devices, including magnetic amplifiers, transistors http://www.tki.org.nz/r/technology/c...m/p85_86_e.php electronic - Pertaining to the energies, distributions, and behaviors of electrons; see mechanical. e-drexler.com/d/06/00/Nanosystems/glossary/glossary_e.html do not 'electronic devices' include transformers?? aren't most of them made out of metallic conductors?? what about capacitors, don't most of them have metallic plates? magnetic amplifiers are most definately made of metallic conductors. EM or ElectroMagnetic theory does indeed include charged particles. Maxwell's equations are definately based on charged particles. just where does the 'i' term come from if not from moving charges? and where does the charge term in art's favorite Gauss' law that is part of Maxwell's equations come from if not from charged particles?? |
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"Dave" wrote ... "Szczepan Bialek" wrote in message There is the fantastic example: http://www.radartutorial.eu/06.antennas/an14.en.html S* and how are you misinterpreting what that is showing? It seems to me that the radiating elements radiate from the ends. Is it misinterpreting? S* |
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"Dave" wrote ... EM or ElectroMagnetic theory does indeed include charged particles. Maxwell's equations are definately based on charged particles. just where does the 'i' term come from if not from moving charges? Take a glance in Maxwell's Treatise. There is the incompressible massles fluid. Maxwell did the math to Faraday ideas. But with one exception. Faraday discovered the atomic nature of electricity (at electrolise). Maxwell ignored it. He prefered fluids and whirls. Todays teachers also prefere it. and where does the charge term in art's favorite Gauss' law that is part of Maxwell's equations come from if not from charged particles?? Each genius wrote his own Electrodynamics. They are in some points similar. But the incompressible fluid is only in Maxwell's. S* |
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"Szczepan Bialek" wrote in message ... "Dave" wrote ... "Szczepan Bialek" wrote in message There is the fantastic example: http://www.radartutorial.eu/06.antennas/an14.en.html S* and how are you misinterpreting what that is showing? It seems to me that the radiating elements radiate from the ends. Is it misinterpreting? S* you are misinterpreting what they are trying to show in the simplified drawings of the pattern and phasing animation. |
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