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On Jun 25, 9:00*am, Cecil Moore wrote:
On Jun 25, 2:13*am, lu6etj wrote: In a TL, instead, total destructive interference in one point would mean energy stop flowing from that point forwards (is it OK say "forwards"?) and reverse its flow direction doubling his value, is it OK?. In our ham transmission line systems, the goal is to accomplish total destructive interference toward the source, i.e. zero reflected energy incident upon the source. So let's talk about destructive interference toward the source and constructive interference toward the load. You name it "redistribution" too, not reflection. By definition, reflection is something that happens to a single wave. By definition, superposition involves two or more waves. The redistribution that I am talking about can include both reflection and superposition if both are present. Depending upon the system configuration, both may be present, both may be absent, or one exist without the other. Well, my question was how we can set (devise) an experiment to get such behaviour in a TL? I've presented it before and it is a simple Z0-match involving a 1/4WL matching section. 50w-----50 ohm------+------1/4WL 300 ohm------1800 ohm load On the source side, rho at '+' is 0.7143 Using a TDR, we can verify that there is indeed a reflection from the 50/300 ohm impedance discontinuity. What happens to that reflection during steady-state? What happens to Vfor1(rho) = 50v(0.7143) = 35.7v? Using superposition, when you add Vrev2(tau) to Vfor1(rho) you get zero. With zero voltage comes 0 energy transfer. For further learning, do not just examine steady state, but also examine how it gets to steady state. Using a lattice diagram, examine what happens as the first reflection and then each re-reflection arrives at '+'. Determine how Vrev2(tau) slowly builds to equal Vrev1 and cancels it, using the simple addition of superposition. While this process is occurring, there is a Vrev1 which decreases after each round trip in the second line section. This is all done with simple addition. No need for products and square roots. For further marks, decide whether you should think of Vrev2 as an infinite sum of reverse waves or is it okay to think of it as one sum that slowly accumulates. Which is it really? Same question for Vfor2. What happens to Pfor1(rho^2) = 50w(0.51) = 25.5w? Once you have computed total Vrev1 using simple superposition, it is easy to compute that the "reverse power", Prev1, is 0. Do you really need rho^2 to understand what goes on in a transmission line? ....Keith |
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