On 16 jun, 03:48, Owen Duffy wrote:
lu6etj wrote :

...

For not to work too much, calculations could be reduced to three
resistive Zls, and three lengths of TL. Let me suggest 25, 50 and 100
ohms RLs and 0.5, 0.25 and 0.125 of lambda (to honor Cecil and Roy
papers), Vg voltage = 100 V RMS, Rs 50 ohms, Zo obviously 50 ohms too
(lossless line). Zl=50 ohms and 1/2 lambda TL are for beginners, as
me ;D

Miguel, I gave an expression for power in your simple source circuit in a
recent post, did you see it. Well here it is again:

Prs=(Vs/2-Vr)^2/Rs where Vs is the o/c source voltage, Vr is the complex
reflected wave voltage equivalent, Rs is the source resistance.

If the reflected wave was always, and entirely dissipated in Rs in that
type of source, then Prs=Vr^2/Zo=Vr^2/Rs... but it isn't, see the above
expression.

You can work one case, three cases, three x three cases, but they are not
as complete as the expression above that shows that in the steady state,
Prs is not simply equal to the 'reflected power'.

But if you want, work the cases and report the results here, it is a
trivial exercise. You will accept the results more readily if you work it
our yourself.

Owen

Do not argue with me Owen... If you do not want put your numbers you
are free, Roy played theirs, Cecil too, it is a simple and loving
exercise of numeric agreement. No arguments, no algebra, no calculus,
no photons, no Quantum, no Maxwell, no clever and slippery words...
simple and crude numbers... Not more than five minutes. :)

73. Here 04:26 I am go to dream with the little angels... Thanks,
Miguel LU6ETJ