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#1
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On Jun 11, 5:03*pm, lu6etj wrote:
From my perspective your main differences are reducible The basic argument revolves around what math shortcuts can be used to solve a particular problem vs what is actually happening in reality according to the accepted laws of physics. I agree one doesn't necessarily need to understand the laws of physics to solve a problem but one should probably know enough physics to recognize when those laws of physics are being violated by one's argument. -- 73, Cecil, w5dxp.com |
#2
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On 11 jun, 23:26, Cecil Moore wrote:
On Jun 11, 5:03*pm, lu6etj wrote: From my perspective your main differences are reducible The basic argument revolves around what math shortcuts can be used to solve a particular problem vs what is actually happening in reality according to the accepted laws of physics. I agree one doesn't necessarily need to understand the laws of physics to solve a problem but one should probably know enough physics to recognize when those laws of physics are being violated by one's argument. -- 73, Cecil, w5dxp.com ............ of course, but that is no fun! I agree ![]() ![]() ...... As a courtesy to me, a foreigner tourist ham, would you mind stop for a brief moment your more general differences and tell me if you agree on the behavior of a Thevenin generator with a series resistance of 50 ohms in relation to changes in impedance of a lossless TL predicted by the Telegrapher's equations solutions in terms of the power dissipated on the load resistance and series resistence of Thevenin source? I am pretty serious about this: until today I could not know if you agree in that!! :) |
#3
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On Jun 12, 4:24*am, lu6etj wrote:
On 11 jun, 23:26, Cecil Moore wrote: On Jun 11, 5:03*pm, lu6etj wrote: From my perspective your main differences are reducible The basic argument revolves around what math shortcuts can be used to solve a particular problem vs what is actually happening in reality according to the accepted laws of physics. I agree one doesn't necessarily need to understand the laws of physics to solve a problem but one should probably know enough physics to recognize when those laws of physics are being violated by one's argument. -- 73, Cecil, w5dxp.com ........... of course, but that is no fun! I agree ![]() ![]() ..... As a courtesy to me, a foreigner tourist ham, would you mind stop for a brief moment your more general differences and tell me if you agree on the behavior of a Thevenin generator with a series resistance of 50 ohms in relation to changes in impedance of a lossless TL predicted by the Telegrapher's equations solutions in terms of the power dissipated on the load resistance and series resistence of Thevenin source? I am pretty serious about this: until today I could not know if you agree in that!! :) sure, if you properly apply the telegrapher's equations and the thevenin equivalent methods. The real problem is that if you try to do that for most amateur radio transmitters the source impedance is not linear, and even worse may be time varying, which renders the thevenin equivalent source substitution invalid. Note though that in real world cases you need to use the full set of equations, usually called by engineers the 'general transmission line equations'. beware, some places may over simplify the telegrapher's equations which may make them invalid in some cases. The Telegrapher's equations (http://en.wikipedia.org/wiki/Telegrapher %27s_equations), are often considered a subset of the 'General transmission line equations (http://en.wikipedia.org/wiki/ Transmission_line) that are taught in distributed circuits and fields and waves courses in engineering schools. |
#4
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....
As a courtesy to me, a foreigner tourist ham, would you mind stop for a brief moment your more general differences and tell me if you agree on the behavior of a Thevenin generator with a series resistance of 50 ohms in relation to changes in impedance of a lossless TL predicted by the Telegrapher's equations solutions in terms of the power dissipated on the load resistance and series resistence of Thevenin source? I am pretty serious about this: until today I could not know if you agree in that!! :) sure, if you properly apply the telegrapher's equations and the thevenin equivalent methods. *The real problem is that if you try to do that for most amateur radio transmitters the source impedance is not linear, and even worse may be time varying, which renders the thevenin equivalent source substitution invalid. OK. Thank you very much. This clarify so much the issue to me. Please, another question: On the same system-example, who does not agree with the notion that the reflected power is never dissipated in Thevenin Rs? (I am referring to habitual posters in these threads, of course) |
#5
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lu6etj wrote in news:da3e5147-cad8-47f9-9784-
: .... OK. Thank you very much. This clarify so much the issue to me. Please, another question: On the same system-example, who does not agree with the notion that the reflected power is never dissipated in Thevenin Rs? (I am referring to habitual posters in these threads, of course) Thevenin's theorem says nothing of what happens inside the source (eg dissipation), or how the source may be implemented. It is the implementation of the source that provides the answer to your question, and the word "never" is too strong for the general case. In respect of typical HF ham transmitters, you may find my article entitled "Does SWR damage HF ham transmitters?" at http://vk1od.net/blog/?p=1081 of interest. Owen |
#6
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On 12 jun, 17:28, Owen Duffy wrote:
lu6etj wrote in news:da3e5147-cad8-47f9-9784- : ... OK. Thank you very much. This clarify so much the issue to me. Please, another question: On the same system-example, who does not agree with the notion that the reflected power is never dissipated in Thevenin Rs? (I am referring to habitual posters in these threads, of course) Thevenin's theorem says nothing of what happens inside the source (eg dissipation), or how the source may be implemented. It is the implementation of the source that provides the answer to your question, and the word "never" is too strong for the general case. In respect of typical HF ham transmitters, you may find my article entitled "Does SWR damage HF ham transmitters?" athttp://vk1od.net/blog/?p=1081of interest. Owen Hello Owen thank you for your answer: Sorry I do not quite understand your answer. I choose a Thevenin model of circuit theory because it is an idealization consisting of an idealized constant voltaje source in series with an idealized resistance without any relation with practical implementation of such imaginary electrical (and mathematical) entity. I first interested get from you such idealized model answer as a reductionistic aproximation method to try arrive later at subsequent interpretations of practical situations. I think we all used to working with idealized models and we accept its limitations, but we also know frequently they are very useful to clear the "field" (as in football "field") (I said "never" because Cecil seem say "sometimes"). For example: ideal conjugate mirror in Maxwell article in my interpretation implicates "never". Reflected power do not return to the source in that context. If you prefer I would be equally satisfied knowing who agree with "never", who with "sometimes" and who with "always". But I would not be too annoying :) 73 Miguel Ghezzi LU6ETJ |
#7
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lu6etj wrote in
: On 12 jun, 17:28, Owen Duffy wrote: lu6etj wrote in news:da3e5147-cad8-47f9-9784- : ... OK. Thank you very much. This clarify so much the issue to me. Please, another question: On the same system-example, who does not agree with the notion that the reflected power is never dissipated in Thevenin Rs? (I am referring to habitual posters in these threads, of course) Thevenin's theorem says nothing of what happens inside the source (eg dissipation), or how the source may be implemented. It is the implementation of the source that provides the answer to your question, and the word "never" is too strong for the general case. In respect of typical HF ham transmitters, you may find my article entitled "Does SWR damage HF ham transmitters?" athttp://vk1od.net/blog/?p=1081of interest. Owen Hello Owen thank you for your answer: Sorry I do not quite understand your answer. I choose a Thevenin model of circuit theory because it is an idealization consisting of an idealized constant voltaje source in series with an idealized resistance without any relation with practical implementation of such imaginary electrical (and mathematical) entity. I first interested get from you such idealized model answer as a reductionistic aproximation method to try arrive later at subsequent interpretations of practical situations. I think we all used to working with idealized models and we accept its limitations, but we also know frequently they are very useful to clear the "field" (as in football "field") Miguel, From Wikipedia: "Thévenin's theorem for linear electrical networks states that any combination of voltage sources, current sources and resistors with two terminals is electrically equivalent to a single voltage source V and a single series resistor R. For single frequency AC systems the theorem can also be applied to general impedances, not just resistors." The theorem does not state or imply that the Thevenin equivalent circuit dissipates the same internal power as the real source, just that any *linear* two terminal circuit containing sources and impedances can be reduced to this two component equivalent (at a single frequency), and V and I at the network terminals will be the same as the original network, irrespective of the external load attached to the network terminals. It is a simple exercise to develop two source networks with the same Thevenin equivalent circuit, but that have quite different internal efficiencies. It is easy to demonstrate that both networks deliver the same power to any given load, but that the internal dissipation of those source networks is different in both cases, and not explainable simply as absorbing 'reflected power'. This is basic linear circuit theory. If there was a valid Thevenin equivalent circuit for a transmitter (and that is questionable), then you can not use that equivalent circuit to make any inference about the internal dissipation of the source (the transmitter in this case), or its efficiency. Nevertheless, I see people trying to do this one way or another in the various threads here. (I said "never" because Cecil seem say "sometimes"). For example: ideal conjugate mirror in Maxwell article in my interpretation implicates "never". Reflected power do not return to the source in that context. If you prefer I would be equally satisfied knowing who agree with "never", who with "sometimes" and who with "always". But I would not be too annoying :) I know that in this age of instant gratification, people reading posts in these fora tend to accept simple dogmatic statements as sure sign of author credibility, and qualifications such as 'often', 'usually' etc as a sign of uncertainty, of a lack of understanding, of weakness in the author. The opposite is often, if not usually true. In English, we have a saying "never say never". What 'never'? 'Hardly ever'... to borrow some dialogue. A man who is hardly ever wrong doesn't use words like 'always' and 'never' much, or imply as much in general statements. Owen |
#8
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Owen Duffy wrote:
lu6etj wrote in news:da3e5147-cad8-47f9-9784- : ... OK. Thank you very much. This clarify so much the issue to me. Please, another question: On the same system-example, who does not agree with the notion that the reflected power is never dissipated in Thevenin Rs? (I am referring to habitual posters in these threads, of course) Thevenin's theorem says nothing of what happens inside the source (eg dissipation), or how the source may be implemented. . . . Cecil has used this fact as a convenient way of avoiding confrontation with the illustrations given in my "food for thought" essays. However, those models aren't claimed to be Thevenin equivalents of anything. They are just simple models consisting of an ideal source and a perfect resistance, as used in may circuit analysis textbooks to illustrate basic electrical circuit operation. The dissipation in the resistance is clearly not related to "reflected power", and the reflected power "theories" being promoted here fail to explain the relationship between the dissipation in the resistor and "reflected power". I contend that if an analytical method fails to correctly predict the dissipation in such a simple case, it can't be trusted to predict the dissipation in other cases, and has underlying logical flaws. For all the fluff about photons, optics, non-dissipative sources, and the like, I have yet to see an equation that relates the dissipation in the resistance in one of those painfully simple circuits to the "reflected power" in the transmission line it's connected to. Roy Lewallen, W7EL |
#9
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Roy Lewallen wrote in
: For all the fluff about photons, optics, non-dissipative sources, and the like, I have yet to see an equation that relates the dissipation in the resistance in one of those painfully simple circuits to the "reflected power" in the transmission line it's connected to. I saw the challenge and note the lack of response. Let me offer a steady state solution. In the case of a simple source being an ideal AC voltage generator of Vs and an ideal series resistance Rs of Ro, and that Zo=Ro, for any arbitrary load, at the source terminals, Vf=Vs/2, Vl=Vf+Vr=Vs/2+Vr, and the voltage difference across Rs is Vs/2-Vr (noting that Vr is a complex quantity and can have a magnitude from 0 to Vs/2 at any phase angle), therfore dissipation in Rs is given by: Prs=(Vs/2-Vr)^2/Rs where Vs is the o/c source voltage, Vr is the complex reflected wave voltage equivalent, Rs is the source resistance. Clearly, dissipation in Rs is related to Vr, but it is not simply proportional to the square of Vr as believed by many who lack the basics of linear circuit theory to come to a correct understanding. Roy, is that a solution? Owen |
#10
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On Jun 15, 6:36*pm, Roy Lewallen wrote:
Owen Duffy wrote: lu6etj wrote in news:da3e5147-cad8-47f9-9784- : ... OK. Thank you very much. This clarify so much the issue to me. Please, another question: On the same system-example, who does not agree with the notion that the reflected power is never dissipated in Thevenin Rs? (I am referring to habitual posters in these threads, of course) Thevenin's theorem says nothing of what happens inside the source (eg dissipation), or how the source may be implemented. . . . Cecil has used this fact as a convenient way of avoiding confrontation with the illustrations given in my "food for thought" essays. However, those models aren't claimed to be Thevenin equivalents of anything. They are just simple models consisting of an ideal source and a perfect resistance, as used in may circuit analysis textbooks to illustrate basic electrical circuit operation. The dissipation in the resistance is clearly not related to "reflected power", and the reflected power "theories" being promoted here fail to explain the relationship between the dissipation in the resistor and "reflected power". I contend that if an analytical method fails to correctly predict the dissipation in such a simple case, it can't be trusted to predict the dissipation in other cases, and has underlying logical flaws. For all the fluff about photons, optics, non-dissipative sources, and the like, I have yet to see an equation that relates the dissipation in the resistance in one of those painfully simple circuits to the "reflected power" in the transmission line it's connected to. Roy Lewallen, W7EL obviously its not the 'reflected power'... that can be easily disproved by showing that the length of the line changes the impedance seen at the source terminals without changing the power that was reflected from the load. since it is the impedance at the source terminals that determines the performance of the amp the power that is reflected is irrelevant. however, it should be relatively easy to derive such a relation for a simple thevenin source with a lossless line and a given load impedance... just transform the impedance along the length of the line back to the source then calculate the resulting current or voltage from the source. that would give you the power dissipated in the source. then you could also calculate the reflection coefficient and separate the forward and reflected waves... and if you did it all correctly and kept everything in terms of RL, Z0, and the length of the line you could come up with a family of parametric curves relating the power dissipated in the source resistance to the reflected power over a range of load impedances for a given line length, or for varying line length for a given load. obviously a purely academic exercise that should be left for a rainy day. |
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