A small riddle, just for fun
 

On Feb 13, 10:18*am, "Szczepan Bialek" wrote:
Uzytkownik "tom" napisal w wiadomoscinews:4d572454$0$87583$8046368a@newsreade r.iphouse.net...

On 2/12/2011 12:06 PM, Szczepan Bialek wrote:

Of course. But the longitudine waves transport mass (electrons) and are
not
symmetric. Jumping off is stronger than sucking *back.

Tesla is not applicable here, an antenna is not a cathode and does not act
like one. *Neither is it made of a material that is cathodic at room
temperature.

Field emission works at each temperature and each material. It is voltage
and temperature dependent. Also: "How would the ideal field emitter look
like? It should be very long and very thin, made of conductive material with
high mechanical strength, be robust, and cheap and easy to process."



So where else does it say the current is asymmetrical?

The emission current from AC lines is. But there the electrons flow to
ground. In the lines no open circuit.
In open circuit *the voltage is doubled (at least) at the end. If some
electrons jump off than the suction voltage is lower. If an antenna radiate
the VSWR is low = some electrons do not come back.

In the giant Warsaw dipole was: "In the lower half of the mast, there was a
vertical steel tube, attached to the mast's outer structure with large
insulators. This tube was grounded at the bottom, and connected electrically
to the mast structure at half the total height. This technique works by
applying a DC ground at a point of minimum radiofrequency voltage,
conducting static charge to ground without diminishing the radio energy.
Static electrical charge can build up to high values, even at times of no
thunderstorm activity, when such tall structures are insulated from ground.

Guess why the static charge is build up?

S*

if there is any breeze: http://en.wikipedia.org/wiki/Triboelectric_effect

or just the clear air electric field: "In fine weather, the potential
increases with altitude at the rate, according to some writers, of
about 30 volts per foot (100 V/m).[3]"
from http://en.wikipedia.org/wiki/Atmospheric_electricity

A small riddle, just for fun
 

On Feb 13, 10:38*am, "Szczepan Bialek" wrote:
Uzytkownik "tom" napisal w wiadomoscinews:4d57257a$0$6699$8046368a@newsreader .iphouse.net...



On 2/12/2011 12:23 PM, Szczepan Bialek wrote:
* *napisal w wiadomosci
....
On Feb 12, 8:55 am, "Szczepan *wrote:

The field emission take place where the voltage exists. But at the end
the
voltage is doubled (standing wave). So the strong radiation is only from
the
nodes.
S*

so if there is only a single high voltage point at the top how is it
vertically polarized and how does it radiate at all without the other
half of the dipole?

You probably have seen the CB radio. On the end of the whip is alternate
high voltage. It radiate the longitudinal electric waves. The other half
of
a dipole is chassis (car). Is there any polarisation?
S*

There sure is. *It is typical to see 20dB or so loss when you rotate a
dipole receiving from a vertical ground plane CB antenna from vertical to
horizontal.

The transmmiting "cold catode" is thin and long. It radiate the alternate
electric field perpendicular to its length. Receiving antenna also have the
best direction to collect electrons.



From a car it may not be truly vertical because of the body, but it is
still easy to detect.

Polarisation is linear, circular, eleptical. Could you produce it by
rotation of monopole?
S*

you can create any direction of linear polarization by rotating a
monopole.

A small riddle, just for fun
 

Uzytkownik "K1TTT" napisal w wiadomosci
...
On Feb 13, 10:18 am, "Szczepan Bialek" wrote:

In the giant Warsaw dipole was: "In the lower half of the mast, there was
a
vertical steel tube, attached to the mast's outer structure with large
insulators. This tube was grounded at the bottom, and connected
electrically
to the mast structure at half the total height. This technique works by
applying a DC ground at a point of minimum radiofrequency voltage,
conducting static charge to ground without diminishing the radio energy.
Static electrical charge can build up to high values, even at times of no
thunderstorm activity, when such tall structures are insulated from
ground.

Guess why the static charge is build up?

S*

if there is any breeze: http://en.wikipedia.org/wiki/Triboelectric_effect

or just the clear air electric field: "In fine weather, the potential
increases with altitude at the rate, according to some writers, of
about 30 volts per foot (100 V/m).[3]"
from http://en.wikipedia.org/wiki/Atmospheric_electricity

You invented a new power plant. But what voltage will be there in fine
weather? In conductor must be the same. Will it be like at bottom or as at
the top or in the middle?

The sentence "when such tall structures are insulated from ground" is wrong.
Should be: "when such dipole works".
S*

A small riddle, just for fun
 

On Feb 14, 10:26*am, "Szczepan Bialek" wrote:
Uzytkownik "K1TTT" napisal w ...
On Feb 13, 10:18 am, "Szczepan Bialek" wrote:





In the giant Warsaw dipole was: "In the lower half of the mast, there was
a
vertical steel tube, attached to the mast's outer structure with large
insulators. This tube was grounded at the bottom, and connected
electrically
to the mast structure at half the total height. This technique works by
applying a DC ground at a point of minimum radiofrequency voltage,
conducting static charge to ground without diminishing the radio energy..
Static electrical charge can build up to high values, even at times of no
thunderstorm activity, when such tall structures are insulated from
ground.

Guess why the static charge is build up?

S*
if there is any breeze:http://en.wikipedia.org/wiki/Triboelectric_effect
or just the clear air electric field: "In fine weather, the potential

increases with altitude at the rate, according to some writers, of
about 30 volts per foot (100 V/m).[3]"
fromhttp://en.wikipedia.org/wiki/Atmospheric_electricity

You invented a new power plant. But what voltage will be there in fine
weather? In conductor must be the same. *Will it be like at bottom or as at
the top or in the middle?

The sentence "when such tall structures are insulated from ground" is wrong.
Should be: "when such *dipole works".
S*



try it and see... tie a wire to a kite and fly it up nice and high and
measure the dc voltage to ground. you can also draw current from it.
many years ago i built a motor that was powered by only a wire
sticking up about 20' in the clear air... very interesting free
power! but very dangerous near thunderstorm!

A small riddle, just for fun
 

"K1TTT" napisal w wiadomosci
...
On Feb 14, 10:26 am, "Szczepan Bialek" wrote:
In the giant Warsaw dipole was: "In the lower half of the mast, there
was
a
vertical steel tube, attached to the mast's outer structure with large
insulators. This tube was grounded at the bottom, and connected
electrically
to the mast structure at half the total height. This technique works by
applying a DC ground at a point of minimum radiofrequency voltage,
conducting static charge to ground without diminishing the radio energy.
Static electrical charge can build up to high values, even at times of
no
thunderstorm activity, when such tall structures are insulated from
ground.


The sentence "when such tall structures are insulated from ground" is
wrong.
Should be: "when such dipole works".
S*



try it and see... tie a wire to a kite and fly it up nice and high and
measure the dc voltage to ground. you can also draw current from it.
many years ago i built a motor that was powered by only a wire
sticking up about 20' in the clear air... very interesting free
power! but very dangerous near thunderstorm!

In clear air the electrons migrate up. Under a cloud down.
The direction of DC is weather dependent.

Of course sometimes no DC at all.

It is interesting that a wire sticking up about 20' produces DC but your
antennas no.

Transmitting antenna is like electron gun.
S*

A small riddle, just for fun
 

Szczepan Bialek wrote:

Transmitting antenna is like electron gun.
S*



SB,

If electrons leaving the antenna are what makes it work, then please
explain how an antenna coated by an insulator like plastic or fiberglass
works.


Thanks,

A small riddle, just for fun
 

"joe" napisal w wiadomosci
...
Szczepan Bialek wrote:

Transmitting antenna is like electron gun.

If electrons leaving the antenna are what makes it work, then please
explain how an antenna coated by an insulator like plastic or fiberglass
works.

Permittivity is material and frequency dependent. The space and an insulator
like ice and plastic or fiberglass have small value.
Water has 81.

An antenna covered with ice works. But if the ice is melting and the all
pores are filled with water the antenna do not work.

The key issue is the net DC current. Of course as a result of ansymmetry.
More electrons flow up then come back.

This net result is easy to measure.
S*
,

A small riddle, just for fun
 

On Feb 18, 6:20*pm, "Szczepan Bialek" wrote:
*"joe" napisal w ...

Szczepan Bialek wrote:

Transmitting antenna is like electron gun.

If electrons leaving the antenna are what makes it work, then please
explain how an antenna coated by an insulator like plastic or fiberglass
works.

Permittivity is material and frequency dependent. The space and an insulator
like ice and plastic or fiberglass have small value.
Water has 81.

An antenna covered with ice works. But if the ice is melting and the all
pores are filled with water the antenna do not work.

The key issue is the net DC current. Of course as a result of ansymmetry.
More electrons flow up then come back.

This net result is easy to measure.
S*
,

antennas submerged in salt water work, how does that happen??

A small riddle, just for fun
 

"K1TTT" napisal w wiadomosci
...
On Feb 18, 6:20 pm, "Szczepan Bialek" wrote:
"
An antenna covered with ice works. But if the ice is melting and the all
pores are filled with water the antenna do not work.

antennas submerged in salt water work, how does that happen??

It was here about antennas made of salt water.
Is it a normal practice to make an underwater antennas?
S*

A small riddle, just for fun
 

On Feb 19, 9:33*am, "Szczepan Bialek" wrote:
"K1TTT" napisal w ...
On Feb 18, 6:20 pm, "Szczepan Bialek" wrote:

"
An antenna covered with ice works. But if the ice is melting and the all
pores are filled with water the antenna do not work.
antennas submerged in salt water work, how does that happen??

It was here about antennas made of salt water.
Is it a normal practice to make an underwater antennas?
S*

yes, there are underwater antennas in use 24/7 by military
submarines... so how do the electrons get through the salt water?

A small riddle, just for fun
 

Uzytkownik "K1TTT" napisal w wiadomosci
...
On Feb 19, 9:33 am, "Szczepan Bialek" wrote:
"K1TTT" napisal w
...
On Feb 18, 6:20 pm, "Szczepan Bialek" wrote:

"
An antenna covered with ice works. But if the ice is melting and the
all
pores are filled with water the antenna do not work.
antennas submerged in salt water work, how does that happen??

It was here about antennas made of salt water.
Is it a normal practice to make an underwater antennas?

yes, there are underwater antennas in use 24/7 by military
submarines... so how do the electrons get through the salt water?

http://www.qsl.net/vk5br/UwaterComms.htm
S*

A small riddle, just for fun
 

Szczepan Bialek wrote:
Uzytkownik "K1TTT" napisal w wiadomosci


yes, there are underwater antennas in use 24/7 by military
submarines... so how do the electrons get through the salt water?

http://www.qsl.net/vk5br/UwaterComms.htm
S*



The word electron does not appear on that page.

A small riddle, just for fun
 

On 2/19/2011 1:15 PM, joe wrote:
Szczepan Bialek wrote:
Uzytkownik "K1TTT" napisal w wiadomosci


yes, there are underwater antennas in use 24/7 by military
submarines... so how do the electrons get through the salt water?


They don't. Radio waves travel through water the same way they travel
through outer space. Albeit better through water at ultra-low frequencies.

http://www.qsl.net/vk5br/UwaterComms.htm
S*


The word electron does not appear on that page.

A small riddle, just for fun
 

On 2/19/2011 11:41 AM, Szczepan Bialek wrote:
Uzytkownik napisal w wiadomosci
...
On Feb 19, 9:33 am, "Szczepan wrote:
snip excess

yes, there are underwater antennas in use 24/7 by military
submarines... so how do the electrons get through the salt water?

http://www.qsl.net/vk5br/UwaterComms.htm
S*

I don't see where you explained anything about the electrons. The
article doesn't, either.

I'll repeat the question in case you forgot it again.

"so how do the electrons get through the salt water?"

And of course then we have the problem of RF communications with people
who are in caves.

How do the electrons get through the dirt? Which seems to be even less
likely than salt water.

tom
K0TAR

A small riddle, just for fun
 

On Sat, 19 Feb 2011 18:36:25 -0600, tom wrote:

How do the electrons get through the dirt?

Having not read most of the nonsense that attends this kind of side
thread, I will dip my oar into this anyway and ask:

How do the electrons get through the air? (especially when, in their
ferocious struggle, they usually light up the night with corona in the
best of worst performance that rarely achieves propagation beyond an
inch).

73's
Richard Clark, KB7QHC

A small riddle, just for fun
 

Uzytkownik "joe" napisal w wiadomosci
...
Szczepan Bialek wrote:
Uzytkownik "K1TTT" napisal w wiadomosci


yes, there are underwater antennas in use 24/7 by military
submarines... so how do the electrons get through the salt water?

http://www.qsl.net/vk5br/UwaterComms.htm

The word electron does not appear on that page.

Asymmetric molecule oscillations = sound waves.
Asymmetric electron oscillations = electric waves.

On that page are radio waves in air and water. Free electrons are
everywhere. But the freedom is material dependent.
S*

A small riddle, just for fun
 

"tom" napisal w wiadomosci
. net...
On 2/19/2011 11:41 AM, Szczepan Bialek wrote:

http://www.qsl.net/vk5br/UwaterComms.htm

I don't see where you explained anything about the electrons. The article
doesn't, either.

I'll repeat the question in case you forgot it again.

"so how do the electrons get through the salt water?"

And of course then we have the problem of RF communications with people
who are in caves.

How do the electrons get through the dirt? Which seems to be even less
likely than salt water.

In Nature are the continuous flows and the oscillatory flows.
The oscillatory flow is a second name of waves. If oscillations are
asymetric than net flow take place.

Electrons are everywhere. Their freedom is material dependent.
S*

A small riddle, just for fun
 

On Feb 20, 8:59*am, "Szczepan Bialek" wrote:
"tom" napisal w wiadomoscinews:4d606204$0$87583$8046368a@newsreade r.iphouse.net...



On 2/19/2011 11:41 AM, Szczepan Bialek wrote:

http://www.qsl.net/vk5br/UwaterComms.htm

I don't see where you explained anything about the electrons. *The article
doesn't, either.

I'll repeat the question in case you forgot it again.

"so how do the electrons get through the salt water?"

And of course then we have the problem of RF communications with people
who are in caves.

How do the electrons get through the dirt? *Which seems to be even less
likely than salt water.

In Nature are the continuous flows and the oscillatory flows.
The oscillatory flow is a second name of waves. If oscillations are
asymetric than net flow take place.

Electrons are everywhere. Their freedom is material dependent.
S*

but then why can't i measure dc current from my antenna? and why do
my oscillations look so symmetric?

A small riddle, just for fun
 

"K1TTT" napisal w wiadomosci
...
On Feb 20, 8:59 am, "Szczepan Bialek" wrote:

In Nature are the continuous flows and the oscillatory flows.
The oscillatory flow is a second name of waves. If oscillations are
asymetric than net flow take place.

Electrons are everywhere. Their freedom is material dependent.

but then why can't i measure dc current from my antenna? and why do
my oscillations look so symmetric?

To measure it you must have an equipment and good will.
The last is more important.

Look at the original Hertz apparatus:
http://people.seas.harvard.edu/~jone...ertz/S_p11.gif

To have one portion of radiation it is enough to charge one half of the
dipole. Charging is made with DC.
After some time you can repeat it.

The radiation is in form of the damped wave:
http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

In damped waves each amplitude is smaller than the previous. So in one cycle
no symmetry.

It is obvious. But you can try to detect it.
S*

A small riddle, just for fun
 

On Feb 21, 9:41*am, "Szczepan Bialek" wrote:
*"K1TTT" napisal w ...
On Feb 20, 8:59 am, "Szczepan Bialek" wrote:

In Nature are the continuous flows and the oscillatory flows.
The oscillatory flow is a second name of waves. If oscillations are
asymetric than net flow take place.

Electrons are everywhere. Their freedom is material dependent.

but then why can't i measure dc current from my antenna? *and why do

my oscillations look so symmetric?

To measure it you must have an equipment and good will.
The last is more important.

Look at the original Hertz apparatus:http://people.seas.harvard.edu/~jone...res/lecture6/h...

To have one portion of radiation it is enough to charge one half of the
dipole. Charging is made with DC.
After some time you can repeat it.

The radiation is in form of *the damped wave:http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

In damped waves each amplitude is smaller than the previous. So in one cycle
no symmetry.

It is obvious. But you can try to detect it.
S*

can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

A small riddle, just for fun
 

"K1TTT" napisal w wiadomosci
...
On Feb 21, 9:41 am, "Szczepan Bialek" wrote:

The radiation is in form of the damped wave:
http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

? In damped waves each amplitude is smaller than the previous. So in one
cycle
no symmetry.

It is obvious. But you can try to detect it.
S*

can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.

If electrons jump off from antennas it will be easy to measure in klystron:
http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*

A small riddle, just for fun
 

On Feb 21, 6:07*pm, "Szczepan Bialek" wrote:
*"K1TTT" napisal w ...
On Feb 21, 9:41 am, "Szczepan Bialek" wrote:

The radiation is in form of the damped wave:
http://en.wikipedia.org/wiki/File:Ondes_amorties.jpg

? In damped waves each amplitude is smaller than the previous. So in one
cycle

no symmetry.

It is obvious. But you can try to detect it.
S*
can't detect it here, my waves look like perfectly symmetric sine

waves and i can not measure dc on antenna. *how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.

feedpoint is 50 ohms, and 99% efficient... how much now?



If electrons jump off from antennas it will be easy to measure in klystron:http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*

i have worked with klystrons... the current in equals the current out,
all electrons are accounted for.

A small riddle, just for fun
 

"K1TTT" napisal w wiadomosci
...
On Feb 21, 6:07 pm, "Szczepan Bialek" wrote:

can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.

feedpoint is 50 ohms, and 99% efficient... how much now?

And peak voltage at the end?


If electrons jump off from antennas it will be easy to measure in
klystron:http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*

i have worked with klystrons... the current in equals the current out,
all electrons are accounted for.

So in your area the field emission do not work.
S*

A small riddle, just for fun
 

On Feb 22, 8:44*am, "Szczepan Bialek" wrote:
*"K1TTT" napisal w ...
On Feb 21, 6:07 pm, "Szczepan Bialek" wrote:



can't detect it here, my waves look like perfectly symmetric sine
waves and i can not measure dc on antenna. how much dc should i have
with 1000w at 14mhz?

I do not know. It is peak voltage and efficiency dependent.
feedpoint is 50 ohms, and 99% efficient... how much now?

And peak voltage at the end?



If electrons jump off from antennas it will be easy to measure in
klystron:http://en.wikipedia.org/wiki/File:Klystron.enp.gif

The electron beam is collected after work. If starting beam is equal to
collected then no jump off.
S*
i have worked with klystrons... the current in equals the current out,

all electrons are accounted for.

So in your area the field emission do not work.
S*

i don't have any electrons jumping off my antennas... but i still talk
around the world. your theory must be wrong.

A small riddle, just for fun
 

Uzytkownik "K1TTT" napisal w wiadomosci
...
On Feb 22, 8:44 am, "Szczepan Bialek" wrote:

And peak voltage at the end?

So in your area the field emission do not work.

i don't have any electrons jumping off my antennas... but i still talk
around the world. your theory must be wrong.

Field emission is voltage dependent. What is the voltage peaks on the end of
your antennas.
Even if they are symmetric the emission is different for negative/positive
voltage. The negative emission is stronger.

Put on CB antenna the cathode ray trap (vacuum tube) and measure the
anticathode to ground current.
S*

A small riddle, just for fun
 

On Feb 22, 5:53*pm, "Szczepan Bialek" wrote:
Uzytkownik "K1TTT" napisal w ...
On Feb 22, 8:44 am, "Szczepan Bialek" wrote:



And peak voltage at the end?

So in your area the field emission do not work.
i don't have any electrons jumping off my antennas... but i still talk

around the world. *your theory must be wrong.

Field emission is voltage dependent. What is the voltage peaks on the end of
your antennas.
Even if they are symmetric the emission is different for negative/positive
voltage. The negative emission is stronger.

Put on CB antenna the cathode ray trap (vacuum tube) and measure the
anticathode to ground current.
S*

how can it be voltage dependent if it is necessary for the rf signal?
do qrp signals that only generate 1v on the tip of the antenna not
generate rf waves and propagate??

A small riddle, just for fun
 

On Feb 22, 5:53*pm, "Szczepan Bialek" wrote:
Uzytkownik "K1TTT" napisal w ...
On Feb 22, 8:44 am, "Szczepan Bialek" wrote:



And peak voltage at the end?

So in your area the field emission do not work.
i don't have any electrons jumping off my antennas... but i still talk

around the world. *your theory must be wrong.

Field emission is voltage dependent. What is the voltage peaks on the end of
your antennas.
Even if they are symmetric the emission is different for negative/positive
voltage. The negative emission is stronger.

Put on CB antenna the cathode ray trap (vacuum tube) and measure the
anticathode to ground current.
S*

oh yeah, riddle me this... infra-red light is another form of
electromagnetic energy which can be picked up from the heat of your
body by an IR camera... since your body is radiating em waves
continuously why aren't you always charged??

A small riddle, just for fun
 

Uzytkownik "K1TTT" napisal w wiadomosci
...
On Feb 22, 5:53 pm, "Szczepan Bialek" wrote:

Put on CB antenna the cathode ray trap (vacuum tube) and measure the
anticathode to ground current.
S*

oh yeah, riddle me this... infra-red light is another form of
electromagnetic energy which can be picked up from the heat of your
body by an IR camera... since your body is radiating em waves
continuously why aren't you always charged??

I am emitting (loss) electrons and I am always positively charged. See:
http://www.siliconfareast.com/tribo_series.htm
It seams that in your area the physics laws do not work.
S*

A small riddle, just for fun
 

On Feb 23, 8:39*am, "Szczepan Bialek" wrote:
Uzytkownik "K1TTT" napisal w ...
On Feb 22, 5:53 pm, "Szczepan Bialek" wrote:



Put on CB antenna the cathode ray trap (vacuum tube) and measure the
anticathode to ground current.
S*
oh yeah, riddle me this... infra-red light is another form of

electromagnetic energy which can be picked up from the heat of your
body by an IR camera... since your body is radiating em waves
continuously why aren't you always charged??

I am emitting (loss) electrons and I am always positively charged. See:http://www.siliconfareast.com/tribo_series.htm
It seams that in *your area the physics laws do not work.
S*

triboelectric charging can result in you being positive or negative...
and is not related to IR radiation you are emitting all the time. lay
still flat on the ground and you will not be triboelectrically
charged, but you will be constantly radiating IR radiation.

A small riddle, just for fun
 

Uzytkownik "K1TTT" napisal w wiadomosci
...
On Feb 23, 8:39 am, "Szczepan Bialek" wrote:

Put on CB antenna the cathode ray trap (vacuum tube) and measure the
anticathode to ground current.

oh yeah, riddle me this... infra-red light is another form of
electromagnetic energy which can be picked up from the heat of your
body by an IR camera... since your body is radiating em waves
continuously why aren't you always charged??

I am emitting (loss) electrons and I am always positively charged.
See:http://www.siliconfareast.com/tribo_series.htm
It seams that in your area the physics laws do not work.

triboelectric charging can result in you being positive or negative...
and is not related to IR radiation you are emitting all the time. lay
still flat on the ground and you will not be triboelectrically
charged, but you will be constantly radiating IR radiation.

Excellent thinking. If I am laying on the ground I constantly pump electrons
from the ground into the air without being charged. Exactly like your
transmitting antennas connected with the ground or chassis. Without
connection to ground they becomes positively charged.

Are you able to measure the static voltage of a human skin?
S*

A small riddle, just for fun
 

On Feb 24, 8:52*am, "Szczepan Bialek" wrote:
Uzytkownik "K1TTT" napisal w ...
On Feb 23, 8:39 am, "Szczepan Bialek" wrote:



Put on CB antenna the cathode ray trap (vacuum tube) and measure the
anticathode to ground current.
oh yeah, riddle me this... infra-red light is another form of
electromagnetic energy which can be picked up from the heat of your
body by an IR camera... since your body is radiating em waves
continuously why aren't you always charged??

I am emitting (loss) electrons and I am always positively charged.
See:http://www.siliconfareast.com/tribo_series.htm
It seams that in your area the physics laws do not work.
triboelectric charging can result in you being positive or negative...

and is not related to IR radiation you are emitting all the time. *lay
still flat on the ground and you will not be triboelectrically
charged, but you will be constantly radiating IR radiation.

Excellent thinking. If I am laying on the ground I constantly pump electrons
from the ground into the air without being charged. Exactly like your
transmitting antennas connected with the ground or chassis. Without
connection to ground they becomes positively charged.

Are you able to measure the static voltage of a human skin?
S*

no, no static voltage on human skin... and no current from ground to
measure either.

A small riddle, just for fun
 

"K1TTT" napisal w wiadomosci
...
On Feb 24, 8:52 am, "Szczepan Bialek" wrote:

Are you able to measure the static voltage of a human skin?
S*

no, no static voltage on human skin... and no current from ground to
measure either.

And no electrons at all. Nothing jump off and come back. Only
incompressible, massles electric and magnetic fluids.

But the electrons exist. All radiations are the electrons vibrations. All
waves are asymmetric. So must be the electrons transport, Hot body loss
electrons. The all is to measure.
S*

A small riddle, just for fun
 

On Feb 25, 8:34*am, "Szczepan Bialek" wrote:
*"K1TTT" napisal w ...
On Feb 24, 8:52 am, "Szczepan Bialek" wrote:



Are you able to measure the static voltage of a human skin?
S*
no, no static voltage on human skin... and no current from ground to

measure either.

And no electrons at all. Nothing jump off and come back. Only
incompressible, massles electric and magnetic fluids.

But the electrons exist. All radiations are the electrons vibrations. All
waves are asymmetric. So must be the electrons transport, Hot body loss
electrons. The all is to measure.
S*

well, you go ahead and measure it, and take a picture of the
asymmetric waves while you are at it... once you publish in a peer
reviewed journal i'll start talking to you again, this is getting
rather boring since you refuse to learn.