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On Jun 6, 10:22*am, "JC" wrote:
Basic question (at least for me) for a very poor antenna matching : -100 w reach the antenna and 50 w are radiated. - 50 w are "reflected", what is their fate ? Are they definitely lost for radiation and just heat the line, the final..... JC I assume that your numbers were obtained using a directional wattmeter, that is, forward power is 100W, 50W are reflected and by subtraction, it is computed that 50W enter the antenna, some of which is dissipated in the antenna losses and some of which is radiated. The 100W forward and 50W reflected have no relation to actual powers but are simply values that are constructed so that when they are subtracted the result is the average power flowing towards the load. From these numbers alone it is impossible to decide whether the system is operating as it should or to compute where the losses might be, or whether there are any losses at all. With an appropriate antenna tuner it is entirely possible that the transmitter is delivering its design output of 50W to the line and all of this energy is reaching the antenna and being radiated. Thus the whole question of "where does the reflected power go?", is rather misleading. ....Keith |
#2
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On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart
wrote: The 100W forward and 50W reflected have no relation to actual powers From HP Journal V.7n.2: If an incident wave is applied at the left as shown in the diagram, the wave passes down the main arm. In the region where the lines are cou pled, a wave 20 db below the inci dent wave will be coupled to the "Forward" terminal, while a second wave 20 db below the incident wave will be coupled to the resistive ter mination in the "Reverse" arm. Since the combined power in the two split-off waves amounts to only 2% of the power in the main wave, the main wave is essentially unalt ered and continues to the right-hand terminal. A wave applied at the right end of the coupler is coupled in an analo gous manner. Waves 20 db below the left-traveling wave will be coupled to the "Reverse" terminal and to the resistive termination in the "For ward" arm, while the main part of the wave continues to the left-hand terminal. The couplers thus provide equal fractions of right-traveling and left traveling waves at separate termin als. The ratio of these waves will be equal to p *, the magnitude of the reflection coefficient of any device connected to the output of the cou pler. This ratio can be measured (Fig. 4) by applying the outputs of the "Forward" and "Reverse" ter minals to the -hp- 416A Ratio Meter, using suitable detectors to demodu late the amplitude-modulated power which must be used with the system. In an ideal directional coupler, no power from a forward wave would be received at the reverse terminal and no power from a reverse wave would be received at the forward ter minal. In practice some undesired power is received at these terminals, although it has been possible to de sign the couplers so that this unde sired power is at least 46 db below the parent wave, i.e, at least 26 db below the desired wave at the oppo site terminal. In other words the di rectivity of the couplers is at least 26 db (30 db in the lower frequency couplers) over the complete fre quency range [Fig. 3(a), (b)]. The coupling mechanism itself consists of quarter-wavelength sec tions of the conductors placed suit ably near one another to achieve the desired degree of coupling. The combined effects of electrical and magnetic coupling impart directiv ity to the coupled wave. The unused terminal of each of the auxiliary arms is terminated in a special widerange low-reflection resistor to ab sorb any power coupled to that ter minal. 73's Richard Clark, KB7QHC |
#3
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On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart
wrote: The 100W forward and 50W reflected have no relation to actual powers From HP Journal V4n5-6: The multi-hole coupler design has now been extended to a 3 db coupler, that is, a coupler in which half the power entering the main guide is coupled into the auxiliary guide. .... The -hp- multi-hole couplers consist of two sections of wave guide mutually coupled by two rows of coupling holes (Fig. 2). Power entering the input arm of the coupler flows down the main guide and divides at the coupling mechanism. Part of the power con tinues down the main guide where it will be incident on any device connected at the end of the guide. The other part of the power is coupled into the auxiliary guide. It is a prop erty of directional couplers that the power coupled into the auxiliary guide flows essen tially in only one direction. In the -hp- coup ler, this power flow is in the same direction as the power in the primary guide. .... R E F L E C T O M E T E R S E T - U P .... Two directional couplers are connected back-to-back as shown. ******* I will leave it to the readership to imagine why. 73's Richard Clark, KB7QHC |
#4
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On Jun 6, 9:34*pm, Richard Clark wrote:
On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart wrote: The 100W forward and 50W reflected have no relation to actual powers From HP Journal V4n5-6: The multi-hole coupler design has now been extended to a 3 db coupler, that is, a coupler in which half the power entering the main guide is coupled into the auxiliary guide. ... The -hp- multi-hole couplers consist of two sections of wave guide mutually coupled by two rows of coupling holes (Fig. 2). Power entering the input arm of the coupler flows down the main guide and divides at the coupling mechanism. Part of the power con tinues down the main guide where it will be incident on any device connected at the end of the guide. The other part of the power is coupled into the auxiliary guide. It is a prop erty of directional couplers that the power coupled into the auxiliary guide flows essen tially in only one direction. In the -hp- coup ler, this power flow is in the same direction as the power in the primary guide. ... R E F L E C T O M E T E R * S E T - U P ... Two directional couplers are connected back-to-back as shown. ******* I will leave it to the readership to imagine why. 73's Richard Clark, KB7QHC Walter was the first to place things in a book and a book is the first point of reference in this newsgroup Nothing personal Richard, but it is obvious that engineers are totally split as to what theorem is correct and the one to be used. There is no way you will get agreement if they all insist their position is correct and thus other positions are not worth consideration.You may be correct in your position but the idea of change is not in your favor. |
#5
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On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart
wrote: The 100W forward and 50W reflected have no relation to actual powers From HP Journal V.3n7-8 DIRECTIONAL couplers have been used widely in wave guide applications for such purposes as monitoring power, meas uring reflections, mixing, and for isolation of signal sources. All of these applications make use of the property that power flowing in one direction in the main branch of the coupler induces a power flow in only one direction in the auxiliary circuit. 73's Richard Clark, KB7QHC |
#6
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On Jun 7, 1:37*am, Richard Clark wrote:
All of these applications make use of the property that power flowing in one direction in the main branch of the coupler induces a power flow in only one direction in the auxiliary circuit. Power flow??? Heaven forbid. -- 73, Cecil, w5dxp.com |
#7
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On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart
wrote: The 100W forward and 50W reflected have no relation to actual powers From HP Journal V.6n.1-2: Power from the source flows down the main arms of the two couplers (Fig. 2) and impinges on the load. The power split off by the 20 db forward coupler is all passed to the forward detector, since the directiv ity characteristic of the multi-hole directional couplers prevents any but a negligible amount of the splitoff power from turning back and being absorbed in the coupler's in ternal termination. The power split off the incident wave by the 10 db reverse coupler, however, is essen tially all absorbed in that coupler's internal termination because of the reversed direction of connection of that coupler (Fig. 2). If the magnitude of the reflection coefficient ~.T. of the load is, say, 0.1, Çf of the incident voltage will be reflected back toward the source. As this reflection passes back through the main arm of the reverse coupler, a 10 db split occurs and is applied to the reverse detector. The remain der of the reflection will proceed back toward the generator where it will be absorbed in the generator impedance and in the termination in the forward coupler. ******** Of course, in regard to this last sentence, HP engineers didn't know jack-**** about power reflections, especially what could be absorbed by the source. 73's Richard Clark, KB7QHC |
#8
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On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart
wrote: The 100W forward and 50W reflected have no relation to actual powers From a current NARDA specification: GENERAL COUPLER OPERATION A coaxial directional coupler has the general appearance of a section of coaxial line, with the addition of a second parallel section of line and with one end terminated (see Figure 9). These two sections are known as the main and auxiliary lines. The two lines are internally separated from each other; the amount of spacing between lines determines the amount of RF energy that may be transferred from the main line to the auxiliary line. In operation, assume that energy is fed into port A of the main line. Most of this energy will appear at output port B of the main line. However, a fraction of this energy (determined by coupling value) will also appear at the coupled port C, of the auxiliary line. A dual-directional coaxial coupler, such as the reflectometer coupler, consists essentially of two single- ended couplers connected back-to-back. Perhaps the most important characteristic of the directional coupler (and the one from which its name originates) is its directivity. .... For reflectometry applications, the dual directional coupler, incorporating two auxiliary outputs, permits the simultaneous sampling of incident and reflected power. .... RF power applied to the load is reflected to some degree depending on load characteristics, thereby resulting in a voltage standing wave ratio (VSWR) which is reflected back to the main line output port. this reflected power is coupled out of the reflected output port at a level 10 dB down from the reflected power level at the load. 73's Richard Clark, KB7QHC |
#9
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On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart
wrote: The 100W forward and 50W reflected have no relation to actual powers From MECA, makers of Isolators - their application: The isolator is placed in the measurement path of a test bench between a signal source and the device under test (DUT) so that any reflections caused by any mismatches will end up at the termination of the isolator and not back into the signal source. This example also clearly illustrates the need to be certain that the termination at the isolated port is sufficient to handle 100% of the reflected power should the DUT be disconnected while the signal source is at full power. If the termination is damaged due to excessive power levels, the reflected signals will be directed back to the receiver because of the circular signal flow. .... MECA offers twenty-four models of isolators and circulators in both N and SMA-female connectors with average power ratings from 2 - 250 watts. 73's Richard Clark, KB7QHC |
#10
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On Jun 8, 3:47*am, Richard Clark wrote:
On Sun, 6 Jun 2010 14:21:16 -0700 (PDT), Keith Dysart wrote: The 100W forward and 50W reflected have no relation to actual powers From MECA, makers of Isolators - their application: The isolator is placed in the measurement path of a test bench between a signal source and the device under test (DUT) so that any reflections caused by any mismatches will end up at the termination of the isolator and not back into the signal source. This example also clearly illustrates the need to be certain that the termination at the isolated port is sufficient to handle 100% of the reflected power should the DUT be disconnected while the signal source is at full power. If the termination is damaged due to excessive power levels, the reflected signals will be directed back to the receiver because of the circular signal flow. ... MECA offers twenty-four models of isolators and circulators in both N and SMA-female connectors with average power ratings from 2 - 250 watts. Good day Richard, You have located several examples from reputable vendors where the behaviour of directional couplers is described in terms of power in a forward and reflected wave. This model of behaviour works within its limits and allows for convenient computation and prediction of the behaviour. But all of these papers have the appropriate discipline and do not ask the question "where does the reflected energy go?" which is good, for this exceeds the limits of the model. As soon as one assigns tangible energy to the reflected wave, it becomes reasonable to ask for an accounting of this energy and the model is incapable of properly accounting for the energy. Following this weakness back through the model, the root cause is the attempt to assign tangible energy to the reflected wave. Think of it as a reflected voltage or current wave and all will be well, but assign power to it and eventually incorrect conclusions will be drawn. For those who understand this, and know that "where did the reflected energy go?" is an invalid question, using the power model within its limits will not cause difficulties. But for those who are not careful, great difficulties arise and a lot of fancy dancing is offered to work around the difficulties, unsuccessfully. Just for fun, here is a simple example. 100V DC source, connected to a 50 ohm source resistor, connected to 50 ohm transmission line, connected to a 50 ohm load resistor. Turn on the source. A voltage step propagates down the line to the load. The impedances are matched, so there are no reflections. The source provides 100W. 100W is dissipated in the source resistor. 100W is dissipated in the load resistor. Energy moves along the transmission line from the source to the load at the rate of 50W. All is well. Disconnect the load. A voltage step propagates back along the line from the load to the source. In front of this step current continues to flow. Behind the step, the current is 0. When the step reaches the source there is no longer any current flowing. The source is no longer providing energy, the source resistor is dissipating nothing, and neither is the load resistor. Proponensts of the power model claim that energy is still flowing down the line, being reflected from the open end and flowing back to the source. Since the source is clearly no longer providing energy, great machinations are required to explain why the reflected 'energy' is re-reflected to provide the forward 'energy'. But really, does anyone believe that a length of transmission line, charged to 100V voltage with zero current flowing, is actually simultaneously transporting energy in both directions? For even more fun, replace the ideal conductors in the transmission line with some lossy conductors. How much of the reflected and re-reflected energy flowing up and down the line will be dissipated in the conductors? Remember that the current is zero, everywhere along the line. ....Keith |
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