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Spherical radiation pattern
On Sep 17, 7:49*pm, Richard Fry wrote:
On Sep 17, 7:02*pm, Art Unwin wrote: ... I found that out by making a resonant directional antenna *for all the TOP band that fits into my rotor on the tower. __________ What do you mean by (self) resonant? Physics shows that NO radiator as small as fits into the rotor on your tower, by itself, could possibly be self-resonant at "TOP band." RF With "David" being barred from the group there should be no obstacle to closing this thread It really was all for his benefit so he could provide insults and now there is no need for it. |
Spherical radiation pattern
On Sep 17, 8:51*pm, tom wrote:
Art Unwin wrote: On Sep 17, 7:49 pm, Richard Fry wrote: On Sep 17, 7:02 pm, Art Unwin wrote: ... I found that out by making a resonant directional antenna *for all the TOP band that fits into my rotor on the tower. __________ What do you mean by (self) resonant? Physics shows that NO radiator as small as fits into the rotor on your tower, by itself, could possibly be self-resonant at "TOP band." RF Watch the PTO print outs. No statements last for ever in physics I'm done You've been done for a looong time, Art. *You just don't realize it yet.. Your patent attempt proves nothing. *It's bad physics, and even with the clueless dips that work in the patent office you are still being rejected. *It's gotta be pretty useless if they won't approve it. tom K0TAR It is very normal for them to request changes. Obviously you have never filed a patent or done anything that would warrant one. Why not pair up with David and write one yourself or do you have some already? No that can't be, otherwise you would be aware of office actions as it goes on all the time. So is it you who is now Master of the group and self esteemed expert that we all now have to follow? Your insults are as good as Davids was! Either way I'm done for a while. |
Spherical radiation pattern
Art Unwin wrote:
On Sep 17, 7:49 pm, Richard Fry wrote: On Sep 17, 7:02 pm, Art Unwin wrote: ... I found that out by making a resonant directional antenna for all the TOP band that fits into my rotor on the tower. __________ What do you mean by (self) resonant? Physics shows that NO radiator as small as fits into the rotor on your tower, by itself, could possibly be self-resonant at "TOP band." RF With "David" being barred from the group there should be no obstacle to closing this thread It really was all for his benefit so he could provide insults and now there is no need for it. "David" had nothing to do with the last 4 exchanges anyway. What the hell are you blabbering about? And who "barred" him? You? If you think that's the case, you carry no weight with the group to begin with, and no one, no matter how much respect they get from the group, can bar anyone. This is an open newsgroup, and anyone can post, even loonies like you. tom K0TAR |
Spherical radiation pattern
Art Unwin wrote:
It is very normal for them to request changes. Obviously you have never filed a patent or done anything that would warrant one. Why not pair up with David and write one yourself or do you have some already? No that can't be, otherwise you would be aware of office actions as it goes on all the time. So is it you who is now Master of the group and self esteemed expert that we all now have to follow? Your insults are as good as Davids was! Either way I'm done for a while. Wonderful!! But I doubt you will keep the promise. And you have no idea of how many patents I've been involved with. But I can safely say the companies I have worked for have made more money from our patents than you have. tom K0TAR |
Spherical radiation pattern
tom wrote:
And you have no idea of how many patents I've been involved with. But I can safely say the companies I have worked for have made more money from our patents than you have. Which should have been "than you have from yours." tom K0TAR |
Spherical radiation pattern
christofire wrote:
Then the assumption of equal forward and reflected traveling waves of current can't be right, because that would imply no radiation ... Of course you are right. But the forward and reflected waves are equal at the ends of the dipole. At the feedpoint of a 1/2WL dipole the reflected current is only ~10% down from the forward current so the equal current assumption through the center loading coil is definitely only an approximation. The question remains: How can the current on a standing wave antenna, known to change by only 2-3 degrees in 90 degrees of antenna, be used to measure the delay through a loading coil installed in the standing wave antenna? Incidentally, the equal amplitude and opposite phase of the forward current and reflected current at the ends of a 1/2WL dipole is the reason that the ends don't radiate much. The two currents are acting like transmission line currents and thus any radiated fields tend to cancel because of destructive interference. The forward current and reflected current are in phase at the feedpoint. Their fields interfere constructively and thus radiation is maximum at that maximum current point. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
Spherical radiation pattern
"Art Unwin" wrote in message ... On Sep 11, 6:36 pm, "Dave" wrote: The problem is that all forces are not accounted for per Maxwell requirements! maxwell made no such requirement. the strong, weak, and gravitational force are not in his equations... never were and never will be. In your case magnetic energy remains with the radiator which is a loss that is unaccounted for ! This loss does not occur with a diamagnetic materials. Very simple my dear Watson. then why do my ferromagnetic antennas work better than there diamagnetic predecessor?? If a design is planar it just cannot be 100% efficient as when all forced are accounted for. nothing is 100% |
Spherical radiation pattern
"Art Unwin" wrote in message ... I'm done sure you are... |
Spherical radiation pattern
"Art Unwin" wrote in message ... With "David" being barred from the group there should be no obstacle to closing this thread who is barred?? i've just been busy with real antennas getting ready for winter. i will be gone in another week or so because verizon caved in and will be dumping usenet. maybe i'll resurrect myself with some other service, but none that i have to pay for, you aren't that much fun. It really was all for his benefit so he could provide insults and now there is no need for it. awww, i'm sure there are others who get as much of a laugh at your rantings and random phrases as i do! keep going!! |
Spherical radiation pattern
On Sep 18, 12:51*pm, "Dave" wrote:
"Art Unwin" wrote in message ... On Sep 11, 6:36 pm, "Dave" wrote: The problem is that all forces are not accounted for per Maxwell requirements! maxwell made no such requirement. *the strong, weak, and gravitational force are not in his equations... never were and never will be. In your case magnetic energy remains with the radiator which is a loss that is unaccounted for ! This loss does not occur with a diamagnetic materials. Very simple my dear Watson. then why do my ferromagnetic antennas work better than there diamagnetic predecessor?? If a design is planar it just cannot be 100% efficient as when all forced are accounted for. nothing is 100% This is when all current is transferred to the particle encapsulation and no current travels in the radiator carrier ie Radiation resistance is 52 ohms |
Spherical radiation pattern
On Sep 18, 12:55*pm, "Dave" wrote:
"Art Unwin" wrote in message ... With "David" being barred from the group there should be no obstacle to closing this thread who is barred?? *i've just been busy with real antennas getting ready for winter. *i will be gone in another week or so because verizon caved in and will be dumping usenet. *maybe i'll resurrect myself with some other service, but none that i have to pay for, you aren't that much fun. It really was all for his benefit so he could provide insults and now there is no need for it. awww, i'm sure there are others who get as much of a laugh at your rantings and random phrases as i do! *keep going!! Your profile states you are barred on all of your past postings! |
Spherical radiation pattern
"Art Unwin" wrote in message ... Your profile states you are barred on all of your past postings! profile?? what profile?? we don't need no stinking profile! this is usenet, i post via a news server, it has no profile of me, it just accepts postings and sends them out to the world. |
Spherical radiation pattern
On Sep 18, 3:18*pm, "Dave" wrote:
"Art Unwin" wrote in message ... Your profile states you are barred on all of your past postings! profile?? *what profile?? *we don't need no stinking profile! *this is usenet, i post via a news server, it has no profile of me, it just accepts postings and sends them out to the world. Well that is good news. I await your next insult |
Spherical radiation pattern
Cecil, W5DXP wrote:
"The forwerd and the reflected current sre in phase at the feedpoint and thus radiation is maximum at that maximum current point." Exactly. The reflected current has made s round trip of 180 degrees plus the reflection has added another 180 degrees for a total of 360 degrees or back in phase with the forward current at the feedpoint. At the open circuited ends of a resonant antenna there is almost double the forward voltage but zero total current due to cancellation of the dorward and reflected currents at the open circuit. At the open circuit in the wire, all the energy in the wave is transferred to the electric field. The relationship between the input power of a given antenna and the strength of the far electromagnetic field which it will produce depends among other factors the length and shape of the antenna. Best regards, Richard Harrison, KB5WZI |
Spherical radiation pattern
Dave wrote:
i will be gone in another week or so because verizon caved in and will be dumping usenet. maybe i'll resurrect myself with some other service, but none that i have to pay for, you aren't that much fun. Groups.google.com is free if one can tolerate the clumsy interface. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
Spherical radiation pattern
"Richard Harrison" wrote ... Cecil, W5DXP wrote: "The forwerd and the reflected current sre in phase at the feedpoint and thus radiation is maximum at that maximum current point." Exactly. The reflected current has made s round trip of 180 degrees plus the reflection has added another 180 degrees for a total of 360 degrees or back in phase with the forward current at the feedpoint. At the open circuited ends of a resonant antenna there is almost double the forward voltage Could you tell us if the "almost double voltage" is the measured of theoretically predicted? but zero total current due to cancellation of the dorward and reflected currents at the open circuit. At the open circuit in the wire, all the energy in the wave is transferred to the electric field. The relationship between the input power of a given antenna and the strength of the far electromagnetic field which it will produce depends among other factors the length and shape of the antenna. Best regards, Richard Harrison, KB5WZI S* |
Spherical radiation pattern
Szczepan Białek wrote:
Could you tell us if the "almost double voltage" is the measured of theoretically predicted? Since a voltage reference point is difficult to achieve at the ends of a dipole, we rely on the conservation of energy principle. Since the current is zero at the ends of a dipole, all the energy must be contained in the electric field. With that knowledge, the voltage can be estimated. Such is easy to understand by taking voltage measurements on a 1/4WL open-circuit stub. If one uses resistance wire for the stub, one can simulate radiation loss in a dipole. The following is a transmission line simulation of a 1/4WL monopole designed to run on the free demo version of EZNEC available from www.eznec.com http://www.w5dxp.com/stub_dip.EZ The user defined resistivity of the wire is what causes the 35 ohm feedpoint resistance akin to a 1/4WL monopole. The 10 megohm load allows us to look at the voltage across the "open" end of the stub. It is 1033 volts for a 100 watt input. We can assume the forward voltage and the reflected voltage at the end of the stub are equal at 516 volts. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
Spherical radiation pattern
"Cecil Moore" wrote ... Szczepan Białek wrote: Could you tell us if the "almost double voltage" is the measured of theoretically predicted? Since a voltage reference point is difficult to achieve at the ends of a dipole, we rely on the conservation of energy principle. Since the current is zero at the ends of a dipole, all the energy must be contained in the electric field. With that knowledge, the voltage can be estimated. Such is easy to understand by taking voltage measurements on a 1/4WL open-circuit stub. If one uses resistance wire for the stub, one can simulate radiation loss in a dipole. The following is a transmission line simulation of a 1/4WL monopole designed to run on the free demo version of EZNEC available from www.eznec.com http://www.w5dxp.com/stub_dip.EZ The user defined resistivity of the wire is what causes the 35 ohm feedpoint resistance akin to a 1/4WL monopole. The 10 megohm load allows us to look at the voltage across the "open" end of the stub. It is 1033 volts for a 100 watt input. We can assume the forward voltage and the reflected voltage at the end of the stub are equal at 516 volts. The acoustic analogy predict it: "Between the nodes are places where the amplitude is doubled. So the places with doubled amplitude are standing. Pressure pulse travel. In antennas is electron gas. The first place where the doubled amplitude (amplitude means voltage or electron density) appear is end of the radials. The next is halve wave apart from the end. Such places radiate strong electric waves. They are the source of radiation." S* -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
Spherical radiation pattern
Szczepan Białek wrote:
In antennas is electron gas. Your "electron gas" is a cloud of photons emitted by electrons. Those photons are infinitely "compressible". The first place where the doubled amplitude (amplitude means voltage or electron density) appear is end of the radials. The next is halve wave apart from the end. Such places radiate strong electric waves. They are the source of radiation." Again, it is impossible for the voltage maximums and current maximums to both radiate since such would double the radiated frequency which it doesn't. We usually transmit and receive on the same frequency. You must decide whether the peak radiation comes from the current maximum or the voltage maximum since they do not occur at the same time. Until you make that choice, rational discussion is not possible. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
Spherical radiation pattern
"Szczepan Bialek" wrote in message ... "Richard Harrison" wrote ... Cecil, W5DXP wrote: "The forwerd and the reflected current sre in phase at the feedpoint and thus radiation is maximum at that maximum current point." Exactly. The reflected current has made s round trip of 180 degrees plus the reflection has added another 180 degrees for a total of 360 degrees or back in phase with the forward current at the feedpoint. At the open circuited ends of a resonant antenna there is almost double the forward voltage Could you tell us if the "almost double voltage" is the measured of theoretically predicted? both |
Spherical radiation pattern
"Szczepan Bialek" wrote in message ... "Cecil Moore" wrote ... Szczepan Białek wrote: Could you tell us if the "almost double voltage" is the measured of theoretically predicted? Since a voltage reference point is difficult to achieve at the ends of a dipole, we rely on the conservation of energy principle. Since the current is zero at the ends of a dipole, all the energy must be contained in the electric field. With that knowledge, the voltage can be estimated. Such is easy to understand by taking voltage measurements on a 1/4WL open-circuit stub. If one uses resistance wire for the stub, one can simulate radiation loss in a dipole. The following is a transmission line simulation of a 1/4WL monopole designed to run on the free demo version of EZNEC available from www.eznec.com http://www.w5dxp.com/stub_dip.EZ The user defined resistivity of the wire is what causes the 35 ohm feedpoint resistance akin to a 1/4WL monopole. The 10 megohm load allows us to look at the voltage across the "open" end of the stub. It is 1033 volts for a 100 watt input. We can assume the forward voltage and the reflected voltage at the end of the stub are equal at 516 volts. The acoustic analogy predict it: "Between the nodes are places where the amplitude is doubled. So the places with doubled amplitude are standing. Pressure pulse travel. In antennas is electron gas. The first place where the doubled amplitude (amplitude means voltage or electron density) appear is end of the radials. The next is halve wave apart from the end. Such places radiate strong electric waves. They are the source of radiation." no, they are called electro-magnetic waves for a REASON! it takes BOTH fields to make up a propagating wave. So it is not the ends that radiate, it is the whole length where there are both electric and magnetic fields generated in smooth transitions of the sine wave, not in pulses. |
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