On Jul 6, 12:20*am, Keith Dysart wrote:
Is there a problem providing an answer?

I don't know how to measure the exact answer. How many photons does it
take to cause a measurable EM field at one cycle per two years? If the
EM field is too low to measure, how do you know it is there at all?
Blind faith in a math model?

Does either one of these views assist you with deciding whether
there are EM waves present during the one year intervals where
the signal value does not change?

No they don't. The problem is random/natural/man-made EM noise. When
the EM wave level drops far below the EM noise, how can you measure
the EM wave level? If you cannot measure it, you are back to angels on
the head of a pin.

If the square wave frequency was 1 MHz, would you have the same
difficulty deciding? Why not?

Because I could measure those EM waves.

So are now saying there may indeed be an EM wave
present with DC? Even with DC, the electrons are not moving with
constant velocity but hop from atom to atom. Seems like
acceleration and deceleration to me.

No, EM waves do not exist at DC steady-state. Those are free electrons
which do not change orbital levels. The only force acting on an
electron during DC steady-state is a constant force.

Maybe you should just start with Kirchoff's current law and
understand what it says before following my suggestion to
compare it with the conservation of energy law.

You have two phasor currents flowing into a junction. One current is
one amp at zero degrees. The other is one amp at 180 degrees. What is
the total current flowing out of the junction? Hint: There is no such
thing as a conservation of current principle. If the quantity can be
completely destroyed to zero at any time, it cannot be conserved.

You seem to have forgotten what you almost certainly once
knew.

And you seem to have invented an impossible metaphysics. So do you
really know how many angels can dance on the head of a pin?
--
73, Cecil, w5dxp.com