On May 27, 9:50*am, lu6etj wrote:
Also I am interested in check other values and
conditions in your other article (first part) with 45 degree line.

Sorry, I forgot to comment on this. If the line length is fixed at 45
degrees, the reflected wave arrives back at the 50 ohm source resistor
90 degrees out of phase with the source's forward wave. When two waves
are 90 degrees out of phase, there is zero interference between them
because cos(90) = 0 and the interference term in the following
equation disappears.

Ptot = P1 + P2 + 2*SQRT(P1*P2)cos(theta)

There is no re-reflection of the reflected wave from the 50 ohm source
resistor because it matches the coax Z0. There is no redistribution of
constructive/destructive interference energy because there is zero
interference. Therefore, for the special case where Vfor is 90 degrees
out of phase with Vref at the source resistor, all of the reflected
power will be dissipated in the source resistor.

If the interference at the source resistor is constructive, i.e. less
than 90 degrees difference between Vfor and Vref, the power dissipated
in the source resistor will be all of the reflected power plus some of
the source power.

If the interference at the source resistor between Vfor and Vref is
destructive, i.e. between 90 degrees and 180 degrees, some of the
reflected power will be redistributed (by wave cancellation) back
toward the load.

Note that the I and Q method of transferring two streams of
information on the same carrier relies on this same no interference
(at 90 degrees) concept.
--
73, Cecil, w5dxp.com