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Old December 1st 09, 09:18 AM posted to rec.radio.amateur.antenna
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Default Faraday shields and radiation and misinterpretations

K7ITM wrote:
I'm asking this because calls of 'troll' and 'loony' aren't working for me.


It's fairly straightforward, actually, if you believe in Faraday's law
of magnetic induction. That law says that for any closed loop (through
air, through a conductor, through anything), there is an electromotive
force (a voltage source, if you will) whose magnitude is proportional
to the rate of change of magnetic flux enclosed by the loop. As there
is no voltage drop along a perfect conductor, if your closed loop
follows the path of a perfect conductor, there is no voltage drop
around that loop, and therefore the rate of change of the total
magnetic flux enclosed by that loop must be zero. If the perfect
conductor is a closed box, then you can draw loops anywhere through
that conductor and you will never see a changing magnetic field
enclosed by that loop. Thus, the inside of the box and the outside are
magnetically independent; things happening on one side (magnetically)
are not sensed on the other side.

You can understand how this works if you realize that a changing
magnetic field outside the box that would penetrate the box if it
weren't there will induce currents in the conducting box (or even just
in a closed loop of wire). Those currents will (in a perfect
conductor) be exactly the right magnitude to cause a magnetic field
that cancels the external one everywhere inside the closed box (or the
net flux enclosed by a loop of wire). An example: if you short the
secondary of a mains transformer, the primary will draw lots of current
at its rated voltage: it's very difficult for the primary to change the
magnetic flux in the core.

Does the electric field shielding from a perfect conductor need any
explanation?

Of course, an imperfect conductor will be an imperfect magnetic shield.
But a perfect conductor won't let any change of field through, no
matter how slow (no matter how low an EMF it generates), so a perfect
conductor works as a shield all the way down to DC. A box made with an
imperfect conductor is essentially a perfect shield if the box's wall
thickness is at least many skin-depths thick at the frequency of interest.

That's a quick beginning. You can find lots more about this in E&M
texts. There's even useful stuff about it on the web. ;-)


Here is a link to a generalized proof of the skin effect:

http://www.ifwtech.co.uk/g3sek/misc/skin.htm

This is exactly equivalent to Tom's explanation above. The detailed
proof is quite mathematical but it is solidly based in classical physics
- Faraday's Law and Ampere's theorem (both of which are embodied in
Maxwell's equations). This derivation produces the well-known equations
for current density as a function of depth, conductivity and
permeability.

The special feature of this particular proof is that it's much more
general than the ones you see in better-known textbooks - and therefore
much more powerful. It shows that if RF current is flowing in/on *any*
conducting surface, for *any* reason, then the skin effect will be
present.

The possible reasons why RF current may be flowing can be divided into
two main groups:

* "Circuit conditions" - the conductor is part of a circuit that makes
RF current flow.

* "Electromagnetic induction" - the conductor is intercepting an
incident electromagnetic wave which induces a current.

In either case, an RF current flows... and wherever that happens, there
you will also find the skin effect.



--

73 from Ian GM3SEK
http://www.ifwtech.co.uk/g3sek
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Old December 1st 09, 09:50 AM posted to rec.radio.amateur.antenna
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Default Faraday shields and radiation and misinterpretations

Ian White GM3SEK wrote in
:

http://www.ifwtech.co.uk/g3sek/misc/skin.htm

This is exactly equivalent to Tom's explanation above. The detailed
proof is quite mathematical but it is solidly based in classical physics
- Faraday's Law and Ampere's theorem (both of which are embodied in
Maxwell's equations). This derivation produces the well-known equations
for current density as a function of depth, conductivity and
permeability.


Thanks, that linking of laws and theories will help me (and the confirmation
that classical physics will be enough to describe it, as I hoped). The OP
mentioned Maxwell too... so did he make some error I have yet to grasp? Other
than taking pot shots at an establishment, that is...

The special feature of this particular proof is that it's much more
general than the ones you see in better-known textbooks - and therefore
much more powerful. It shows that if RF current is flowing in/on *any*
conducting surface, for *any* reason, then the skin effect will be
present.


That appeals to me. I think the more something can be seen to apply
generally, the more it helps. Proportion can't be gauged with a model that
denies it.
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Old December 1st 09, 06:41 PM posted to rec.radio.amateur.antenna
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First recorded activity by RadioBanter: Oct 2008
Posts: 173
Default Faraday shields and radiation and misinterpretations


"Ian White GM3SEK" wrote in message
...
K7ITM wrote:
I'm asking this because calls of 'troll' and 'loony' aren't working for
me.


- snip -

Here is a link to a generalized proof of the skin effect:

http://www.ifwtech.co.uk/g3sek/misc/skin.htm

This is exactly equivalent to Tom's explanation above. The detailed proof
is quite mathematical but it is solidly based in classical physics


- further snip -
--

73 from Ian GM3SEK
http://www.ifwtech.co.uk/g3sek



Your statement on your web page 'It is temporarily reproduced here, under
provisions of the Berne Copyright Convention, to support technical
discussions on the rec.radio.amateur.antenna newsgroup' looks interesting
because, to the best of my knowledge, the issue of the legality of copying
parts of others' published work onto Web sites hasn't been resolved. I
can't find any specific provision in the Berne Convention that _allows_
re-publishing on the Internet - it looks more likely to inhibit it because
Web sites are automatically worldwide.

On the page 'http://www.copyrightservice.co.uk/copyright/p09_fair_use' it
is stated: 'Under fair use rules, it may be possible to use quotations or
excerpts, where the work has been made available to the public, (i.e.
published). Provided that:
a.. The use is deemed acceptable under the terms of fair dealing.
b.. That the quoted material is justified, and no more than is necessary
is included.
c.. That the source of the quoted material is mentioned, along with the
name of the author.'
But also: 'The actual specifics of what is acceptable will be governed by
national laws, and although broadly similar, actual provision will vary from
country to country.'

Presumably you have researched this matter, and I for one would be
interested to hear what you've found that appears to cover international www
re-publishing.

Chris



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