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Walter, W2DU wrote:
"I`ll give you two ways to determine Vfwd." Walter makes it too easy by using the power relationships, but that`s the way it is. The forward (incident) wave is opposed by Ro in a practical line. The reward (reflected) wave is also opposed by Ro (the surge impedance) of the line. Power from the transmitter is nearly the same as that delivered to the load as loss is small and no significant room exists in the line to store RF. Power to the load is the difference between forward power and reflected power. The voltage at any point on a mismatched line is the sum of the forward and reflected waves at that point but is merely a manifestatoion of SWR and has little practical value. At a current or a voltage loop (maximum), the forward and reflected amps or volts are in-phase. So, if a line is opened at a loop point, the impedance looking toward the load is a pure resistance regardless of the nature of the load (see page 37 of "Transmission Lines, Antennas, and Wave Guides" by King, Mimno, and Wing). Best regards, Richard Harrison, KB5WZI |
#2
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Richard Harrison wrote:
The voltage at any point on a mismatched line is the sum of the forward and reflected waves at that point but is merely a manifestatoion of SWR and has little practical value. All true and completely irrelevant to Dr. Best's article since he was *never* talking about the net voltage. He is talking about the forward voltage. Any notion that Dr. Best was talking about net voltage is a mistaken notion. (I can't believe I'm defending Dr. Best but he said what he said.) -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#3
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