"Richard Clark" wrote in message
...
On Fri, 20 Nov 2009 18:26:17 -0600, "amdx" wrote:

Hi Richard,
What do you mean by "lack of driven element symmetry" ?
Mike
Hi Mike,

The driven loop is not symettrical to the plane of the directors and
reflector, thus it peers down (or up, or to the side - depending on
deployment).
Look boresight down the boom. The loop is off-center.

73's
Richard Clark, KB7QHC

Good, I thought that might be the answer but wanted to check.
Glad I added that detail to the drawing, do you think that is
engineered to control output impedance?
What happens to the impedance if you center it?

Could you post your model or send it to me, I have a fellow
ham that tried to model the FD and could not get it to work.
He would like to see one that does work and find out what he did wrong.
Eznec if you have it.
Thanks, Mike

On Sat, 21 Nov 2009 06:24:49 -0600, "amdx" wrote:

Could you post your model or send it to me, I have a fellow
ham that tried to model the FD and could not get it to work.
He would like to see one that does work and find out what he did wrong.
Eznec if you have it.
Thanks, Mike


Hi Mike,

It has been posted to you as you asked. Jeff also has a copy.

Can you tell us what you mean about your buddy's model and how he
"could not get it to work?" Did he follow your dimensions?

73's
Richard Clark, KB7QHC

"Richard Clark" wrote in message
...
On Sat, 21 Nov 2009 06:24:49 -0600, "amdx" wrote:

Could you post your model or send it to me, I have a fellow
ham that tried to model the FD and could not get it to work.
He would like to see one that does work and find out what he did wrong.
Eznec if you have it.
Thanks, Mike


Hi Mike,

It has been posted to you as you asked. Jeff also has a copy.

Can you tell us what you mean about your buddy's model and how he
"could not get it to work?" Did he follow your dimensions?

73's
Richard Clark, KB7QHC

He's out of town for a couple of days, when he returns I'll quiz him.
Mike