Richard Harrison wrote:
If everything is symmetrical, the self-impedances and the mutual
impedances of the two elements should be equal, producing equal powers
into each element.

Unfortunately, it is not that easy except under special circumstances.
The element with leading phase often has a different feedpoint impedance
than the element with lagging phase. For instance:

Given two 1/4WL monopoles, 1/4WL apart, and fed 90 degrees apart with
one amp each will exhibit a gain of 3 dBi in one direction. However,
the feedpoint of one element is 20-j20 and the feedpoint of the other
element is 50+j20. The feedpoint voltages are obviously not equal so
to equalize the current magnitudes takes some juggling. That' what
Roy's BASIC program does - finds a solution if one exists.

I once had a BASIC program that calculated the mutual impedances given
the feedpoint impedance of one element alone and the feedpoint impedances
of the two elements during operation but I seem to have misplaced it.
--
73, Cecil http://www.qsl.net/w5dxp



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