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Old June 12th 10, 12:27 AM posted to rec.radio.amateur.antenna
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First recorded activity by RadioBanter: Jul 2006
Posts: 2,951
Default Where does it go? (mismatched power)

On Fri, 11 Jun 2010 14:29:17 -0700 (PDT), K1TTT
wrote:

you can qualify an impedance as non-dissipative


It's called reactance.

There are certainly some contortions that have evolved from an
argument that the source lacks the ability to dissipate.

Impedance = (R ± jX) Ohm

This is well known by all and yet it seems unsatisfactory and
impossible to measure in a Tube even when R is exhibited both by
measurement and by heat - something that by all normal accounts is
evidence of dissipation. That same heat seems to be unaccountable
because it's non-linear? If you use this heat on an ice cube, do you
get harmonics? Even or odd?

If it doesn't dissipate it must be because it has NOhms. If we embark
further on this mysterious Load Conjugation with a loss-less resistor,
what would we see for the Load Objurgation formula?

rraaZ = (Rr ± iR ± jX) NOhm

We must now have a Nimpedance measured along a second (hither too
unreported) imaginary axis. I can imagine the dawn of the new Photon
Ninterferences that will emerge from this.

KEWEL !

73's
Richard Clark, KB7QHC
 
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